# High Level Quantitative Aptitude for SBI PO 2019 PDF | New Pattern Based Quantitative Aptitude for SBI PO, IBPS PO, SBI Clerk, IBPS Clerk, IBPS RRB PO, 2019 at Smartkeeda

Directions : Study the following information carefully and answer the questions given beside.
Important for :
1
Four friends, Ram, Ghanshyam, Ravi, and Sham have taken up a typing project. The typing speed of Ram is 40% more the typing speed of Ghanshyam and the typing speed of Ravi is 37.5% less than the typing speed of Sham. The ratio between the typing speed of Ghanshyam and Ravi is 1 : 2. All of four works one by one each day in rotation, starting with Ghanshyam followed by Ram, Sham and Ravi respectively then they can complete the project in 173 days. [S.1 Q.1]

Find the difference between the number of days(approximately) taken by Ghanshyam alone and the number of days taken by Sham alone to complete the work?
» Explain it
B
The number of days taken by Ghanshyam alone

 = 1639a = 1639 days 5a 5

Number of days taken by Sham alone
 = 1639a = 1639 days 16 a 16

 Reqd. difference = 1639 days – 1639 days 5 16

 = 1639 × 11 = 225.3625 = approximately 225 days 80

Hence, option B is correct.

Common explanation :

Let the typing speed of Ghanshyam = 5x then the typing speed of Ram = 140% of 5x = 7x

Let the typing speed of Sham = 8y then the typing speed of Ravi = 62.5% of 8y = 5y

Ghanshyam: Ravi= 1 : 2 = 5x : 5y, x : y = 1 : 2

Therefore, Ghanshyam: Ram : Sham : Ravi = 5x : 7x : 8y : 5y

= 5 × 1 : 7 × 1 : 8  ×  2: 5 × 2 = 5 : 7 : 16 : 10

Let it be 5a, 7a, 16a, 10a = their efficiency = typing speed

Therefore, all of four works one by one each day in rotation, starting with Ghanshyam then the total units of work done by them in 4 days (one rotational shift) = 5a + 7a + 16a + 10a = 38a

According to the question, they take 173 days it means 43 rotational shifts + Ghanshyam’s 1-day work

Therefore, the total units of work done in 173 days = 43 × 38a + 5a = 1634a + 5a = 1639a
2
Four friends, Ram, Ghanshyam, Ravi, and Sham have taken up a typing project. The typing speed of Ram is 40% more the typing speed of Ghanshyam and the typing speed of Ravi is 37.5% less than the typing speed of Sham. The ratio between the typing speed of Ghanshyam and Ravi is 1 : 2. All of four works one by one each day in rotation, starting with Ghanshyam followed by Ram, Sham and Ravi respectively then they can complete the project in 173 days. [S.1 Q.2]

If all of them work together every day then in how many days can they finish the work?
» Explain it
A
The total units of work = 1639a

If all of them work together every day then the total units of work done in one day = = 5a + 7a + 16a + 10a = 38a

 The reqd. number of days = 1639a = 1639 = 43 5 days 38a 38 38

Hence, option A is correct.

Common explanation :

Let the typing speed of Ghanshyam = 5x then the typing speed of Ram = 140% of 5x = 7x

Let the typing speed of Sham = 8y then the typing speed of Ravi = 62.5% of 8y = 5y

Ghanshyam: Ravi= 1 : 2 = 5x : 5y, x : y = 1 : 2

Therefore, Ghanshyam: Ram : Sham : Ravi = 5x : 7x : 8y : 5y

= 5 × 1 : 7 × 1 : 8  ×  2: 5 × 2 = 5 : 7 : 16 : 10

Let it be 5a, 7a, 16a, 10a = their efficiency = typing speed

Therefore, all of four works one by one each day in rotation, starting with Ghanshyam then the total units of work done by them in 4 days (one rotational shift) = 5a + 7a + 16a + 10a = 38a

According to the question, they take 173 days it means 43 rotational shifts + Ghanshyam’s 1-day work

Therefore, the total units of work done in 173 days = 43 × 38a + 5a = 1634a + 5a = 1639a
3
Four friends, Ram, Ghanshyam, Ravi, and Sham have taken up a typing project. The typing speed of Ram is 40% more the typing speed of Ghanshyam and the typing speed of Ravi is 37.5% less than the typing speed of Sham. The ratio between the typing speed of Ghanshyam and Ravi is 1 : 2. All of four works one by one each day in rotation, starting with Ghanshyam followed by Ram, Sham and Ravi respectively then they can complete the project in 173 days. [S.1 Q.3]

If Ram works at 5/7th of his original efficiency and Ghanshyam works 25% more than his original efficiency then in how many days they all can complete the project? (All of them work one by one each day in rotation starting with Ghanshyam followed by Ram, Sham and Ravi respectively)
» Explain it
D
Ghanshyam: Ram: Sham: Ravi = 5x : 7x : 8y : 5y

= 5 × 1 : 7 × 1 : 8 × 2 : 5 × 2 = 5 : 7 : 16 : 10

Let it be 5a, 7a, 16a, 10a = there efficiency = typing speed

 When Ram work 5/7th of his efficiency then 5 × 7a = 5a, 7

When Ghanshyam work 25% more than his original speed then the speed of Ghanshyam = 125% of 5a = 6.25a

Therefore, all of four works one by one each day in rotation, starting with Sham then the total units of work done by them in 4 days (one rotational shift) = 6.25a + 5a + 16a + 10a = 37.25a The total number of shifts to do 1639a units of work

 = 1639a = 44 shifts = 44 × 4 = 176 days 37.25a

Hence, option D is correct.

Common explanation :

Let the typing speed of Ghanshyam = 5x then the typing speed of Ram = 140% of 5x = 7x

Let the typing speed of Sham = 8y then the typing speed of Ravi = 62.5% of 8y = 5y

Ghanshyam: Ravi= 1: 2 = 5x: 5y, x: y = 1: 2

Therefore, Ghanshyam: Ram: Sham: Ravi = 5x: 7x: 8y: 5y

= 5 × 1 : 7 × 1 : 8  ×  2: 5 × 2 = 5 : 7 : 16 : 10

Let it be 5a, 7a, 16a, 10a = their efficiency = typing speed

Therefore, all of four works one by one each day in rotation, starting with Ghanshyam then the total units of work done by them in 4 days (one rotational shift) = 5a + 7a + 16a + 10a = 38a

According to the question, they take 173 days it means 43 rotational shifts + Ghanshyam’s 1-day work

Therefore, the total units of work done in 173 days = 43 × 38a + 5a = 1634a + 5a = 1639a
4
According to the new plan rolled out by Axis bank, the rate of simple interest on a sum of money is x% per annum for the first 4 years, y% per annum for the next 8 years and 10% per annum for the beyond the first 12 years. Ram invests some amount of money then the simple interest received by Ram at the end of 25 years is Rs. 29800. Other person, Mohan’s investments sum is same as the Ram’s investments then the simple interest revived by Mohan at the end of 32 years is Rs. 36800. If Ram invests only for 3 years then the total SI received by his is Rs. 3600 and Mohan invest only for 5 years then the total SI received by him is Rs. 6300. ​[S.2 Q.1]

If Mohan had invested the same amount of money at the rate of y% per annum simple interest for 32 years then how much more money, he would have received?
» Explain it
C
y = 15% per annum

P = 10000

The total SI received @ 15% per annum SI in 32 years

 = 10000 × 32 × 15 = Rs. 48000 100

the simple interest revived by Mohan at the end of 32 years is Rs. 36800

The required difference = 48000 – 36800 = 11200

Hence, option C is correct.

Common explanation :

Let the investments of Ram = Rs. p then the investments of Mohan = p

According to the question,

the simple interest received by Ram at the end of 25 years is Rs. 29800

 SI = P × R × T 100

29800 = p × 4 × x% + p × 8 × y% + p × 13 × 10% ----- (i)

the simple interest revived by Mohan at the end of 32 years is Rs. 91000

36800 = p × 4 × x% + p × 8 × y% + p × 20 × 10% ----- (ii)

Equation (ii) – equation (i)

70% of p = 7000

P = 10,000

Now, when Ram invest only for 3 years then

 10,000 × 3 × x = 3600 100

3x = 36

X = 12% per annum

If Mohan invests only for 5 years then the total SI received by him

10,000 × 4 × x% + 10000 × 1 × y% = 6300

10000 × 4 × 12% + 10000 × y% = 6300

By solving, y = 15%
5
According to the new plan rolled out by Axis bank, the rate of simple interest on a sum of money is x% per annum for the first 4 years, y% per annum for the next 8 years and 10% per annum for the beyond the first 12 years. Ram invests some amount of money then the simple interest received by Ram at the end of 25 years is Rs. 29800. Other person, Mohan’s investments sum is same as the Ram’s investments then the simple interest revived by Mohan at the end of 32 years is Rs. 36800. If Ram invests only for 3 years then the total SI received by his is Rs. 3600 and Mohan invest only for 5 years then the total SI received by him is Rs. 6300. [S.2 Q.2]

If Sanju invests some amount of money on the new plan rolled out by Axis bank then at the end of 50 years, he receives the total amount of Rs.14904 then find how much money had he invested in starting?
» Explain it
C
Let the total investments made by Sanju = Rs. q then

q + q × 4 × 12% + q × 8 × 15% + q × 38 × 10% = 14904

100q + 548q =14904 × 100

648q = 14904 × 100

By solving, q = 2300

Hence, option C is correct.

Common explanation :

Let the investments of Ram = Rs. p then the investments of Mohan = p

According to the question,

the simple interest received by Ram at the end of 25 years is Rs. 29800

 SI = P × R × T 100

29800 = p × 4 × x% + p × 8 × y% + p × 13 × 10% ----- (i)

the simple interest revived by Mohan at the end of 32 years is Rs. 91000

36800 = p × 4 × x% + p × 8 × y% + p × 20 × 10% ----- (ii)

Equation (ii) – equation (i)

70% of p = 7000

P = 10,000

Now, when Ram invest only for 3 years then

 10,000 × 3 × x = 3600 100

3x = 36

X = 12% per annum

If Mohan invests only for 5 years then the total SI received by him

10,000 × 4 × x% + 10000 × 1 × y% = 6300

10000 × 4 × 12% + 10000 × y% = 6300

By solving, y = 15%
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Welcome to the www.smartkeeda.com, In this article we are going to practice different type of Miscellaneous Arithmetic Questions with Solution for SBI PO Pre 2019, These questions also important for other Bank exams like SBI PO, IBPS PO, IBPS Clerk, SBI Clerk, NIACL, NABARD, LIC etc.

Its a very important topic for SBI PO Aspirants to practice. Miscellaneous Arithmetic  Questions are generally called Word problems which belongs Average, Percentage, Ratio and Proportion,  Profit and Loss, Compound Interest, Simple Interest etc.
This Article will you to understand what type question is being asked in the form miscellaneous in SBI PO Pre, SBI Clerk 2019 Exams. You will also get here Miscellanenous Quesiton for All Bank PO Exams 2019.

You can practice here Miscellaneous questions for SBI PO. You can download miscellaneous questions and answers pdf for free here.

Here are the various links that refers to miscellaneous quiz for SBI PO Pre, In this link we will discuss word problems chapter individually one by one.

Average Question and answers for SBI PO Pre IBPS PO Pre 2019

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There are many other chapters like Boats and stream, Partnership, Mixture and Alligation, Simple Interest, Problems on Trains etc. These kind of questions has been seen in SBI PO Exams. We would like to recommend you to practice miscellaneous question for sbi po pre and ibps po at Smartkeeda with detailed solution at Free cost. You can download miscellaneous questions pdf with explanation for ibps po 2019.

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