1.
If 4x + 5y = 83 and
3x
=
21
then y – x = ?
2y
22

Answer: Option
B

Explanation:

4x+ 5y = 83 ...(i)

and
3x
=
21
⇒ 66x = 42y
2y
22

⇒ 11x – 7y = 0 ...(ii)

Solving equations (i) and (ii) we get x = 7 and y = 11

Now, y – x = 11 – 7 = 4

2.
The price of 2 trousers and 4 shirts is Rs. 1,600. With the same amount one can buy 1 trouser and 6 shirts. If one wants to buy 12 shirts, he has to pay

A.
Rs. 2400
B.
Rs. 4800
C.
Rs. 1200
D.
Rs. 3700

Answer: Option
A

Explanation:

Let the price of a trouser and a shirt be Rs. x and Rs. y respectively.

Then, 2x + 4y = 1600 .... (i) and x + 6y = 1600 ...... (ii)

Solving (i) and (ii), we get : x = 400, y = 200

∴ Cost of 12 shirts = Rs. (12 × 200) = Rs. 2400.

3.
The straight line 4x + 3y = 12 passes through:
A.
1st, 2nd and 3rd quadrant
B.
1st, 2nd and 4th quadrant
C.
2nd, 3rd and 4th quadrant
D.
1st, 3rd and 4th quadrant

Answer: Option
B

Explanation:

Putting y = 0 in 4x + 3y = 12

we get x = 3

Putting x = 0 in 4x + 3y = 12, we get y = 4

4.
The area of the triangle formed by the graph of 3x + 4y = 12, x-axis and y-axis (in sq. units) is

Answer: Option
C

Explanation:

x-axis ⇒ y = 0, putting in equation 3x + 4y = 12

3x = 12 ⇒ x = 4

⇒ Co-ordinates of point of intersection on x-axis = (4, 0)

Putting on y-axis = (0, 3)

∴ (0, 3)

OA = 4

OB = 3

=
1
× OA × OB =
1
× 4 × 3 = 6 sq. units
2
2

5.
An equation of the form ax + by + c = 0 where a ≠ 0, b ≠ 0, c = 0 represents a straight line which passes through

A.
(0, 0)
B.
(3, 2)
C.
(2, 4)
D.
None of these

Answer: Option
A

Explanation:

ax + by + c = 0

when c = 0,

ax + by = 0

When x = 0, y = 0 i.e. Thus, this line passes through the origin (0,0).