Important for :

1

D

Cost of each toffee = | 1 |

5 |

As toffees are marked up by 25% then

Marked price per toffee = 125% of | 1 |

5 |

Given that discount is 12%

So, the required selling price per toffee = 88% of 125% of | 1 |

5 |

= | 88 × 125 × 1 | = 0.22 |

100 × 100 × 5 |

As, in Rs. 0.22 anyone can buy 1 toffee

So, in Rs. 1 anyone can buy | 1 | toffees |

0.22 |

Thus, in Rs. 22 anyone can buy | 1 | × 22 = 100 toffees |

0.22 |

Cost of each toffee be | 1 |

4 |

As toffees are marked up by 26% then

Marked price per toffee = 126% of | 1 |

4 |

Given that discount is 10%

So, the required selling price per toffee = 90% of 126% of | 1 |

4 |

= | 90 × 126 × 1 | = 0.2835 |

100 × 100 × 4 |

As, in Rs. 0.2835 anyone can buy 1 toffee

So, in Rs. 1 anyone can buy | 1 | toffees |

0.2835 |

Thus, in Rs. 22 anyone can buy | 1 | × 28.35 = 100 toffees |

0.2835 |

Hence, option (D) is correct.

2

B

Suppose initially Rajendra had Rs. y

Then, amount received by Ajnish = Rs. | y |

3 |

Amount remaining with Rajendra = Rs. | ( | y – | y | ) | = Rs. | 2y |

3 | 3 |

Amount received by Narendra = Rs. | ( | 1 | × | y | ) | = Rs. | y |

2 | 3 | 6 |

Since, | ( | 2y | – | y | ) | = 2500 |

3 | 6 |

⇒ (4y – y) = 2500 × 6

⇒ 3y = 2500 × 6

⇒ y = 5000.

Hence, amount received by Ajnish = Rs. | y | = Rs. 1667 |

3 |

Suppose initially Rajendra had Rs. y

Then, amount received by Ajnish = Rs. | y |

2 |

Amount remaining with Rajendra = Rs. | ( | y – | y | ) | = Rs. | y |

2 | 2 |

Amount received by Narendra = Rs. | ( | 1 | × | y | ) | = Rs. | y |

4 | 2 | 8 |

Since, | ( | y | – | y | ) | = 1875 |

2 | 8 |

⇒ (4y – y) = 1875 × 8

⇒ 3y = 1875 × 8

⇒ y = 5000.

Hence, amount received by Ajnish = Rs. | y | = Rs. 2500 |

2 |

Therefore, option (B) is correct.

3

D

**Quantity I:**

We know that, Ostriches has 1 head and 2 legs.

Giant marsupial has 1 head and 4 legs

Let number of Ostriches and Giant marsupial be x and y respectively.

According to question,

(2x + 4y) + 14 = 4 × (x + y)

Or, 2x + 4y – 4x – 4y = – 14

Or, –2x = –14

Or, x = 7

So, number of Ostriches = 7

Number of legs = (2x + 4y) = (2 × 7 + 4y) = 14 + 4y

**Quantity II:**

We know that, Ostriches has 1 head and 2 legs.

Giant marsupial has 1 head and 4 legs

Let number of Ostriches and Giant marsupial be x and y respectively.

According to question,

(2x + 4y) + 15 = 5 × (x + y)

Or, 2x + 4y – 5x – 5y = –15

Or, –3x – y = –15

Or, 3x + y = 15

There is 2 unknown and 1 equation so, exactly we can say anything about x and y. Thus, we cannot calculate number of legs exactly.

Hence, we cannot find any relation between quantity I and quantity II.

Therefore, option (D) is correct.

4

B

Let x, y and z be the rates of doing work of Worker A, Worker B and Worker C respectively.

According to question,

x = 1.15y and y = 1.12z

So, x = 1.15y = (1.15 × 1.12)z = 1.288z

Therefore, (x : y : z) = (1.288 : 1.12 : 1)

i.e, the rates of doing work are in the ratio (1.288 : 1.12 : 1)

Hence, earning will be distributed in the ratio (1.288 : 1.12 : 1)

Total earnings, as per the data = Rs. 10000

Hence the share of Worker A = Rs. | 1.288 | × 10000 = Rs. 3779 |

3.408 |

And share of Worker C = Rs. | 1 | × 10000 = Rs. 2934 |

3.408 |

Hence the difference between share of the share of Worker C and Worker A = Rs. (3779 – 2934) = Rs. 845

Let x, y and z be the rates of doing work of Worker A, Worker B and Worker C respectively.

According to question,

x = 1.20y and y = 1.10z

So, x = 1.20y = (1.20 × 1.10) z = 1.32z

Therefore, (x : y : z) = (1.32 : 1.10 : 1)

i.e, the rates of doing work are in the ratio (1.32 : 1.10 : 1)

Hence, earning will be distributed in the ratio (1.32 : 1.10 : 1)

Total earnings, as per the data = Rs. 9500

Hence the share of Worker A = Rs. | 1.32 | × 9500 = Rs. 3667 |

3.42 |

And share of Worker C = Rs. | 1 | × 9500 = Rs. 2778 |

3.42 |

Hence the difference between share of the share of Worker C and Worker A = Rs. (3667 – 2778) = Rs. 889

Therefore, option (B) is correct.

5

B

Let the amount lent at 11.225% per annum be x

The amount lent at 4.055% per annum be (12700 – x)

According to the question,

(12700 – x) × 4.055 | + | x × 11.225 | = 1150 |

100 | 100 |

⇒ (12700 × 4.055) – 4.055 × x + 11.225 × x = 1150 × 100

⇒ 51498.5 + 7.17 × x = 115000

⇒ 7.17 × x = 63501.5

⇒ x = 8856.6

Hence, the amount lent at 11.225% per annum be Rs. 8856.6

The amount lent at 4.252% per annum be (12000 – x)

According to the question,

(12000 – x) × 4.252 | + | x × 10.325 | = 1200 |

100 | 100 |

⇒ (12000 × 4.252) – 4.252 × x + 10.325 × x = 1200 × 100

⇒ 51024 + 6.073 × x = 120000

⇒ 6.073 × x = 68976

⇒ x = 11357.8

Hence, the amount lent at 10.325% per annum be Rs. 11357.8

Therefore, option (B) is correct.