# Simplification with their Types and Examples in the form of Quiz, PDF for Bank and Insurance Exams

Today, we talk about ‘Simplification’, candidates those who are preparing for banks and competitive exams must have to know the simple tricks to solve the simplification questions that’s why we discuss here about :-
• Simplification
• Types of simplification
• Various Simplification Tricks
• Quizzes
Candidates who are preparing for the competitive exams must know that Simplification topic is one of the important topics because mainly 5 – 10 questions consist of this topic.  But students don’t need to worry about that Smartkeeda will be always with you, we know what type of tricks & techniques students want to solve the questions.

What is Simplification?

Simplification means finding the solution from the complex calculation, simplification topic covers a huge part of the exam. So in this article you can also know how to improve your score in exams like SBI Clerk, RBI Assistant, SBI PO,IBPS Clerk, IBPS PO, SSC SGL, SSC CHSL .

Now here we discuss about the type of Simplification,

Types of Simplification :-

Simplification questions will be ask in two ways, so you all have to know the both types,
1. The first one is ‘Finding the missing number’.
2. The second type of simplification question will be ‘the relation between the numbers and simplify the numbers using the rules of simplification’.
Let’s we take the examples with proper explanation:

Directions: Study the following questions carefully and choose the right answer:

Q. 1:
 4 × 2 × ? = 1008 7 3
A. 2688
B. 2604
C. 2667
D. 2646
E. None of these
Ans. D
 ? = 1008 × 7 × 3 = 2646 4 2
Hence, option D is correct.

Q. 2:
(? – 968) ÷ 79 × 4 = 512
A. 11080
B. 10190
C. 11075
D. 10185
E. None of these
Ans. A
 (? – 968) × 4 = 512 79
 ⇒ ? = 512 × 79 + 968 = 11080 4
Hence, option A is correct.

Q. 3:
(?)3 × (55) ÷ 225 = 3000
A. 6
B. 8
C. 5
D. 9
E. None of these
Ans. A
(?)3 × (55) ÷ 225 = 3000
(?)3 × (55) = 3000 × 225 = 675000
(?)3 = 675000 ÷ (55) = 216
? = 6
Hence, option A is correct.

Q.4:
– 948 + 147 – ? = – 1432
A. 683
B. 631
C. 647
D. 676
E. None of these
Ans. B
– 948 + 147 – ? = – 1432
– 801 – ? = – 1432
? = 631
Hence, option B is correct.

Q.5:
94736 + 43693 + 25638 = ?
A. 160546
B. 164076
C. 165046
D. 160467
E. None of these
Ans. E
94736 + 43693 + 25638 = 164067
Hence, option E is correct.

Directions: Study the following questions carefully and choose the right answer:

Q.1:
132 + 168 ÷ 24 – 33 + 107 = (?)2

A. 2
B. 256
C. 16
D. 4
E. None of these

Ans. D

 (?)2 = 132 + 168 ÷ 24 – 33 + 107
 (?)2 = 169 + 7 – 27 + 107
 (?)2 = 256 = 16 = (4)2
∴  ? = 4
Hence, option D is correct.

Q.2:
 9.6 × 3.6 + 7.2 + 10.8 of 1 – 1 = ? 18 10

A. 42.26
B. 24.26
C. 40
D. 45.26
E. None of these

Ans. A
 ? = 9.6 × 3.6 + 7.2 + 10.8 of 1 – 1 18 10
= 34.56 + 7.2 + 0.6 – 0.1  = 42.26
Hence, option A is correct.

Q.3:

 21 ÷ 9 × 5 ÷ 10 = ? 25 20 12 17
A. 2.12
B. 5.42
C. 6.66
D. 1.32
E. None of these
Ans. D
 ? = 21 ÷ 9 × 5 ÷ 10 25 20 12 17
 = 21 × 20 × 5 × 17 25 9 12 10
 = 119 = 1.32 90
Hence, option D is correct.

Q.4:
1827 ÷ 29 ÷ 7 + 567 ÷ 21 = ?
A. 7
B. 4
C. 6
D. 9
E. 36
Ans. C
 ? = 1827 ÷ 29 ÷ 7 + 567 ÷ 21
 1827 × 1 × 1 + 27 29 7
 = 9 + 27 = 36 = 6
Hence, option C is correct.

Q.5:
6561 ÷ 9 ÷ 81 = ?

A. 1
B. 18
C. 4
D. 81
E. 9
Ans. E
? = 6561 ÷ 9 ÷ 81
 = 6561 × 1 × 1 = 9 9 81
Hence, option E is correct.

Now, the question is how to simply solve the questions every student want to know some essential tricks and techniques.
So here are some easiest methods which everybody has to keep in method before solving the equation:

Simplification Tricks :-
• Understand the Bodmas Rule.
•  If an expression contains brackets the expression within the brackets should be simplified first.
• Learn the Concept of Digital Sum
• Memorize the Reciprocals.
• Quickly find cube roots and square root of a large number.
Here are some examples through which you can apply the above tips:-

Directions: Study the following questions carefully and choose the right answer:

Q.1:
 17 1 + 21 1 = 33 1 % of ? 3 2 3
A. 116.5
B. 104.5
C. 112.33
D. 118.33
None of these
Ans. A
 17 1 + 21 1 = 33 1 % of ? 3 2 3
 52 + 43 = 1 of ? 3 2 3
 104 + 129 = 1 of ? 6 3
 ? = 233 = 116.5 2
Hence, option A is correct.

Q.2:
 18 × 8 + 10% of 624 15 = 4 ?
A. 16
B. 18
C. 22
D.24
D. None of these
Ans. B
 18 × 8 + 10% of 624 15 = 4 ?
 6 × 8 + 62.4 = ? × 4 5
9.6 + 62.4 = 72 = 4 × ?
? = 18
Hence, option B is correct.

Q.3:
√1024  × 40 + 202 + 0.5% of 9600 + 469 =  ?3

A. 23
B. 13
C. 17
D. 19
E. None of these
Ans. B
√1024  × 40 + 202 + 0.5% of 9600 + 469 =  ?3
32 × 40 + 400 + 48 + 469 = ?3
1280 + 448 + 469 = ?3
2197 = ?3
? = 13
Hence, option B is correct.

Q.4:
 4 3 % of 6500 + 3 2 % of 3500 = ? 5 7
A. 424
B. 414
C. 418
D. 404
E. None of these
Ans. B
 4 3 % of 6500 + 3 2 % of 3500 = ? 5 7
 23 × 6500 + 23 × 3500 = ? 500 700
? = 23 × (13 + 5)
? = 23 × 18 = 414
Hence, option B is correct.

Q.5
44 + 54 + 10% of 8000 = ?2

A. 1681
B. 16812
C. 41
D. 43
E. None of these
Ans. C
44 + 54 + 10% of 8000 = ?2
256 + 625 + 800 = 1681 = ?2
? = 41
Hence, option C is correct.

Q.1:
(26 × 14 – 7) ÷ 21 = ?

A. 11
B. 25
C. 33
D. 46
E. None of these
Ans. E
(26 × 14 – 7) ÷ 21
 ? = 364 – 7 21
 ? = 357 = 17 21
Hence, option E is correct.

Q.2:
√2116 + √1296 – √1681 = ?

A. 12
B. 33
C. 46
D. 24
E. None of these
Ans. E
√2116 + √1296 – √1681 = ?
462 = 2116,  362 = 1296,  412 = 1681
? = √2116 + √1296 – √1681
? = 46 + 36 – 41
? = 41
Hence, option E is correct.

Q.3:
(33)2 – (35)2 + (17)2 = ?

A. 121
B. 138
C. 153
D. 165
E. None of these
Ans. C
(33)2 – (35)2 + (17)2 = ?
? = 332 – 352 + 172
? = 1089 – 1225 + 289
? = 153
Hence, option C is correct.

Q.4:
1496 ÷ 34 = ? + 39
A. 3
B. 5
C. 9
D. 15
E. None of these
Ans. B
1496 ÷ 34 = ? + 39
? = 1496 ÷ 34 – 39
? = 44 – 39
? = 5
Hence, option B is correct.

Q.5:
142 – 5121/3  + 7841/2 = ?

216
228
238
249
None of these
Ans. A
142 – 5121/3 + 7841/2 = ?
142 = 196, 83 = 512, 282 = 784
? = 196 – 8 + 28
? = 216
Hence, option A is correct.

Take a look at the rules of simplification,

Rules of Simplification:

 V Vinculum B Remove Brackets - in the order ( ) , { }, [ ] O Of D Division M Multiplication A Addition S Subtraction

At a Glance

In the above article we have discussed about Simplification,  friends simplification covers a large part of  Quantitative Aptitude Section that’s the reason we have discussed simplification all topics clearly.