= | xy |
x + y |
= | x × 2x | = 16 |
3x |
⇒ T_{2} = | 15 × 20 × 8 | = 10 hours |
20 × 12 |
xy | days. | |
y – x |
10 × 12 | = | 120 | = 60 days | |
12 – 10 | 2 |
= | 7 | + | 7 | = | 7 |
20 | 30 | 12 |
= 1 – | 7 | = | 5 |
12 | 12 |
Now, | 5 | work done by C in 10 days. |
12 |
= 10 × | 12 | = 24 days |
5 |
= 1 – | 1 | = | 7 |
8 | 8 |
= | 1 | + | 1 | = | 1 |
6 | 12 | 4 |
= | 7 | × 4 = | 7 | = 3 | 1 | days |
8 | 2 | 2 |