Join Testzone
ABOUT US
CONTACT US
Blog
support@smartkeeda.com
Quantitative Aptitude
Reasoning Aptitude
General English
Knowledge Bank
Current Affairs
Law Exams
Probs on Numbers Quiz 3
Probs on Numbers Quiz 2
Probs on Numbers Quiz 1
Home
»
Quantitative Aptitude
»
Arithmetic
»
Problems on Numbers Quiz
» CGLTier 1 » Probs on Numbers Quiz 2
Problems On Numbers Questions for SSC, CDSE, CLAT and Railways Exams
all
SBI Clerk Pre
SBIClerk
IBPS Clerk Pre
IBPSClerk
IBPS PO Pre
IBPSPO
SBI PO Pre
SBIPO
IBPS RRB
SSC 10+2
CGLTier 1
CGL Tier 2
CDSE
CLAT
MAT
NIFT
IBPS CL Mains
IBPS SO Pre
Syndicate Bank PO
Canara Bank PO
Railways
RBI Grade B
RRB Scale I Pre
CCC
IBPS SO Law
IBPS SO HR
IBPO SO AFO
IBPS SO IT
UGC NET
IBPS SO Mktg
RJS
LIC AAO
NABARD
EPFO SSA Pre
LIC Assistant
Join Testzone, Smartkeeda’s Test Series Platform for:
Hi
Directions: Study the following questions carefully and choose the right answer.
Important for :
CDSE
CGL Tier 2
CGLTier 1
CLAT
Railways
SSC 10+2
1
The ratio between a two-digit number and the sum of the digits of that number is 4 : 1. If the digit in the unit's is three more than the digit in the ten's places, what is the number?
A
25
B
36
C
47
D
58
» Explain it
Correct Option:
B
Let the ten's digit be x. then, unit's digit = (x + 3).
Sum of the digits = x + (x + 3) = 2x + 3.
Let the number = 10x + (x +3) = 11x + 3
So,
11x + 3
=
4
2x + 3
1
⇒ 11x + 3 = 4(2x + 3) ⇔ 11x + 3 = 4 (2x + 3)
⇒ 3x = 9 ⇒ x = 3
Hence, required number = 11x + 3 ⇒ 36.
Hence, option B is correct.
1
A
B
C
D
» Explain it
सही विकल्प :
B
B
2
If three numbers are added in pairs, the sums equal 10, 19 and 21. Find the numbers?
A
2,3 and 5
B
6,8 and 10
C
6, 4 and 15
D
12, 9 and 15
» Explain it
Correct Option:
C
Smart Approach:
By 'Hit & Trial' method
(2 + 3) ≠ 10. Option 'A' gets eliminated
(6 + 8) ≠ 10. Option 'B' gets eliminated too.
(6 + 4) = 10
(4 + 15) = 19
& (15 + 6) = 21
It's evident that the numbers in option 'C' satisfy the given condition.
Hence, option 'C' is the correct answer.
_____________________________________________________________
Traditional Approach:
Let the numbers be x, y and z. then
x + y = 10 .....(1) y + z = 19 .....(2) x + z = 21 ....(3)
Adding (1), (2) and (3),
we get : 2(x + y + z) = 50 or (x + y + z) = 25.
Thus, x = (25 – 19) = 6; y = (25 – 21) = 4; z = (25 – 10) = 15.
Hence, the required numbers are 6, 4 and 15.
Hence, option C is correct.
2
A
B
C
D
» Explain it
सही विकल्प :
C
C
3
50 is divided into two parts such that the sum of their reciprocal is 1/12 find the two parts.
A
14, 36
B
20, 30
C
38, 12
D
35, 15
» Explain it
Correct Option:
B
For shortcut method kindly refer to the video.
Let the two parts be x and (50 – x).
Then,
1
+
1
=
1
x
50 – x
12
⇒
50 – x + x
=
1
x(50 – x)
12
⇒ x
2
– 50x + 600 = 0 ⇒ (x – 30) (x – 20) = 0
⇒ x = 20 or x = 30
So, the parts are 30 and 20.
Hence, option B is correct.
3
A
B
C
D
» Explain it
सही विकल्प :
B
B
4
If sum of two numbers is 50, one of them 2/5th of other one then the value of numbers?
A
115
,
235
7
7
B
150
,
200
7
7
C
240
,
110
7
7
D
250
,
100
7
7
» Explain it
Correct Option:
D
Let's the first numeber is x so,
another number will be
2
x, then,
5
⇒ x +
2
x = 50
5
⇒
5x + 2x
= 50
5
⇒
7x
= 50
5
⇒ x =
250
7
Similarly,
Another number will be
=
2
×
250
=
100
5
7
7
Hence, the numbers are
250
,
100
.
7
7
Hence, option D is correct.
4
A
B
C
D
» Explain it
सही विकल्प :
D
D
5
A number exceeds its two fifth by 75. The number is:
A
112
B
150
C
125
D
100
» Explain it
Correct Option:
C
Let the number be x
As per the the equation,
x –
2
x = 75
5
∴
3
x = 75 ⇒ x = 125.
5
Hence option C is correct.
5
A
B
C
D
» Explain it
सही विकल्प :
C
C
Previous Excercise
Next Excercise