# High Level Free Study Material for SBI PO 2020 and Download New Pattern Quantitative Questions for Bank PO Exams like IBPS PO, IBPS RRB Scale 1, SBI Clerk, IBPS Clerk at Smartkeeda

Important for :
1
Saurav travels from Delhi to Patna. He stops at equidistant places, that is Kanpur, Allahabad and Gaya during his journey. He covers the first one-fourth distance at a speed of 60 km/hr, the second one-fourth distance at a speed of 30 km/hr, third one fourth distance at a speed of 40 km/hr the last one-fourth distance at a speed of 60 km/hr. However, while returning, his uniform speed is 60 km/hr and he stops only at Jaunpur, which is exactly at the mid-point between Delhi and Patna. What is the average speed (in km/hr) of Saurav during the whole journey, not considering his halt time?
» Explain it
A
Suppose total distance between Delhi to Patna is x

 Average speed = total distance travelled total time taken

Total distance travelled during whole journey = 2x

 x x x x Total time taken = 4 + 4 + 4 + 4 + x = 19x 60 30 40 60 60 480

 Required average speed = 2x = 50.52 km/hr 19x 480

Hence, option A is correct.
2
In 2016 the ratio of salaries of Muskan and Babli was 2 : 3. The ratios of the salary of 2016 to that of the 2017, in the case of Muskan and Babli respectively, are 3 : 4 and 5 : 7. If this year i.e. 2017 the difference in their salaries is 2300, what is Babli’s salary this year?
» Explain it
B
Let a year ago i.e. in 2016 Muskan and Babli’s salaries were x and y and now it is m and n respectively.

Given that,

 x = 2 ......(i) y 3

 x = 3 ......(ii) m 4

 y = 5 ......(iii) n 7

From (i) and (ii),

 m = (2 × 4) = 8 ......(iv) y (3 × 3) 9

From (iii) and (iv)

 m = (8 × 5) = 40 y (9 × 7) 63

 n = 63 m 40

 n – 1 = 63 – 1 m 40

 n – m = 63 – 40 m 40

 n – m = 23 .....(v) m 40

Also, given that (n – m) = 2300

Putting the value In equation (v)

 2300 = 23 m 40

 m = 40 × 2300 = 4000 23

So, n = 4000 + 2300 = 6300

Hence, option B is correct.
3
A man rows to a certain place(downstream) and comes back(upstream), but by mistake he covers 1/3rd more distance while coming back. The total time for this journey is 10 hours. The ratio of speed of boat to that of stream is 2: 1. If the difference between upstream and downstream speed is 12km/hr, then how much time will the man take to reach to starting point from his present position?
» Explain it
D
Speed of boat and stream be 2x and x respectively.

So downstream speed = 2x + x = 3x,

Upstream speed = 2x – x = x

Let total distance between points is d km

So he covered d km downstream,

 While coming back i.e. upstream he covers d + 1 × d = 4d km 3 3

Total time for this journey is 10 hrs.
 ⇒ d + 4d = 10 3x 3x

⇒ d = 6x

Now also given, that (2x + x) – (2x – x) = 12

⇒ x = 6

So, d = 36 km
 Now to come to original point, he will have to cover 1 × 36 = 12 km 3

And with speed 3x = 18 km/hr (downstream)
 Hence, time is 12 × 60 = 40 minutes 18

Therefore, option (D) is correct.
4
Water flows out at the rate of 20 m/min from a cylindrical pipe of radius 5 mm. Find the time taken to fill a conical tank whose diameter at the surface is 40 cm and depth 24 cm.
» Explain it
B
 Volume of cone = 1 πr2h 3

 = 1 × 22 × 20 × 20 × 24 3 7

= 10057.14 cm3

Radius of pipe = 5 mm

= 0.5 cm

Volume of water flowing out of the pipe per minute (in cm3)

= 1000 × 0.5 × 0.5 × π

= 785 cm3

Hence, time taken to fill the tank

 = 10057.14 785

= 12.8 minutes

Hence, option B is correct.
5
It takes 30 minutes to empty a half-full tank by draining it at a constant rate. It is decided to simultaneously pump water into the half-full tank while draining it. What is the rate at which water has to be pumped in so that it gets fully filled in 10 minutes?
» Explain it
A
Drainage pipe can drain complete tank in 60min.

Let the filling pipe can fill the tank in x min

Now, both are operational and tank is half filled

Also remaining half needs to get filled in 10 min

 10 { 1 – 1 } = 1 x 60 2

⇒ x = 15min.
 Hence, filling pump needs to have rate be 60 15
= 4 times the draining rate.

Therefore, option (A) is correct.
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Welcome to the www.smartkeeda.com, In this article we are going to practice different type of Miscellaneous Arithmetic Questions with Solution for SBI PO Pre 2020, These questions also important for other Bank exams like SBI PO, IBPS PO, IBPS Clerk, SBI Clerk, NIACL, NABARD, LIC etc.

Its a very important topic for SBI PO Aspirants to practice. Miscellaneous Arithmetic  Questions are generally called Word problems which belongs Average, Percentage, Ratio and Proportion,  Profit and Loss, Compound Interest, Simple Interest etc.
This Article will you to understand what type question is being asked in the form miscellaneous in SBI PO Pre, SBI Clerk 2020 Exams. You will also get here Miscellanenous Quesiton for All Bank PO Exams 2020.

Here are the various links that refers to miscellaneous quiz for SBI PO Pre, In this link we will discuss word problems chapter individually one by one.

Average Question and answers for SBI PO Pre IBPS PO Pre 2020

Profit and Loss Questions for SBI PO Pre IBPS PO Pre 2020

Time and Work Questions and Answer for SBI PO Pre and IBPS PO Pre 2020

Probability Questions and Answer for SBI PO Pre 2020

Time and Distance Questions and Answer for IBPS PO Pre and SBI PO Pre 2020

Compound Interest Questions and Answer for IBPS PO Pre and SBI PO Pre 2020

Percentage Questions and Answer for IBPS PO Pre and SBI PO Pre 2020

Ration and Proportion Questions and Answer for SBI PO Pre 2020

Permutation and Combination Questions and Answer for SBI PO Pre 2020

There are many other chapters like Boats and stream, Partnership, Mixture and Alligation, Simple Interest, Problems on Trains etc. These kind of questions has been seen in SBI PO Exams. We would like to recommend you to practice miscellaneous question for sbi po pre and ibps po at Smartkeeda with detailed solution at Free cost. You can download miscellaneous questions pdf with explanation for ibps po 2020.

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