 # Download Profit and Loss Questions for SBI PO Mains, IBPS Mains and RBI Grade B 2021

Important for :
1
Saleem has 40 articles of same cost price. He sold 24 articles at a profit of 30% and 16 articles at a profit of 20%. Had he sold all the articles at a profit of 15%, then his profit would have been reduced by Rs. 880. What is the cost price (in Rs.) of each article?
» Explain it
B
 Profit on all the articles = 24 × 30 + 16 × 20 = 26% 40

(26 – 15)% of total CP of 40 articles = 880

Total CP of 40 articles = Rs. 8000

 C.P. of one article = 8000 = Rs. 200 40

Hence, Option B is correct.
2
Sohan bought an old Honda Bike and spent Rs. 1500 on its repairs. Then Sohan sold it to Rakesh at a prolit of 20%. Rakesh sold it to Raj at a loss of 10%. Raj finally sold it for Rs. 12100 at a profit of 10%. How much did Sohan pay for the old Honda Bike?
» Explain it
C
 Cost price of Honda Bike for Raj = 12100 = 11000 1.1

Since selling price of Honda Bike by Rakesh = Rs. 11000

From question Cost price of Honda Bike for Rakesh

 = 11000 = Rs. 12222.22 0.9

Since selling price of Honda Bike by Sohan = Rs. 12222.22

According to question sohan got 20% profit

Since Cost Price of Honda Bike for Sohan

 = 12222.22 = Rs. 10185.2 1.2

This cost price is includes a Rs. 1500 for repairs.

Hence purchase price for Sohan = 10185.2 – 1500 = Rs. 8685

Therefore option (C) is correct.
3
Sourav Ganguly wants to buy a total of 100 sports equipment using exactly a sum of Rs.1000. He can buy ball at Rs.20 per unit, wicket at Rs.5 per unit and bat at Rs.1 per unit. If he has to buy at least one of each equipment and cannot buy any other type of equipment, then in how many distinct ways can he make his purchase?
» Explain it
C
Let the number of ball, wickets and bats purchased be A, B and C, respectively.

Thus,

20A + 5B + C = 1000 and A + B + C = 100

Solving the above two equations by eliminating C, we Get

19A + 4B = 900

 ⇒ B = 225 – 19 A 4

Now, as B is the number of wickets and 0 < B < 99,

So, putting these limiting values of B in the above equation will provide the value of A as 27 < A < 47.

Since A has to be the multiple of 4, so possible values of A are 28, 32, 36, 40 and 44.

Now, for A = 28 and 32; A + B > 100, so these values of A can be rejected.

For all other values of A, we get the desired solution:

A = 36, B = 54, C = 10

A = 40, B = 35, C = 25

A = 44, B = 16, C = 40

Thus, there are three possible solutions.

Hence, option (C) is correct.
4
In St. Peter’s college Agra an exhibition was organised, hand-made crafts are displayed for sale. Some students are assigned the work of selling crafts. The overall profit p depends on the number of students x selling the crafts on that particular day and is given by the equation p = 250x – 5x2. The school manager claims to have made a maximum profit. Find the number of students engaged in selling the crafts and the maximum profit made.
» Explain it
C
For profit to be maximum, the derivative of p with reference to x must be 0 and hence

 = d (250x – 5x2) = 0 = 250 – 10x = 0 dx

So x = 25

Now p for x = 25 is

= 250 (25) – 5 (25)2 = Rs3125

Hence, option (C) is correct.
5
The marked price of an article is Rs. 3,000. If two successive discounts, each of x%, on the marked price is equal to a single discount of Rs. 1,174.80, then what will be the selling price of the article if a single discount of x% is given on the marked price?
» Explain it
B
 Discount = 1174.80 × 100 = 39.16 3000

 x + x – ( x × x ) = 39.16 100

x = 22

 So the answer = 3,000 × (100 – 22) = 2340 100

Hence, Option B is correct.