Directions: The following table shows the percentage of marks obtained by six students in five different subjects. Answer the following questions based on this table.

Students
Physics
(Out of 75)
Chemistry
(Out of 75)
Maths
(Out of 200)
Hindi
(Out of 50)
English
(Out of 150)
A 84% 42% 67% 44% 74%
B 68% 64% 49% 74% 52%
C 72% 54% 58% 68% 64%
D 48% 82% 63% 48% 70%
E 70% 78% 71% 56% 78%
F 56% 66% 55% 76% 66%
1
What is the average marks scored by all the students in Physics?
» Explain it
A
Average marks of all students in Physics

=   1  ×  75 [84% + 68% + 72% + 48% + 70% + 56%]
6

⇒     1  ×   75% [84 + 68 + 72 + 48 + 70 + 56]
6

⇒    1  ×   75 [398] = 49.75
6 100

Hence, option A is correct.

2
What is the total marks scored by Student F in all the subjects together?
» Explain it
E
Total marks scored by student F in all the subject together =

= (75 × 56%) + ( 75 × 66%) + ( 200 × 55%) + (50 × 76%) + (150 × 66%)


(75 × 56)  +  (75 × 66)  +  (200 × 55)  +  (50 × 76)  +  (150 × 66)
100 100 100 100 100
 

= 42 + 49.5 + 110 + 38 + 99 = 338.5


Hence, option E is correct.
3
What is the overall percentage of marks scored by Student B? (Answer approximate value.)
» Explain it
B
= (75 × 68%) + ( 75 × 64%) + ( 200 × 49%) + (50 × 74%) + (150 × 52%)  


⇒   (75 × 68)  +  (75 × 64)  +  (200 × 49)  +  (50 × 74)  +  (150 × 52)
100 100 100 100 100
  ⇒   51 + 48 + 98 + 37 + 78 = 312  
 
Reqd% =   312  × 100 = 56.72 ≈ 57%
550


Hence, option B is correct.
4
The marks scored by Student C in physics is approximately what per cent of the marks scored by him in English?
» Explain it
A
Total marks scored by Student C in physics

72  × 75 = 54
100


Total marks scored by Student C in English

64  × 150 = 96
100

Reqd% =  54  × 100 = 56.25 ≈ 56%
96

Hence, option A is correct.
5
What is the difference between the total marks obtained by Student D in Chemistry and English and that obtained by Student F in the same subject?
» Explain it
C
Total marks of Student D in Chemistry and English 
 
= (82% of 75) + (70% of 150) = 61.5 + 105 = 166.5
 
Total marks of Student F in Chemistry and English 
 
= (66% of 75) + (66% of 150) = 49.5 + 99 = 148.5
 
∴    Reqd difference = 166.5 – 148.5 = 18
____________________________________________

Smart approach:

Reqd difference= (82 – 66)% of 75 + (70 – 66)% of 150 

= 16% of 75 + 4% of 150

= 12 + 6 = 18

Hence, option C is correct.
 

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Smartkeeda.com helps exam aspirants understand Tabular Data Interpretation (DI) questions on solving them with the help of relevant examples. Tabular Data Interpretation is the most important chapter of arithmetic section of Quantitative Aptitude. Here on this page, you will get to know about Table Chart Data Interpretation questions with solutions for Bank Exams and SSC Exams, one of the important chapters of Quantitative Aptitude with all the short tricks of Data Interpretation question and answer, tricks to solve line chart, bar chart, mixed chart, information chart, radar chart, web chart, table chart, set theory and pie chart. Less time taking approaches to solve Data Interpretation sets, tricks to solve data analysis questions and answers problems, Data Interpretation formulas, Important quantitative aptitude DI tricks video, Table Charts Data Interpretation shortcuts, wherever applied.

In Build your concept part you get all types of Data Interpretation formulas and tips on how to solve Data Interpretation questions quickly without using a pen or paper. The section consists of Data Interpretation tricks and tips or fundamentals related to this very important chapter of Quantitative Aptitude. Plus, you get all the Data Interpretation shortcuts with complete explanations and video solutions for specific exams like SSC CGL Tier 1, SSC CGL Tier 2, CDSE, CLAT, MAT, SSC LDC, SSC MTS, SSC DEO, SSC Stenographer, LIC AAO, NICL, Railways, SBI Clerk Pre, IBPS Clerk Pre, SBI PO Pre, IBPS PO Pre, IBPS RRB Office Assistant Pre, IBPS RRB Officer Scale 1 Pre.

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Link to Testzone, the test series platform: https://testzone.smartkeeda.com/