Important for :

1

[17.98 ÷ 6.2] + [1.25 ÷ 0.5] – [0.96 ÷ 0.8] = ?

A

⇒ ? = | 17.98 | + | 1.25 | – | 0.96 |

6.2 | 0.5 | 0.8 |

⇒ ? = 2.9 + 2.5 – 1.2

⇒ ? = 5.4 – 1.2

∴ ? = 4.2

Hence, option A is correct.

2

A

Let the present ages of Sitamma and Radha are x and y years respectively.We have,

10 years ago age of Sitamma was 3 times the age of Radha.

i.e. (x – 10) = 3 (y – 10)

⇒ 3y – x = 20 .............(i)

And,

10 years later age of Sitamma will be twice the age of Radha.

i.e. (x + 10) = 2 (y + 10)

⇒ x – 2y = 10 .............(ii)

Adding eqn. (i) and (ii), we get

y = 30 years

Put y = 30 years in eqn. (i), we get

⇒ 3 × 30 – x = 20

⇒ 90 – 20 = x

∴ x = 70 years

Required Ration = x : y

= 70 : 30 or, 7 : 3

Hence, option A is correct.

3

1 | 2 | + 2 | 1 | + 2 | 2 | – 4 | 1 | = ? |

3 | 3 | 3 | 2 |

C

1 | 2 | + 2 | 1 | + 2 | 2 | – 4 | 1 | = ? |

3 | 3 | 3 | 2 |

⇒ ? = | 5 | + | 7 | + | 8 | – | 9 |

3 | 3 | 3 | 2 |

⇒ ? = | 5 + 7 + 8 | – | 9 |

3 | 12 |

⇒ ? = | 20 | – | 9 |

3 | 12 |

⇒ ? = | 40 – 27 |

6 |

⇒ ? = | 13 |

6 |

∴ ? = 2 | 1 |

6 |

Hence, option C is correct.

4

67. 436 × 17 × 3 ÷ 32 = ?

» Explain it

∴ ? = 694.876

Hence, option B is correct.

B

⇒ ? = | 436 × 17 × 3 |

32 |

⇒ ? = | 22236 |

32 |

∴ ? = 694.876

Hence, option B is correct.

5

D

Average attendance for first three days = 325Total attendance for first three days = 325 × 3 = 975

Average attendance for first four days = 320

Total attendance for first four days = 1280

Attendance on fourth day = 1280 – 975 = 305

Hence, option D is correct.