1

2

3

C

We can easily solve this question by applying the 'Hit & Trial' approach.

The condition says that sum of the numbers and its reciprocal must be (13/6) and in

the 1

5 | (the num) + | 3 | (its reciprocal) will give us | 34 | . |

3 | 5 | 15 |

Option 'A' hence gets eliminated.

the 2

2 + | 1 | = | 5 | |

2 | 2 |

Option 'B' hence gets eliminated too.

the 3rd option, the sum of

3 | + | 2 | = | 13 | . |

2 | 3 | 6 |

Option 'C' hence is the correct answer.

_________________________________________________________

Given expression:'

Then, z + | 1 | = | 13 |

z | 6 |

⇒ |
z^{2 }+ 1 |
= | 13 | . |

z | 6 |

⇒ 6z

⇒ 6z

⇒ z = 2/3 or 3/2.

Hence, option C is correct.

4

5