Mixture and Alligation Questions PDF for SBI Clerk Pre, IBPS Clerk Pre, IBPS RRB

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Direction : Read the following questions carefully and choose the right answer.
1
A shopkeeper deals in milk and 45 litre mixture is to be distributed in Milk & Water in the ratio of 4 : 1. If 4 litre milk & 3 litre water will be added in the mixture then what will be the new ratio of water and milk?
» Explain it
B
In the mixture of 45 litre,
Milk =  45  × 4 = 36 litre, Water =  45  × 1 = 9 litre
5 5
New ratio,

= 9 + 3 : 36 + 4

= 12 : 40 = 3 : 10

Hence, option B is correct.
 
2
48 litre of Glycerin is mixed with 144 litre Rose water. D litre of total mixture is taken out and 32 litre Glycerin and 48 litre Rose water are added in the mixture. The final mixture contains 30% Glycerin, find the quantity of the mixture that is taken out.
» Explain it
B
Total mixture = 48 + 144 = 192 litre

% of Glycerin = 48/ 192 × 100 = 25% = % of Rose water = 75%

In the final mixture glycerin= 30%, Rose water = 70%

Ratio = 30 : 70 = 3 : 7

(48 – D × 25% + 32) : (144 – D × 75% + 48) = 3 : 7

7 (48 – D × 25% + 32) = 3 (144 – D × 75% + 48)

7 (80 – 0.25 D) = 3 (192 – 0.75 D)

560 – 1.75 D = 576 – 2.25 D

2.25 D – 1.75 D = 576 – 560

0.5 D = 16

D = 32 litre

Hence, option B is correct.
3
In a mixture, the ratio of the alchohol and water is 6 : 5. When 22 litre mixture are replaced by water, the ratio becomes 9 : 13. Find the quantity of water after replacement.
» Explain it
D
Let alchohol = 6x, water = 5x

According to the question,


6x – 22 ×  6  : 5x – 22 ×  5  + 22 = 9 : 13
11 11

6x – 12 : 5x – 10 + 22 = 9 : 13

13 (6x – 12) = 9 (5x + 12)

78x – 156 = 45x + 108

78x – 45x = 156 + 108

33x = 264

x = 8

Water after replacement = 5 × 8 – 10 + 22 = 40 + 22 = 52 litre

Hence, option D is correct.
4
A solution of ‘THANDA SHARBAT’ has 15% sugar. Another solution has 5% sugar. How many liters’ of the second solution must be added to the 20L of first solution to make a solution of 10 % sugar?
» Explain it
D
Let required amount of second solution to be added = a L

Then     15 × 20 + 5a  = 10
20 + a

⇒ 300 + 5a = 200 + 10a

⇒ 5a = 100

⇒ a = 20

Hence, option (D) is correct.
 
5
Copper and Zinc are in the ratio 2 : 3 in 200 gms of an alloy. The quantity (in grams) of copper to be added to it to make the ratio 3 : 2 is:
» Explain it
B
Given, quantity of the alloy = 200 gm.

If Copper : Zinc = 2 : 3

Then quantity of Copper =  2  × 200 = 80gm
5

And quantity of Zinc =  3  × 200 = 120gm
5


 As per the  question,

80 + x  =  3
120 2


 x = 100 gm

So  The quantity of Copper to be added is 100gm


Hence, option B is correct.