# Scheduling Based Reasoning Puzzles for IBPS PO 2019 and SBI PO 2020 Exams | Download Reasoning Puzzles PDF at Smartkeeda

Directions: Read the given information carefully and answer the questions given below.

Charu, Diya, Emran, Farah, William, Paris, Bholu and Kashi are the eight candidates who have their job interviews lined up in the months namely – January, April, September and December in 2017. In each month, the interview is scheduled either on 10th or 25th of the month. Interviews of not more than two candidates have been scheduled in the same month.

William’s interview is on 10th of the month which has only 30 days. Only three candidates have to attend their interviews between William and Bholu. Charu and Bholu have to attend their interviews neither on the same day nor in the same month. Charu does not have her interview in April. Only two candidates have their interview dates between Charu’s and Farah’s. Paris’ and Farah’s interview dates are same but in different months. Diya has her interview on one of the days before Paris’ interview is scheduled. Only one person is to sit for interview between Diya’s and Emran’s. Less than four candidates have to sit for interviews between Emran’s and Kashi’s interview dates.
Important for :
1
Which of the following candidates had their interviews in the month of December?
» Explain it
C
From the common explanation it is clear that Kashi and Paris gave their interviews in December.

Hence option C is correct.

Final Schedule

 Month –(No. of days) Day Candidate January (31) 10 Bholu 25 Diya April (30) 10 Farah 25 Emran September (30) 10 William 25 Charu December (31) 10 Paris 25 Kashi

Common Explanation

Reference:

William’s interview is on 10th of the month which has only 30 days.
Only three candidates have to attend their interviews between William and Bholu.
Charu and Bholu have to attend their interviews neither on the same day nor in the same month.
Charu does not have her interview in April.
Only two candidates have their interview dates between Charu’s and Farah’s.

Inference:

With the given hints following two cases can be drawn:

Case 1

 Month (No. of days) Day Candidate Hints January (31) 10 25 Charu April (30) 10 William Charu - X 25 Charu - X September (30) 10 Farah 25 December (31) 10 Bholu 25

Case 2

 Month –(No. of days) Day Candidate Hints January (31) 10 Bholu 25 April (30) 10 Farah Charu – X 25 Charu - X September (30) 10 William 25 Charu December (31) 10 25

Reference:

Paris’ and Farah’s interview dates are same but in different months.
Diya has her interview on one of the days before Paris’ interview is scheduled.
Only one person is to sit for interview between Diya’s and Emran’s.
Less than four candidates have to sit for interviews between Emran’s and Kashi’s interview dates.

Inference:
Case1 fails as it violates the second hint. In case 1, Diya’s  interview is scheduled before Paris’, but Paris’ interview comes at 10th of January and no date is prior to that.

Case 1 (Failed)

 Month (No. of days) Day Candidate January (31) 10 Paris 25 Charu April (30) 10 William 25 September (30) 10 Farah 25 December (31) 10 Bholu 25

Case 2

 Month –(No. of days) Day Candidate January (31) 10 Bholu 25 Diya April (30) 10 Farah 25 Emran September (30) 10 William 25 Charu December (31) 10 Paris 25 Kashi

Thus the final arrangement is obtained by Case 2.
2
How many candidates had given their interview between the interviews of Diya and William?
» Explain it
C
From the common explanation it is clear that only two candidates had been given their interviews between Diya and William.

Hence option C is correct.

Final Schedule

 Month  –(No. of days) Day Candidate January (31) 10 Bholu 25 Diya April (30) 10 Farah 25 Emran September (30) 10 William 25 Charu December (31) 10 Paris 25 Kashi

Common Explanation

Reference:

William’s interview is on 10th of the month which has only 30 days.
Only three candidates have to attend their interviews between William and Bholu.
Charu and Bholu have to attend their interviews neither on the same day nor in the same month.
Charu does not have her interview in April.
Only two candidates have their interview dates between Charu’s and Farah’s.

Inference:

With the given hints following two cases can be drawn:

Case 1

 Month (No. of days) Day Candidate Hints January (31) 10 25 Charu April (30) 10 William Charu - X 25 Charu - X September (30) 10 Farah 25 December (31) 10 Bholu 25

Case 2

 Month  –(No. of days) Day Candidate Hints January (31) 10 Bholu 25 April (30) 10 Farah Charu – X 25 Charu - X September (30) 10 William 25 Charu December (31) 10 25

Reference:

Paris’ and Farah’s interview dates are same but in different months.
Diya has her interview on one of the days before Paris’ interview is scheduled.
Only one person is to sit for interview between Diya’s and Emran’s.
Less than four candidates have to sit for interviews between Emran’s and Kashi’s interview dates.

Inference:
Case1 fails as it violates the second hint. In case 1, Diya’s  interview is scheduled before Paris’, but Paris’ interview comes at 10th of January and no date is prior to that.

Case 1 (Failed)

 Month (No. of days) Day Candidate January (31) 10 Paris 25 Charu April (30) 10 William 25 September (30) 10 Farah 25 December (31) 10 Bholu 25

Case 2

 Month  –(No. of days) Day Candidate January (31) 10 Bholu 25 Diya April (30) 10 Farah 25 Emran September (30) 10 William 25 Charu December (31) 10 Paris 25 Kashi

Thus the final arrangement is obtained by Case 2.
3
If all the candidates are made to give their interviews in alphabetical order starting from 10th January then position of how many candidates will remain unchanged?
» Explain it
E
From the common explanation it is clear that position of only three candidates will remain unchanged.

Hence option E is correct.

Final Schedule

 Month –(No. of days) Day Candidate In Alphabetical order January (31) 10 Bholu Bholu 25 Diya Charu April (30) 10 Farah Diya 25 Emran Emran September (30) 10 William Farah 25 Charu Kashi December (31) 10 Paris Paris 25 Kashi William

Common Explanation

Reference:

William’s interview is on 10th of the month which has only 30 days.
Only three candidates have to attend their interviews between William and Bholu.
Charu and Bholu have to attend their interviews neither on the same day nor in the same month.
Charu does not have her interview in April.
Only two candidates have their interview dates between Charu’s and Farah’s.

Inference:

With the given hints following two cases can be drawn:

Case 1

 Month (No. of days) Day Candidate Hints January (31) 10 25 Charu April (30) 10 William Charu - X 25 Charu - X September (30) 10 Farah 25 December (31) 10 Bholu 25

Case 2

 Month  –(No. of days) Day Candidate Hints January (31) 10 Bholu 25 April (30) 10 Farah Charu – X 25 Charu - X September (30) 10 William 25 Charu December (31) 10 25

Reference:

Paris’ and Farah’s interview dates are same but in different months.
Diya has her interview on one of the days before Paris’ interview is scheduled.
Only one person is to sit for interview between Diya’s and Emran’s.
Less than four candidates have to sit for interviews between Emran’s and Kashi’s interview dates.

Inference:
Case1 fails as it violates the second hint. In case 1, Diya’s  interview is scheduled before Paris’, but Paris’ interview comes at 10th of January and no date is prior to that.

Case 1 (Failed)

 Month (No. of days) Day Candidate January (31) 10 Paris 25 Charu April (30) 10 William 25 September (30) 10 Farah 25 December (31) 10 Bholu 25

Case 2

 Month  –(No. of days) Day Candidate January (31) 10 Bholu 25 Diya April (30) 10 Farah 25 Emran September (30) 10 William 25 Charu December (31) 10 Paris 25 Kashi

Thus the final arrangement is obtained by Case 2.
4
Four of the following five are alike in a certain way and hence form a group. Which of the following does not belong to the group?
» Explain it
E
From the common explanation it is clear that except Bholu all others had given interview on 10th of any month, whereas Bholu had given interview on 25th of the month.

Hence option E is correct.

Final Schedule

 Month –(No. of days) Day Candidate January (31) 10 Bholu 25 Diya April (30) 10 Farah 25 Emran September (30) 10 William 25 Charu December (31) 10 Paris 25 Kashi

Common Explanation

Reference:

William’s interview is on 10th of the month which has only 30 days.
Only three candidates have to attend their interviews between William and Bholu.
Charu and Bholu have to attend their interviews neither on the same day nor in the same month.
Charu does not have her interview in April.
Only two candidates have their interview dates between Charu’s and Farah’s.

Inference:

With the given hints following two cases can be drawn:

Case 1

 Month (No. of days) Day Candidate Hints January (31) 10 25 Charu April (30) 10 William Charu - X 25 Charu - X September (30) 10 Farah 25 December (31) 10 Bholu 25

Case 2

 Month  –(No. of days) Day Candidate Hints January (31) 10 Bholu 25 April (30) 10 Farah Charu – X 25 Charu - X September (30) 10 William 25 Charu December (31) 10 25

Reference:

Paris’ and Farah’s interview dates are same but in different months.
Diya has her interview on one of the days before Paris’ interview is scheduled.
Only one person is to sit for interview between Diya’s and Emran’s.
Less than four candidates have to sit for interviews between Emran’s and Kashi’s interview dates.

Inference:
Case1 fails as it violates the second hint. In case 1, Diya’s  interview is scheduled before Paris’, but Paris’ interview comes at 10th of January and no date is prior to that.

Case 1 (Failed)

 Month (No. of days) Day Candidate January (31) 10 Paris 25 Charu April (30) 10 William 25 September (30) 10 Farah 25 December (31) 10 Bholu 25

Case 2

 Month  –(No. of days) Day Candidate January (31) 10 Bholu 25 Diya April (30) 10 Farah 25 Emran September (30) 10 William 25 Charu December (31) 10 Paris 25 Kashi

Thus the final arrangement is obtained by Case 2.
5
On which of the following dates, Interview of Emran was scheduled?
» Explain it
B
From the common explanation it is clear that Emran's interview was scheduled on 25th April.

Hence option B is correct.

Final Schedule

 Month  –(No. of days) Day Candidate January (31) 10 Bholu 25 Diya April (30) 10 Farah 25 Emran September (30) 10 William 25 Charu December (31) 10 Paris 25 Kashi

Common Explanation

Reference:

William’s interview is on 10th of the month which has only 30 days.
Only three candidates have to attend their interviews between William and Bholu.
Charu and Bholu have to attend their interviews neither on the same day nor in the same month.
Charu does not have her interview in April.
Only two candidates have their interview dates between Charu’s and Farah’s.

Inference:

With the given hints following two cases can be drawn:

Case 1

 Month (No. of days) Day Candidate Hints January (31) 10 25 Charu April (30) 10 William Charu - X 25 Charu - X September (30) 10 Farah 25 December (31) 10 Bholu 25

Case 2

 Month  –(No. of days) Day Candidate Hints January (31) 10 Bholu 25 April (30) 10 Farah Charu – X 25 Charu - X September (30) 10 William 25 Charu December (31) 10 25

Reference:

Paris’ and Farah’s interview dates are same but in different months.
Diya has her interview on one of the days before Paris’ interview is scheduled.
Only one person is to sit for interview between Diya’s and Emran’s.
Less than four candidates have to sit for interviews between Emran’s and Kashi’s interview dates.

Inference:
Case1 fails as it violates the second hint. In case 1, Diya’s  interview is scheduled before Paris’, but Paris’ interview comes at 10th of January and no date is prior to that.

Case 1 (Failed)

 Month (No. of days) Day Candidate January (31) 10 Paris 25 Charu April (30) 10 William 25 September (30) 10 Farah 25 December (31) 10 Bholu 25

Case 2

 Month  –(No. of days) Day Candidate January (31) 10 Bholu 25 Diya April (30) 10 Farah 25 Emran September (30) 10 William 25 Charu December (31) 10 Paris 25 Kashi

Thus the final arrangement is obtained by Case 2.

#### Scheduling Based Reasoning Puzzles for IBPS PO 2019 | Reasoning Puzzle Test Set No 132 at Smartkeeda

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