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SBI Clerk Quantitative Aptitude Questions PDF with Solution at Smartkeeda

Directions : Read the following questions carefully and choose the right answer.
1
24 litres of Petrol and 6 litres of Diesel are mixed together. A man removes 18 litres of the mixture. Calculate the capacity of petrol and diesel in the remaining mixture? 
» Explain it
C
The ratio in the initial mixture and the remaining mixture remains same.

The ratio in the initial mixture = 24 : 6 = 4 : 1

Since, 18 litres is removed, 12 litres remains.

Capacity of petrol in the remaining mixture

= 12 ×  4  = 9.6 litres
5

Capacity of Diesel in the remaining mixture

= 12 ×  1  = 2.4 litres
5

Hence, option C is correct.
2
Priyanka and Sonam decided to do a project together. Priyanka and Sonam can alone do the project in y and (y + 3) days respectively. They were paid Rs. 2400 for completing the project in 5 days. They took help of Anchal and completed the project in time. If Anchal’s share is Rs. 600, find the value of y.  
» Explain it
C
Priyanka and Sonam can do 1/y and 1/(y + 3)th part of the project in a day respectively.

In 5 days, they can do 5 {1/y + 1/(y+3)} of the total project.

Total profit was Rs. 2400, Anchal is getting Rs. 600 as her share for the part of the project she did.

x =  600  =  1
2400 4

So, Anchal did 1/4th of the project, rest will be done by Priyanka and Sonam i.e., 3/4th part of the project.

→ 5  ( 1  +  1 )  =  3
y y + 3 4

Solving this we get y = 12

Hence, option C is correct.
3
Sanjay has some money, he spends 14.28% of his money on one day international cricket tickets, 11.11% of the remaining money on snacks and remaining money he kept for lunch and transport. If the money kept for lunch and transport is in the ratio 5 : 3 respectively and money kept for transport is Rs. 330, find the money spent on tickets?    
» Explain it
B
14.28% =  1
7
 
11.11% =  1
9

LCM {7, 9} = 63

Let the money he had be Rs. 63x

He spend 1/7 on tickets =  63x  = Rs. 9x
7

He is left with = (63 – 9)x  = Rs. 54x

Now, he spend 1/9 of 54x on snacks i.e., =  54x  = Rs. 6x
9

Remaining money = (54 – 6)x = Rs. 48x

48x is divided in the ratio 5 : 3 for lunch and transport,

For transport =  48x × 3  = 18x
8

According to the question,

18x corresponds to 330

x correspond to =  330  =  55
18 3

Money spend on tickets, 9x will correspond to

9 × 55  = Rs. 165
3

Hence, option B is correct.
4
5 years ago, the age of father was 2.25 times the age of his son. 2 years hence, the age of father becomes 2.6 times the age of his daughter. If the son is 7 years elder to daughter, find the present age of Father.
» Explain it
D
Let the present age of father, son and daughter be F, S and D respectively.
 
According to the question, 
 
5 years ago, the age of father is 2.25 times the age of son.
 
F – 5 = 2.25 (S – 5)
 
F = 2.25S – 5 (2.25 – 1)
 
F = 2.25S – 6.25     ...(1)
 
2 years hence, the age of father becomes 2.6 times the age of daughter,
 
F + 2 = 2.6 (D + 2)
 
F = 2.6D + 2 (2.6 – 1)
 
F = 2.6D + 3.2          ...(2)   
 
S – D = 7                   ...(3)
 
From (1) and (2),
 
2.25S – 6.25 = 2.6D + 3.2
 
2.25S – 2.6D = 9.45    ...(4)
 
Multiply (3) by 2.25 and subtract it from (4)
 
– 0.35D = – 6.3
 
D = 18 years, S = 18 + 7 = 25 years
 
Substituting value of D in (2), 
 
F = 2.6 × 18 + 3.2 
 
F = 50 years 
 
Hence, option D is correct.
5
Three taps T, U and V can fill a tank in z, (z + 3) and (z + 8) hours respectively. They are opened alternatively for one hour each starting with Tap T followed by U and V respectively. Find the value of z, if the tank gets filled completely in 15 hours.
» Explain it
E
Taps T, U and V can fill in z, (z + 3) and (z + 8) hours respectively.

Capacity of tank = LCM {z, z + 3, z + 8}

In 1st hour, T is opened, in 2nd hour U is opened and in the 3rd hour V is opened. In 3 hours, the taps were opened once, alternatively.

According to the question, total time taken to the tank completely = 15 hours

→  ( 1  +  1  +  1 )    
z z + 3 z + 8  =  1
  3 15

→  ( 1  +  1  +  1 )  =  1
z z + 3 z + 8 5

Substituting the values from the options,

→ z = 15,

→  ( 1  +  1  +  1 )  =  138 + 115 + 90
15 18 23 2070

→  343  ≠  1
2070 5

→ z = 20

→  ( 1  +  1  +  1 )  ≠  1
20 23 28 5

→ z = 10

→  ( 1  +  1  +  1 ≠  1
10 13 18 5

→ z = 18

→  ( 1  +  1  +  1 )  ≠  1
18 21 26 5

→ z = 12

→  ( 1  +  1  +  1 )  =  5 + 4 + 3
12 15 20 60
 
→  12  =  1
60 5

→  1  =  1
5 5

Hence, option E is correct.

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Quantitative Aptitude is one most important section when it comes to SBI Clerk Exams, you can’t neglect it. So be sure you are ready to improve your mathematical skills with help of these quizzes, we at Smartkeeda will give you important Quantitative Aptitude Quizzes for SBI Clerk Pre 2020 which through you becomes confident towards you quant section preparation. If you devote more time to this section you get more marks because answers of the quantitative aptitude section are surer than answers of reasoning section. Here are some important links for the individual exercise of different Quantitative Aptitude Chapters.

Quantitative Aptitude for SBI Clerk 2020 consist of given below chapters:
  • Percentage questions for SBI Clerk Pre Click Here
  • Quadratic Equations for SBI Clerk Pre Click Here
  • Problems on Numbers Questions for SBI Clerk Pre Click Here
  • Probability Questions for SBI Clerk Pre Click Here
  • Partnership Questions for SBI Clerk Pre Click Here
  • Ratio & Proportion Questions for SBI Clerk Pre Click Here
  • Mixture & Alligation Questions for SBI Clerk Pre Click Here
  • Boat & Stream Questions for SBI Clerk Pre Click Here
  • Permutation & Combination Questions for SBI Clerk Pre Click Here
  • Problems on Trains Questions for SBI Clerk Pre Click Here
  • Simple Interest Questions for SBI Clerk Pre Click Here

Quantitative Aptitude is a very interesting topic when it comes to SBI Clerk Prelims preparation. If you don’t find the Quantitative Aptitude section interesting, it simply means you have not tried to understand it. At Smartkeeda you will get Quant Questions Quiz on regular basis for SBI Clerk 2020. So that will create interest with fun towards the Quant section. 

Here are some important examples regarding Quantitative Aptitude for SBI Clerk 2020 with PDFs.

Q.1.  Priyanka and Sonam decided to do a project together. Priyanka and Sonam can alone do the project in y and (y + 3) days respectively. They were paid Rs. 2400 for completing the project in 5 days. They took help of Anchal and completed the project in time. If Anchal’s share is Rs. 600, find the value of y.

15
9
12
18
21
 
Explanation:  

Priyanka and Sonam can do 1/y and 1/(y + 3)th part of the project in a day respectively.

In 5 days, they can do 5 {1/y + 1/(y+3)} of the total project.

Total profit was Rs. 2400, Anchal is getting Rs. 600 as her share for the part of the project she did.

x =  600  =  1
2400 4

So, Anchal did 1/4th of the project, rest will be done by Priyanka and Sonam i.e., 3/4th part of the project.

→ 5  ( 1  +  1 )  =  3
y y + 3 4

Solving this we get y = 12

Hence, option C is correct.
.
Q.2.  Three taps T, U and V can fill a tank in z, (z + 3) and (z + 8) hours respectively. They are opened alternatively for one hour each starting with Tap T followed by U and V respectively. Find the value of z, if the tank gets filled completely in 15 hours.

15
20
10
18
12
 
Explanation:  

Taps T, U and V can fill in z, (z + 3) and (z + 8) hours respectively.

Capacity of tank = LCM {z, z + 3, z + 8}

In 1st hour, T is opened, in 2nd hour U is opened and in the 3rd hour V is opened. In 3 hours, the taps were opened once, alternatively.

According to the question, total time taken to the tank completely = 15 hours

→  ( 1  +  1  +  1 )    
z z + 3 z + 8  =  1
  3 15

→  ( 1  +  1  +  1 )  =  1
z z + 3 z + 8 5

Substituting the values from the options,

→ z = 15,

→  ( 1  +  1  +  1 )  =  138 + 115 + 90
15 18 23 2070

→  343  ≠  1
2070 5

→ z = 20

→  ( 1  +  1  +  1 )  ≠  1
20 23 28 5

→ z = 10

→  ( 1  +  1  +  1 ≠  1
10 13 18 5

→ z = 18

→  ( 1  +  1  +  1 )  ≠  1
18 21 26 5

→ z = 12

→  ( 1  +  1  +  1 )  =  5 + 4 + 3
12 15 20 60
 
→  12  =  1
60 5

→  1  =  1
5 5

Hence, option E is correct.

Q.3. A biker travels a distance of 190 km in 3 hours partly at a speed of 100 kmph and partly at a speed of 50 kmph. If the distance travelled by speed 50 kmph is 'a' km, then find the time taken to travel 'a' km with 55 kmph speed?

1 hour
3 hours
2 hours
4 hours
2.5 hours

Explanation:  

Let the distance travelled with speed 50 kmph be a and the distance travelled with 100 kmph be (190 – a) km respectively.

According to the question,

190 – a  +  a  = 3
100 50
 
190 – a + 2a  = 3
100

a = 110 km

Now speed is 55 kmph,

Time taken =  110  = 2 hours
55

Hence, option C is correct.
 
All the above questions through, you must make sure about arithmetic miscellaneous questions which have been seen in the last few years. We hope this above Quantitative Aptitude for SBI Clerk 2020 will clear your all doubts regarding bank clerk exams.

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