Important for :

1

B

In the mixture of 45 litre,
Milk = | 45 | × 4 = 36 litre, Water = | 45 | × 1 = 9 litre |

5 | 5 |

= 9 + 3 : 36 + 4

= 12 : 40 = 3 : 10

Hence, option B is correct.

2

B

Total mixture = 48 + 144 = 192 litre% of Glycerin = 48/ 192 × 100 = 25% = % of Rose water = 75%

In the final mixture glycerin= 30%, Rose water = 70%

Ratio = 30 : 70 = 3 : 7

(48 – D × 25% + 32) : (144 – D × 75% + 48) = 3 : 7

7 (48 – D × 25% + 32) = 3 (144 – D × 75% + 48)

7 (80 – 0.25 D) = 3 (192 – 0.75 D)

560 – 1.75 D = 576 – 2.25 D

2.25 D – 1.75 D = 576 – 560

0.5 D = 16

D = 32 litre

Hence, option B is correct.

3

D

Let alchohol = 6x, water = 5xAccording to the question,

6x – 22 × | 6 | : 5x – 22 × | 5 | + 22 = 9 : 13 |

11 | 11 |

6x – 12 : 5x – 10 + 22 = 9 : 13

13 (6x – 12) = 9 (5x + 12)

78x – 156 = 45x + 108

78x – 45x = 156 + 108

33x = 264

x = 8

Water after replacement = 5 × 8 – 10 + 22 = 40 + 22 = 52 litre

Hence, option D is correct.

4

D

Let required amount of second solution to be added = a LThen | 15 × 20 + 5a | = 10 |

20 + a |

⇒ 300 + 5a = 200 + 10a

⇒ 5a = 100

⇒ a = 20

Hence, option (D) is correct.

5

B

Given, quantity of the alloy = 200 gm.If Copper : Zinc = 2 : 3

Then quantity of Copper = | 2 | × 200 = 80gm |

5 |

And quantity of Zinc = | 3 | × 200 = 120gm |

5 |

As per the question,

80 + x | = | 3 |

120 | 2 |

⇒* x *= 100 gm

So The quantity of Copper to be added is 100gm

Hence, option B is correct.