x =  100  (if y = 8) 
8 
h = 14 m, then r =  14  = 7 m 
2 
Then, πr^{2}h =  22  × 7 × 7 × 14 = (22 × 7 × 14)m^{3} 
7 
Capacity =  (  462 × 2 × 

)  m^{3} 
⇒ 3x + 2y > 4p + 6q ⇒ x +  2  y >  4  p + 2q 
3  3 
So the sum of cost of the Laptop and 2/3 of cost of the Modem is more than the sum of the cost of 4/3 of the Mobile (4/3 implies more than 1 here) and twice of that headphone (twice implies 2 headphones). Evidently, the sum cost of the Laptop and that of the Modem must be more than the sum of the cost of the Mobile and that of the Headphone.
So, statement I alone is sufficient.
From Statement II:
2x + 3y < p + 1.5q
Clearly, the sum of the cost of the Mobile and 1 and a half of the Headphone is more than the sum of the cost of the two Laptops and that of the three Modems.
So, statement II alone is also sufficient.
Hence, either of the statements is sufficient to reach the answer.