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Approximation Questions for SBI Clerk 2021, NIACL, CET, IBPS Clerk, Download Approximation PDF for Free at Smartkeeda

Directions: What value will come in place of question mark (?) in the following questions: (You are not expected to calculate the exact value)
1
(1611.23 + 2113.03 – 923.98) ÷ 3.98 × 2 = ? + 99
» Explain it
A
(1611.23 + 2113.03 – 923.98) ÷ 3.98 × 2 = ? + 99

≈ {(16 11 + 2113 – 924) / 4} × 2 = ? + 99

{(3724 – 924) / 2} = ? + 99

(2800 / 2) = ? + 99

? = 1400 – 99

? = 1301 ≈ 1300

Hence, option A is correct.

2
√1370 + √1763.9 × 3 ÷ 21 = ?3 + 15

A
8
» Explain it
D
√1370 + √1763.9 × 3 ÷ 21 = ?3 + 15
 
≈ √1369 + √1764 × 3 ÷ 21 = ?3 + 15
 
37 + 42 ÷ 7 = ?3 + 15
 
37 + 6 – 15 = ?3
 
?3 = 28
 
? = 3.04 ≈ 3

Hence, option D is correct.
 
3
(14.98)2 + (12.01)2 – (10.98)2 = ? + 95 ÷ 5
» Explain it
C
(14.98)2 + (12.01)2 – (10.98)2 = ? + 95 ÷ 5
 
≈ 152 + 122 – 112 = ? + 19
 
225 + 144 – 121 – 19 = ?
 
? = 369 – 140
 
? = 229 ≈ 230

Hence, option C is correct.

4
89.9% of 900 – ?2 – 20% of 400.01 = 420 – 10.98

A
18
» Explain it
A
89.9% of 900  – ?2 – 20% of 400.01 = 420 – 10.98
 
≈ 90% of 900 – ?2 – 20% of 400 = 420 – 11
 
810 – ?2 – 80 = 409
 
?2 = 810 – 409 – 80
 
?2 = 321
 
? = 17.91 ≈ 18

Hence, option A is correct.
 

5
(20.1 × 17.97) ÷ (16 × 14.98) + 16.09 + 2 × 1.50 = ?

A
10
» Explain it
E
(20.1 × 17.97) ÷ (16 × 14.98) + 16.09 + 2 × 1.50 = ?

? ≈ (20 × 18) ÷ (16 × 15) + 16 + 2 × 1.5

{(20 × 18) / (16 × 15)} + 16 + 3 = ?

(360 / 240) + 19 = ?

1.5 +19 = ?

? = 20.5 ≈ 20

Hence, option E is correct.