1

2

C

By 'Hit & Trial' method

(2 + 3) ≠ 10. Option 'A' gets eliminated

(6 + 8) ≠ 10. Option 'B' gets eliminated too.

(6 + 4) = 10

(4 + 15) = 19

& (15 + 6) = 21

It's evident that the numbers in option 'C' satisfy the given condition.

Hence, option 'C' is the correct answer.

_____________________________________________________________Let the numbers be x, y and z. then

x + y = 10 .....(1) y + z = 19 .....(2) x + z = 21 ....(3)

Adding (1), (2) and (3),

we get : 2(x + y + z) = 50 or (x + y + z) = 25.

Thus, x = (25 – 19) = 6; y = (25 – 21) = 4; z = (25 – 10) = 15.

Hence, the required numbers are 6, 4 and 15.

Hence, option C is correct.

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5