Important for :

1

D

Take LCM{2, 3} = 6

In 6 hours, cartoonist can make = | 6 | = 3 cartoons |

2 |

In 6 hours, helper can make = | 6 | = 2 cartoons |

3 |

In 6 hours, both can make = 5 cartoons

For making 50 cartoons they need 10 such periods.

So, total time taken by both to make 50 cartoons = 10 × 6 = 60 hours.

The target gets completed by 18 April 12 am.

Hence, option D is correct.

Cartoons made by Cartoonist in 1 day = | 24 | = 12 cartoons |

2 |

Cartoons made by helper in 1 day = | 24 | = 8 cartoons |

3 |

Cartoons made by Cartoonist in 2 days = 24 cartoons

Cartoons made by helper in 2 days = 16 cartoons

Total cartoons made in 2 days = 24 + 16 = 40 cartoons

Remaining cartoons = 50 – 40 = 10

In the next 12 hours, Cartoonist makes

= | 12 | = 6 cartoons and helper makes = | 12 | = 4 cartoons |

2 | 3 |

So the target is completed in = 48 + 12 = 60 hours

The target gets completed by 18 April 12 am.

2

3

D

Capacity of one tank is = LCM{12, 20, 24} = 120 unitsIn 1 hour, capacity of water that T

= | 120 | = 10 units |

12 |

In 1 hour, capacity of water that T

= | 120 | = 6 units |

20 |

In 1 hour, capacity of water that T

= | 120 | = 5 units |

24 |

In the first hour T

So, in the set of two hours = T

→ 10 + (6 + 5) = 21 units

In 10 hours, capacity that gets filled = 21 × 5 = 105 units

Remaining capacity = 120 – 105 = 15 units

In the next hour, it’s T1’s turn, it fills 10 units/hr. So,

→ 15 – 10 = 5 units

Now, it’s T

= | 5 × 60 | = 27.27 mins |

11 |

Total time to fill the tank = 10 + 1 + 27.27 mins = 11 hours 27.27 mins

Hence, option D is correct.

4

B

Let the present age of Seema be x yearsSweeta’s present age = x – 10

When Seema was 14 years, mother was 34 years. So, when Seema is x years, mother will be = 34 – 14 + x

Mother’s present age = 20 + x

According to the question,

x + 20 + 6 | = | 2 |

x – 10 + 6 | 1 |

x + 26 | = | 2 |

x – 4 | 1 |

x = 34 years

Seema’s age = 34 years

Sweeta’s age = 24 years

Mother’s present age = 54 years

Average = | 34 + 24 + 54 | = 37.33 years |

3 |

After 2 years, Seema’s age = 36 years, Sweeta’s age = 26 years, Mother’s age = 56 years

Average after 2 years,

Avg = | 36 + 26 + 56 | = 39.33 years |

3 |

Hence, option B is correct.

5

C

Let the investment of Sumit = Rs. xInvestment of Sachin = Rs. | x |

3 |

Time for which Sumit invested = | 2 | = | 1 | year |

4 | 2 |

Time for which Sachin invested = 2 years

Profit ratio, Sachin : Sumit = | ( | x | ) | (2) : (x) | ( | 1 | ) |

3 | 2 |

Profit ratio = 4 : 3

Share of Sachin = total profit × | 4 |

7 |

Let total Profit be P

7 × 13440 | = P |

4 |

P = Rs. 23520

Hence, option C is correct.

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Here are some important examples regarding

A. 17 April 12 am

B. 18 April 12 pmC. 19 April 2 am

D. 18 April 12 am

E. 17 April 12 pm

Take LCM{2, 3} = 6

In 6 hours, cartoonist can make = | 6 | = 3 cartoons |

2 |

In 6 hours, helper can make = | 6 | = 2 cartoons |

3 |

In 6 hours, both can make = 5 cartoons

For making 50 cartoons they need 10 such periods.

So, total time taken by both to make 50 cartoons = 10 × 6 = 60 hours.

The target gets completed by 18 April 12 am.

Hence, option D is correct.

Cartoons made by Cartoonist in 1 day = | 24 | = 12 cartoons |

2 |

Cartoons made by helper in 1 day = | 24 | = 8 cartoons |

3 |

Cartoons made by Cartoonist in 2 days = 24 cartoons

Cartoons made by helper in 2 days = 16 cartoons

Total cartoons made in 2 days = 24 + 16 = 40 cartoons

Remaining cartoons = 50 – 40 = 10

In the next 12 hours, Cartoonist makes

= | 12 | = 6 cartoons and helper makes = | 12 | = 4 cartoons |

2 | 3 |

So the target is completed in = 48 + 12 = 60 hours

The target gets completed by 18 April 12 am.

A. Rs. 24520

B. Rs. 25440

C. Rs. 23520

D. Rs. 32420

E. Rs. 22520

Let the investment of Sumit = Rs. x

Investment of Sachin = Rs. | x |

3 |

Time for which Sumit invested = | 2 | = | 1 | year |

4 | 2 |

Time for which Sachin invested = 2 years

Profit ratio, Sachin : Sumit = | ( | x | ) | (2) : (x) | ( | 1 | ) |

3 | 2 |

Profit ratio = 4 : 3

Share of Sachin = total profit × | 4 |

7 |

Let total Profit be P

7 × 13440 | = P |

4 |

P = Rs. 23520

Hence, option C is correct.

A. 8 sec

B. 6 sec

C. 7 sec

D. 9 sec

E. 10 sec

When the trains run in opposite direction, the relative speed is double the relative speed when the trains run in the same direction.

They take 20 seconds to cross when in the same direction , so the time taken to cross when in opposite direction will be half of the time taken when in the same direction which will be equal to 20/2 = 10 secs

Hence option E is correct.

Total distance covered = 300 + 320 = 620m

When they run in the same direction, relative speed (p – q) is given by

p – q = | 620 | = 31 .......(i) |

20 |

When they run in the opposite direction, relative speed (p + q) is given by

p + q = | 620 | .......(ii) |

x |

Given that,

p + q = 2 × 31 = 62 m/sec

by putting values in (2), we get

x = | 620 | = 10 sec |

62 |

Time taken by the trains to cross each other when in opposite direction is 10 seconds.

Hence, option E is correct.

A. 70

B. 60

C. 80

D. 90

E. 50

The ratio of speed of Rani and that of Sonia is 4 : 9

When the escalator is turned off, let the number of steps visible be x.

Given that, Rani takes 20 steps to reach the top and Sonia takes 30 steps to reach the top. The ratio of speed of Rani to that of escalator

= | 20 | ...........(i) |

x – 20 |

The ratio of speed of Sonia to that of escalator

= | 30 | ...........(ii) |

x – 30 |

(i)/(ii)

The ratio of speed of Rani to that of Sonia

→ | 20 | = | |

x – 20 | 4 | ||

30 | 9 | ||

x – 30 |

→ | 20 (x – 30) | = | 4 |

30 (x – 20) | 9 |

→ 3x – 90 = 2x – 40

→ x = 50

Hence, option E is correct.

All the above questions through, you must make sure about arithmetic miscellaneous questions which have been seen in the last few years. We hope this above *Quantitative Aptitude for RBI assistant 2020* will clear your all doubts regarding bank clerk exams.

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Team Smartkeeda