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Maths Questions Quiz No 2 with PDF for CLAT Exam at Smartkeeda

Directions : Study the following information carefully and answer the questions given beside.
 
Information about number of patients who were tested positive to COVID-19 tests in five different cities of India is as follows.
 
Delhi has 60% more patients than Jaipur, which has 400 more than Chennai. Number of patients in Calcutta was half the number of patients in Chennai. Number of patients in Mumbai was 100 less than Chennai. Total patients were 9100 as on 31 March 2019 in all the five cities together.
 
It was found that out of every 200 patients, 180 recovered within 14 days, 18 took 30 days to recover and 2 died.
Important for :
1
Find average number of patients in Chennai, Calcutta and Mumbai.
» Explain it
C
From common explanation, we have

Chennai = 1600

Calcutta = 800

Mumbai = 1500

Total = 3900

Average = 1300

Hence, option C is correct.

Common explanation : 

Let the number of patients in Delhi, Jaipur, Chennai, Calcutta, Mumbai were D, J, Ch, Cal, M respectively.

Then we have

D = 1.6J = 1.6(400+Ch)

Cal =  1  Ch
2

M = Ch – 100

Therefore, we have

D + J + Ch + Cal + M = 9100

1.6 (400 + Ch) + (400 + Ch) + Ch +  1  Ch + Ch – 100 = 9100
2

940 + 5.1Ch = 9100

Ch = 1600

Thus, patients in various cities are

Delhi = 3200

Jaipur = 2000

Chennai = 1600

Calcutta = 800

Mumbai = 1500
2
Number of patients in Jaipur was what percent more than Calcutta?
» Explain it
B
From common explanation, we have

Jaipur = 2000

Calcutta = 800

Percent difference =  2000 – 800  × 100 = 150%
800

Hence, option B is correct.

Common explanation : 

Let the number of patients in Delhi, Jaipur, Chennai, Calcutta, Mumbai were D, J, Ch, Cal, M respectively.

Then we have

D = 1.6J = 1.6(400+Ch)

Cal =  1  Ch
2

M = Ch – 100

Therefore, we have

D + J + Ch + Cal + M = 9100

1.6 (400 + Ch) + (400 + Ch) + Ch +  1  Ch + Ch – 100 = 9100
2

940 + 5.1Ch = 9100

Ch = 1600

Thus, patients in various cities are

Delhi = 3200

Jaipur = 2000

Chennai = 1600

Calcutta = 800

Mumbai = 1500
3
For each 1000 tests the numbers of people who were found positive were 130. Find out how many tests were conducted that produced 9100 total positive cases?
» Explain it
E
From common explanation, we have

For each 1000 tests we have 130 positive.

Thus for 9100 = 70 ( × 130), we should have 70 (× 1000) = 70,000 tests.

Hence, option E is correct.

Common explanation : 

Let the number of patients in Delhi, Jaipur, Chennai, Calcutta, Mumbai were D, J, Ch, Cal, M respectively.

Then we have

D = 1.6J = 1.6(400+Ch)

Cal =  1  Ch
2

M = Ch – 100

Therefore, we have

D + J + Ch + Cal + M = 9100

1.6 (400 + Ch) + (400 + Ch) + Ch +  1  Ch + Ch – 100 = 9100
2

940 + 5.1Ch = 9100

Ch = 1600

Thus, patients in various cities are

Delhi = 3200

Jaipur = 2000

Chennai = 1600

Calcutta = 800

Mumbai = 1500
4
How many people died in Jaipur, Mumbai and Chennai together?
» Explain it
B
From the common explanation, we have

It is given that out of 200 patients, only 2 dies,

thus  2  × 100 = 1% die.
200

Number of patients in Jaipur, Mumbai and Chennai = 2000 + 1500 + 1600 = 5100

Number of people who will die = 1% of 5100 = 51

Hence, option B is correct.

Common explanation : 

Let the number of patients in Delhi, Jaipur, Chennai, Calcutta, Mumbai were D, J, Ch, Cal, M respectively.

Then we have

D = 1.6J = 1.6(400+Ch)

Cal =  1  Ch
2

M = Ch – 100

Therefore, we have

D + J + Ch + Cal + M = 9100

1.6 (400 + Ch) + (400 + Ch) + Ch +  1  Ch + Ch – 100 = 9100
2

940 + 5.1Ch = 9100

Ch = 1600

Thus, patients in various cities are

Delhi = 3200

Jaipur = 2000

Chennai = 1600

Calcutta = 800

Mumbai = 1500
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Maths plays an important role in the CLAT exam. Neglecting the preparation of this section can prove detrimental to your efforts of achieving a good score and ultimately reaching a good National Law University. The new pattern of CLAT 2020 is based on Data Interpretation and analysis which was introduced by CLAT commission in late 2019.

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