Important for :

1

E

Let the income of Asha in 2018 and 2017 be 3x and 5x respectively.

Let the income of Ravenna in 2018 and 2017 be 3y and 2y respectively

Since, the ratio of their income in the year 2017 was 5 : 4

5x : 2y = 5 : 4

2x = y

The sum of their incomes in 2018 is Rs. 10242

3x + 3y = 10, 242

9x = 10, 242

x = 1,138 and y = 2276

Ravenna’s income for the year 2017 = 2y = Rs. 4552

Hence, option E is correct.

2

D

Amount of milk poured into C from vessel A and B= 2 × | 3 | + 3 × | 2 | = | 16 | litres |

5 | 3 | 5 |

Also, amount of water poured into C from vessels A and B

= 5 – | 16 | = | 9 | litres |

5 | 5 |

Given, 5 litres represent 40% of the capacity of vessel C, vessel C has a capacity of

= 5 × | 5 | = 12.5 litres |

2 |

To make the quantities of water and milk same in the vessel C, quantity of water to be added

= | 16 | – | 9 | = | 7 | litres |

5 | 5 | 5 |

Therefore, reqd. answer = | 7/5 | = | 14 |

12.5 | 125 |

Hence, option D is correct.

3

D

Let the score of the topper be T.

Total score of the 52 students = 52 × 85 = 4420

Total score of the remaining 47 students after scores of the best five performers are removed = 47 × 83 = 3901

Total score of the top five students = 4420 – 3901 = 519

T + (total score of the next 4 top scores) = 519

T is the maximum when the total score of the next 4 top scorers is minimum.

Total score of the next 4 top scorers has a minimum value of 80 + 81 + 82 + 83 = 326 (since all the top 5 scores are distinct) and the least is 80.

T has a maximum value of 519 – 326 = 193

Hence, option D is correct.

4

B

Ratio of the number of coins of denominations Rs. 1 : Rs. 2 : Rs. 5 = 5 : 7 : 6

Let, the number of coins of Rs. 1, Rs. 2 and Rs. 5 in the bag be 5x, 7x and 6x.

Since, the total value of Rs. 1 coin in the bag is Rs. 15

So, the number of coins of Rs. 1 in a bag = 15

5x = 15 , ⇒ x = 3

Therefore, number of Rs. 5 coins in the bag = 6x = 18

So, required value of Rs. 5 coins = 6 × 3 × 5 = Rs.90

Hence, option B is correct.

5

B

Let the children be P, Q, R and S and Father be F

Chocolates with P : Q : R= 3 : 7 : 11

Let the number of chocolates be 3k, 7k and 11k

Total chocolates with three eldest children = 21k

Chocolate with F and S = 3 × 21k = 63k

Total chocolates = (21k + 63k) = 84k

Chocolate with F : (P + Q + R + S) = 3 : 4

Total 7 units of chocolate = 84 k

1 unit = 12k

Chocolate with F = 3 × 12k = 36k

Chocolate with S = (63k – 36k) = 27k

27 k = 81 → k=3

Total number of chocolates = 84k = 84 × 3 = 252

Hence, option B is correct.

Ratio and Proportion Questions Quiz for Bank, CET, LIC Exams

Ratio and Proportion concept is one of the most important parts of word problems, in each exam bank exams around 1 to 2 questions has been seen. If you are aware about tricks and short cuts of ratio and proportion you can easily solve world problems within a minute.

Ratio, Proportion and Variation form an interesting chapter. The basic fundamentals of this chapter are extensively used in solving many questions in chapters like time and work, time and distance. You are likely to find the quite a few questions in the actual exams, based on these concepts

Here first we will discuss about, “what is ratio”

The comparison between two quantities of the same kind of units. Two of different kinds can’t be compared. Thus, there is no relation between rupees and 20 men. The ratio of a and b is usually written as a : b or a/b.

Ratio and Proportion questions asked in SBI Clerk Pre, IBPS Clerk Pre, IBPS RRB Pre, IBPS RRB Office Assistant Pre, IBPS RRB Scale 1 Pre, IBPS RRB Office Assistant Mains, IBPS RRB Scale 1 Mains, IBPS PO Pre, IBPS SO Pre, IBPS PO, SBI PO Pre, SBI SO Pre, SBI PO, LIC, NIACL, OICAL, CLAT, MAT, NIFT, CTET etc.

In this above quiz you will practice of 10 Ratio and Proportion questions with detailed solution, you will also get to know about how to solve ration and proportion questions fast by using tricks and shortcuts at free of cost.

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