Practice Quantitative Aptitude for RBI Assistant 2023 with PDF, Number Series, Data Interpretation, Quadratic Equation, Simplification and Approximation etc.
By Smartkeeda
25 Dec 2019
Hi Aspirants,
In this Article, we will cover up the detailed syllabus with important questions of Quantitative Aptitude for the RBI Assistant Exam 2023 to boost up your chances to get selected for RBI Assistant.
This is predicted pattern of Quantitative aptitude which have high chances to be appeared in RBI Assistant Exam 2023.
So we at Smartkeeda helps you to reach your desired post of RBI Assistant by providing strategies and important questions with solution to minimize any losses in RBI Assistant 2023. Here is an detailed topic of Quantitative Aptitude syllabus and selected important questions for practice which can be asked in RBI Assistant Exam 2023.
The RBI Assistant syllabus for Quantitative Aptitude is described as below:
In this Article, we will cover up the detailed syllabus with important questions of Quantitative Aptitude for the RBI Assistant Exam 2023 to boost up your chances to get selected for RBI Assistant.
This is predicted pattern of Quantitative aptitude which have high chances to be appeared in RBI Assistant Exam 2023.
So we at Smartkeeda helps you to reach your desired post of RBI Assistant by providing strategies and important questions with solution to minimize any losses in RBI Assistant 2023. Here is an detailed topic of Quantitative Aptitude syllabus and selected important questions for practice which can be asked in RBI Assistant Exam 2023.
The RBI Assistant syllabus for Quantitative Aptitude is described as below:
- Number Series - 5
- Data Interpretation - 5
- Simplification/Approximation - 10
- Quadratic Equations – 5
- Miscellaneous – 10
Let’s start to understand each and every topic in detail with the help of examples of Quantitative Aptitude for RBI Assistant Exam 2023.
Number Series for RBI Assistant
Basically number series are of two types, one is “Finding the next term” or you can say “Missing term Number Series” and other one is to “Find the Wrong Term”. But we will discuss only “Missing term Series” in examples as you know that in prelims, Missing term Series have high chances to appear, we will also suggest you to practice wrong term series as well.
If you are worrying about "What is Number Series?", So in a simple word we can jsut say it is a proper sequence of numbers to form out missing numbers. If you didn't understand yet, you will get to know with the help of examples easily.
In the questions of Number Series we have to find out the patternwhich help us find the missing term in the series as you can see below:
Directions: What should come in place of the Question mark (?) in the following question?
Q.1. 2 3 10 39 172 ?
A. 340
B. 885
C. 880
D. 251
E. None of these
Solution:
| Series Pattern | Given Series | |
| 2 | 2 | |
| 2 × 1 + 1 = 3 | 3 | |
| 3 × 2 + 4 = 10 | 10 | |
| 10 × 3 + 9 = 39 | 39 | |
| 39 × 4 + 16 = 172 | 172 | |
| 172 × 5 + 25 = 885 | 885 | ? |
Hence, option (B) is correct.
Q.2. 9827 9706 9606 9525 9461 ?
A. 9520
B. 9421
C. 9412
D. 9425
E. None of these
Solution:
| Series Pattern | Given Series | |
| 9827 | 9827 | |
| 9827 – 121 = 9706 | 9706 | |
| 9706 – 100 = 9606 | 9606 | |
| 9606 – 81 = 9525 | 9525 | |
| 9525 – 64 = 9461 | 9461 | |
| 9461 – 49 = 9412 | 9412 | ? |
Hence, option (C) is correct.
Q.3. 1240, 1140, 1019, 875, 706, ?
A. 428
B. 439
C. 510
D. 498
E. None of these
Solution:
| Series Pattern | Given Series | |
| 1240 | 1240 | |
| 1240 – 102 = 1140 | 1140 | |
| 1140 – 112 = 1019 | 1019 | |
| 1019 – 122 = 875 | 875 | |
| 855 – 132 = 706 | 706 | |
| 706 – 142 = 510 | 510 | ? |
Hence, option (C) is correct.
Q.4. 320 160 240 600 2100 ?
A. 8350
B. 8850
C. 9450
D. 9650
E. None of these
Solution:
| Series Pattern | Given Series | |
| 320 | 320 | |
| 320 × 1/2 = 160 | 160 | |
| 160 × 3/2 = 240 | 240 | |
| 240 × 5/2 = 600 | 600 | |
| 600 × 7/2 = 2100 | 2100 | |
| 2100 × 9/2 = 9450 | 9450 | ? |
Hence, option (C) is correct.
Q.5. 13 15 21 33 53 ?
A. 81
B. 82
C. 83
D. 92
E. 102
Solution:
| Series Pattern | Given Series | |
| 13 | 13 | |
| 13 + 12 + 1 | 15 | |
| 15 + 22 + 2 | 21 | |
| 21 + 32 + 3 | 33 | |
| 33 + 42 + 4 | 53 | |
| 53 + 52 + 5 | 83 | ? |
Hence, option (C) is correct.
Data Interpretation for RBI Assistant
Data Interpretation or DI can be described as the implementation of some process by which the given data is reviewed for the reason of arriving at an interference. Term Interpreting can described as in which given data requires an analysation to interpretate the information to give the answers of the questions which is asked for Data Interpretation. Generally there are four to five types of formation of DIs like Table Chart, Pie Chart, Line Chart, Caselet DI and Mixed Etc. In RBI Assistant, the Data Interpretation you will get one summary with 5 questions as you can see below in the example of Table Chart.
Directions : Study the following table chart carefully and answer the questions given beside.
The following table represents the number of employees in five different organisations in 2012, 2013, 2014 and 2015.
| Organization | 2012 | 2013 | 2014 | 2015 |
| P | 5000 | 8800 | 3600 | 6200 |
| Q | 4800 | 10200 | 12100 | 8300 |
| R | 5500 | 6500 | 8800 | 4250 |
| S | 8000 | 4800 | 9000 | 5650 |
| T | 7600 | 7200 | 8400 | 3880 |
Q.1. Find the Total number of employees in all the organisations in 2013.
A. 35450
B. 32200
C. 37500
D. 36560
E. None of these
Solution:
Total number of employees in all the organisations in 2013
= 8800 + 10200 + 6500 + 4800 + 7200
= 37500
Hence, option C is correct.
Q.2. Number of employees in organization P in 2013 and 2014 together is what percent of number of employees in organization R in 2014 and 2015 together?
A. 80.01%
B. 95.01%
C. 91.01%
D. 88.52%
E. None of these
Solution:
Number of employees in organization P in 2013 and 2014 together = 8800 + 3600 = 12400
Number of employees in organization R in 2014 and 2015 together = 8800 + 4250 = 13050
| Reqd. % = | 12400 | × 100 = 95.01% |
| 13050 |
Hence, option B is correct.
Q.3. Number of employees in organization Q in 2012 is 125% of number of employees in organization Q in 2011. Find the number of employees in organization Q in 2011.
A. 4020
B. 3840
C. 3248
D. 3008
E. None of these
Solution:
Let the number of employees in organization Q in 2011 = y
Q.3. Number of employees in organization Q in 2012 is 125% of number of employees in organization Q in 2011. Find the number of employees in organization Q in 2011.
A. 4020
B. 3840
C. 3248
D. 3008
E. None of these
Solution:
Let the number of employees in organization Q in 2011 = y
| y × | 125 | = 4800 |
| 100 |
⇒ y = 3840
Hence, option B is correct.
Q.4. Find the difference between number of employees in organization S in all the years together and number of employees in 2014 in all the organizations together.
A. 14450
B. 12500
C. 11200
D. 10050
E. None of these
Solution:
Number of employees in organization S in all the years together
= 8000 + 4800 + 9000 + 5650 = 27450
Number of employees in 2014 in all the organizations together
= 3600 + 12100 + 8800 + 9000 + 8400 = 41900
Required difference = 41900 – 27450 = 14450
Hence, option A is correct.
Q.5. Find the respective ratio of number of employees in 2012 in organizations S and T together to that in 2014 in the same organizations.
A. 27 : 25
B. 29 : 26
C. 25 : 27
D. 26 : 29
E. None of these
Solution:
A. 27 : 25
B. 29 : 26
C. 25 : 27
D. 26 : 29
E. None of these
Solution:
Number of employees in 2012 in organizations S and T together = 8000 + 7600 = 15600
Number of employees in 2014 in organizations S and T together = 9000 + 8400 = 17400
Required ratio = 15600 : 17400 = 26 : 29
Hence, option D is correct.
Simplification and Approximation for RBI Assistant
Simplification and Apprximation is a very easy topic and results in high marks scoring in prelims exams like RBI Assistant. To solve such Simplification and Approximation questions, aspirant has to follow VBODMAS rule which stands for Vinculum Bar (-), addition (+), subtraction (–), multiplication (×), division (÷), root (√), and brackets, etc systematically. Let discuss VBODMAS rule to make this intro clearer.
VBODMAS rule gives the correct order in which various operations regarding simplification are to be performed, so as to find out the values of given expressions in simple ways. Let us see what these letters mean.
VBODMAS rule gives the correct order in which various operations regarding simplification are to be performed, so as to find out the values of given expressions in simple ways. Let us see what these letters mean.
- V = Vinculum Bar
- B = Brackets,
- Order of removing brackets
- I: Vinculum Brackets (Bar Brackets) ‘–’
- II: Small Brackets (Circular Brackets) ‘( )’
- III: Middle Brackets (Curly Brackets) ‘{ }’
- IV: Square Brackets (Big Brackets) ‘[ ]’
- O = Of
- D = Division (÷)
- M = Multiplication (×)
- A = Addition (+)
- S = Subtraction (–)
Order of above mentioned operations is as same as the order of letters in the ‘VBODMAS’ from the left to right as
V → B → O → D → M → A → S
Directions: What approximate value should come in place of question mark.
Q.1. 15 × 18 + 110% of 850 + 870.26 ÷ 15 + 12 = ?
A. 1270
B. 1275
C. 1280
D. 1285
E. 1289
Solution:
15 × 18 + 110% of 850 + 870.26 ÷ 15 + 12 = ?
270 + 85 × 11 + 58 + 12 = ?
270 + 935 + 70 = 1275
Hence, option B is correct.
Q.2. 840.951/2 + 17.49 × 28 – 40961/3 = ?
A. 495
B. 475
C. 509
D. 515
E. 503
Solution:
840.951/2 + 17.49 × 28 – 40961/3 = ?
? ≈ √5041 – √4624 + ∛2197 – ∛1330
? = 71 – 68 + 13 – 11
? = 84 – 79 = 5
Hence, option A is correct.
Q.4. 5376 ÷ 24 × 13 – 703 = ?2
A. 57
B. 47
C. 53
D. 43
E. None of these
Solution:
?2 = 5376 ÷ 24 × 13 – 703
E. None of these
Solution:
Hence, option B is correct.
V → B → O → D → M → A → S
Directions: What approximate value should come in place of question mark.
Q.1. 15 × 18 + 110% of 850 + 870.26 ÷ 15 + 12 = ?
A. 1270
B. 1275
C. 1280
D. 1285
E. 1289
Solution:
15 × 18 + 110% of 850 + 870.26 ÷ 15 + 12 = ?
| 270 + 850 × | 110 | + | 870 | + 12 = ? |
| 100 | 15 |
270 + 935 + 70 = 1275
Hence, option B is correct.
Q.2. 840.951/2 + 17.49 × 28 – 40961/3 = ?
A. 495
B. 475
C. 509
D. 515
E. 503
Solution:
840.951/2 + 17.49 × 28 – 40961/3 = ?
8411/2 + 17.5 × 28 – 16 = ?
29 + 490 – 16 = ?
? = 519 – 16
? = 503
Hence, option E is correct.
Q.3. √5040 – √4625 = ? – ∛2198 + ∛1330
A. 5
B. 25
C. 16
D. 12
E. 2
Solution:
? = √5040 – √4625 + ∛2198 – ∛1330
Q.3. √5040 – √4625 = ? – ∛2198 + ∛1330
A. 5
B. 25
C. 16
D. 12
E. 2
Solution:
? = √5040 – √4625 + ∛2198 – ∛1330
? = 71 – 68 + 13 – 11
? = 84 – 79 = 5
Hence, option A is correct.
Q.4. 5376 ÷ 24 × 13 – 703 = ?2
A. 57
B. 47
C. 53
D. 43
E. None of these
Solution:
?2 = 5376 ÷ 24 × 13 – 703
?2 = 224 × 13 – 703
?2 = 2912 – 703 = 2209
? = √2209 = 47
Hence, option B is correct.
| Q.5. 7 | 2 | + 9 | 7 | + 11 | 3 | – 6 | 1 | = ? |
| 3 | 12 | 4 | 2 |
| A. 25 | 3 |
| 5 |
| B. 22 | 1 |
| 2 |
| C. 23 | 3 |
| 4 |
| D. 22 | 3 |
| 5 |
E. None of these
Solution:
| 7 | 2 | + 9 | 7 | + 11 | 3 | – 6 | 1 | = ? |
| 3 | 12 | 4 | 2 |
| ? = (7 + 9 + 11 – 6) + | ( | 2 | + | 7 | + | 3 | – | 1 | ) |
| 3 | 12 | 4 | 2 |
| ? = 21 + | 8 + 7 + 9 – 6 | = 21 + | 18 | |
| 12 | 12 |
| ? = 21 + | 3 | = 22 + | 1 | = 22 | 1 | |
| 2 | 2 | 2 |
Hence, option B is correct.
Quadratic Equation for RBI Assistant
Quadratic Equation is also very easy topic among prelims exams like RBI Assistant, you can solve Quadratic Equation questions in just 35 to 55 seconds. Which is quite efficient to save time in your RBI Assistant Exams. Quadratic Equation can be described as a equation in which the highest exponent on variable is 2. and the writing standard of this equation is ax2 + bx + c=0. So what you need to do in Quadratic Equation you must be given two equations in the form of x and y and you need to find the root values of x and y.
Directions: In each of these questions, two equations (I) and (II) are given.You have to solve both the equations and give answer.
Q.1. I. x3 – 4913 = 0 II. y2 – 361 = 0
A. if x < y
B. if x = y or relationship between x and y can't be established
C. if x > y
D. if x ≥ y
E. if x ≤ y
Solution:
or, x3 = 4913
x = 17
or, y = ± 19
While comparing the values of x and y, one root value of y lies between the root values of x
Hence, option D is correct.
Q.2. I. x2 = 361 II. y3 = 7269 + 731
A. if x < y
B. if x > y
C. if x ≥ y
D. if x ≤ y
E. if x = y or relationship between x and y can't be established
Solution:
I. x2 = 361
x = ± 19
II. y3 = 7269 + 731
y3 = 8000
y = 20
x < y
Hence, option A is correct.
Q.3. I. 15x2 + x – 6 = 0 II. 5y2 – 23y + 12 = 0
A. if x > y
B. if x ≤ y
C. if x ≥ y
D. if x < y
E. if x = y or relationship between x and y can't be established
Solution:
I. 15x2 + x – 6 = 0
15x2 + 10x – 9x – 6 = 0
5x (3x + 2) – 3 (3x + 2) = 0
(5x – 3) (3x + 2) = 0
II. 5y2 – 23y + 12 = 0
5y2 – 20y – 3y + 12 = 0
5y (y – 4) – 3 (y – 4) = 0
(y – 4) (5y – 3) = 0
x ≤ y
Hence, option B is correct.
Q.4. I. x2 + (343)1/3 = 56 II. (y)4/3 × (y)5/3 – 295 = 217
A. if x > y
B. if x ≤ y
C. if x ≥ y
D. if x < y
E. if x = y or relationship between x and y can't be established
Solution:
I. x2 + (343)1/3 = 56
x2 + 7 = 56
x2 = 49
∴ x = √49 = ±7
Here, x < y
Hence, option D is correct.
Q.5. I. 5x + 4y = 8 II. 3x + 2y = 4
A. if x > y
B. if x ≤ y
C. if x ≥ y
D. if x < y
E. if x = y or relationship between x and y can't be established
Solution:
5x + 4y = 8 .......(i) × 3
3x + 2y = 4 .......(ii) × 5
Directions: In each of these questions, two equations (I) and (II) are given.You have to solve both the equations and give answer.
Q.1. I. x3 – 4913 = 0 II. y2 – 361 = 0
A. if x < y
B. if x = y or relationship between x and y can't be established
C. if x > y
D. if x ≥ y
E. if x ≤ y
Solution:
I. x3 – 4913 = 0
or, x3 = 4913
x = 17
II. y2 = 361
or, y = ± 19
While comparing the values of x and y, one root value of y lies between the root values of x
Hence, option D is correct.
Q.2. I. x2 = 361 II. y3 = 7269 + 731
A. if x < y
B. if x > y
C. if x ≥ y
D. if x ≤ y
E. if x = y or relationship between x and y can't be established
Solution:
I. x2 = 361
x = ± 19
II. y3 = 7269 + 731
y3 = 8000
y = 20
x < y
Hence, option A is correct.
Q.3. I. 15x2 + x – 6 = 0 II. 5y2 – 23y + 12 = 0
A. if x > y
B. if x ≤ y
C. if x ≥ y
D. if x < y
E. if x = y or relationship between x and y can't be established
Solution:
I. 15x2 + x – 6 = 0
15x2 + 10x – 9x – 6 = 0
5x (3x + 2) – 3 (3x + 2) = 0
(5x – 3) (3x + 2) = 0
| x = | 3 | , – | 2 |
| 5 | 3 |
II. 5y2 – 23y + 12 = 0
5y2 – 20y – 3y + 12 = 0
5y (y – 4) – 3 (y – 4) = 0
(y – 4) (5y – 3) = 0
| y = 4, | 3 |
| 5 |
x ≤ y
Hence, option B is correct.
Q.4. I. x2 + (343)1/3 = 56 II. (y)4/3 × (y)5/3 – 295 = 217
A. if x > y
B. if x ≤ y
C. if x ≥ y
D. if x < y
E. if x = y or relationship between x and y can't be established
Solution:
I. x2 + (343)1/3 = 56
x2 + 7 = 56
x2 = 49
∴ x = √49 = ±7
II. (y)4/3 × (y)5/3 – 295 = 217
(y)3 = 217 + 295
(y)3 = 512 = (8)3
or, y = 8
(y)3 = 217 + 295
(y)3 = 512 = (8)3
or, y = 8
Here, x < y
Hence, option D is correct.
Q.5. I. 5x + 4y = 8 II. 3x + 2y = 4
A. if x > y
B. if x ≤ y
C. if x ≥ y
D. if x < y
E. if x = y or relationship between x and y can't be established
Solution:
5x + 4y = 8 .......(i) × 3
3x + 2y = 4 .......(ii) × 5
15x + 12y = 24 .......(iii)
15x + 10y = 20 .......(iv)
– – –
2y = 4
y = 2
Putting the value of y in (i), we get
5x + 8 = 8
5x = 0
∴ x = 0
Here, x < y
Hence, option D is correct.
15x + 10y = 20 .......(iv)
– – –
2y = 4
y = 2
Putting the value of y in (i), we get
5x + 8 = 8
5x = 0
∴ x = 0
Here, x < y
Hence, option D is correct.
Miscellaneous for RBI Assistant
Miscellaneous Questions are consist of different topics like time and distance, percentage, probability, boats and stream, average, time and work, problems on numbers, ratio & proportion, permutation and combination etc. In which the important topics such as time and distance, boats and stream, time and work, percentage, profit and loss etc. in which we have given some selected important question to practice to achieve high score in RBI Assistant 2023.
Directions : Read the following questions carefully and choose the right answer.
Q.1. A man can reach a certain place in 40 hours. If he reduces his speed by 1/15th, he goes 5 km less in that time. Find the total distance covered by him.
A. 60 km.
B. 85 km.
C. 75 km.
D. 52 km.
E. None of these
Solution:
Let Distance = D km, Speed = S km/h
After reducing speed,
After solving equation 1 and 2
14 Distance = 15 (Distance – 5)
14 Distance = 15 Distance – 75
Distance = 75 km.
Hence, option C is correct.
Q.2. In a college Anjana scored 80 marks out of 150 in History and 95 marks out of 120 in English. If she wants to score 70% marks in 3 subjects, find the minimum marks she should score in Geography out of 100.
A. 70
B. 55
C. 76
D. 85
E. None of these
Solution:
Total maximum marks = 100 + 120 + 150 = 370
Total marks in History and English = 95 + 80 = 175
Total marks required by her to get 70% = 370 × 70% = 259
So, she needs 259 – 175 = 84 marks to score 70%.
Hence, option E is correct.
Q.3. There are 15 boys and 10 girls in a class. If three students are selected at random, what is the probability that 1 girl and 2 boys are selected?
A. 1/10
B. 1/2
C. 21/46
D. 7/41
E. None of these
Solution:
Hence, option C is correct.
Q.4. Amit goes Mumbai to Kolkata by sea route. The speed of the boat in still water is 60 km/h and speed of the current is 15 km/h. After reaching Kolkata he stayed there for 20 minutes and after that come back by same boat. The time taken by him in this journey is 19 hours 32 minutes, find the distance travel by him in one side.
A. 450 km
B. 360 km
C. 540 km
D. 600 km
E. None of these
Solution:
Time taken by him in travelling = 19 hours 32 minutes – 20 minutes
x = 540 km
Hence, option C is correct.
Q.5. Two trains 165 m and 135 m long run at the speed of 70 km/hr and 38 km/hr respectively in opposite directions on parallel tracks. The time (in seconds) which they take to cross each other is:
A. 4 sec
B. 5 sec
C. 10 sec
D. 13 sec
E. None of these
Solution:
Relative speed = (70 + 38) = 108 km/hr {As the trains are moving in opposite directions)
Distance covered in crossing each other = (165 + 135) = 300 m
Hence, option C is correct.
As the notification is released by Reserve Bank Of India for the post of RBI Assistant 2023 preparation level of candidates are on highest peak, so if you also want to achieve high marks in this Exam then you will have to practice hard as we all know “practice makes the man perfect”. If you want to boost up your performance in RBI Assistant Exam 2023, you can practice more questions in the form of quizzes for RBI Assistant 2023 by the links given below .
Directions : Read the following questions carefully and choose the right answer.
Q.1. A man can reach a certain place in 40 hours. If he reduces his speed by 1/15th, he goes 5 km less in that time. Find the total distance covered by him.
A. 60 km.
B. 85 km.
C. 75 km.
D. 52 km.
E. None of these
Solution:
Let Distance = D km, Speed = S km/h
| Time = | Distance |
| Speed |
| 40 = | Distance | .... (1) |
| Speed |
After reducing speed,
| Distance = Distance – 5 km, Speed = S × | 14 | km/h |
| 15 |
| Time = | Distance |
| Speed |
| 40 = | (Distance – 5) | .... (2) | |
| Speed × | 14 | ||
| 15 | |||
After solving equation 1 and 2
| Distance | = | (Distance – 5) | |
| Speed | Speed × | 14 | |
| 15 | |||
14 Distance = 15 (Distance – 5)
14 Distance = 15 Distance – 75
Distance = 75 km.
Hence, option C is correct.
Q.2. In a college Anjana scored 80 marks out of 150 in History and 95 marks out of 120 in English. If she wants to score 70% marks in 3 subjects, find the minimum marks she should score in Geography out of 100.
A. 70
B. 55
C. 76
D. 85
E. None of these
Solution:
Total maximum marks = 100 + 120 + 150 = 370
Total marks in History and English = 95 + 80 = 175
Total marks required by her to get 70% = 370 × 70% = 259
So, she needs 259 – 175 = 84 marks to score 70%.
Hence, option E is correct.
Q.3. There are 15 boys and 10 girls in a class. If three students are selected at random, what is the probability that 1 girl and 2 boys are selected?
A. 1/10
B. 1/2
C. 21/46
D. 7/41
E. None of these
Solution:
Total number of ways of selecting 3 students from 25 students = 25C3
Number of ways of selecting 1 girl and 2 boys = selecting 2 boys from 15 boys and 1 girl from 10 girls
⇒ Number of ways in which this can be done = 15C2 × 10C1
Number of ways of selecting 1 girl and 2 boys = selecting 2 boys from 15 boys and 1 girl from 10 girls
⇒ Number of ways in which this can be done = 15C2 × 10C1
| ⇒ Required probability = | (15C2 × 10C1) |
| (25C3) |
| = | 21 |
| 46 |
Hence, option C is correct.
Q.4. Amit goes Mumbai to Kolkata by sea route. The speed of the boat in still water is 60 km/h and speed of the current is 15 km/h. After reaching Kolkata he stayed there for 20 minutes and after that come back by same boat. The time taken by him in this journey is 19 hours 32 minutes, find the distance travel by him in one side.
A. 450 km
B. 360 km
C. 540 km
D. 600 km
E. None of these
Solution:
Time taken by him in travelling = 19 hours 32 minutes – 20 minutes
= 19 hours 12 minutes
Let Distance = x km
According to the question,
| x | + | x | = 19 | 12 |
| 60+15 | 60 – 15 | 60 |
| x | + | x | = | 96 |
| 75 | 45 | 5 |
| 5x + 3x | = | 96 |
| 225 | 5 |
| 8x | = | 96 |
| 225 | 5 |
x = 540 km
Hence, option C is correct.
Q.5. Two trains 165 m and 135 m long run at the speed of 70 km/hr and 38 km/hr respectively in opposite directions on parallel tracks. The time (in seconds) which they take to cross each other is:
A. 4 sec
B. 5 sec
C. 10 sec
D. 13 sec
E. None of these
Solution:
Relative speed = (70 + 38) = 108 km/hr {As the trains are moving in opposite directions)
| ⇒ | ( | 108 × | 5 | ) | = 30 m/sec. |
| 18 |
Distance covered in crossing each other = (165 + 135) = 300 m
| Reqd. time = | ( | 300 × | 1 | ) | sec ⇒ | 30 | sec = 10 sec. |
| 30 | 3 |
Hence, option C is correct.
As the notification is released by Reserve Bank Of India for the post of RBI Assistant 2023 preparation level of candidates are on highest peak, so if you also want to achieve high marks in this Exam then you will have to practice hard as we all know “practice makes the man perfect”. If you want to boost up your performance in RBI Assistant Exam 2023, you can practice more questions in the form of quizzes for RBI Assistant 2023 by the links given below .
RBI Assistant Exam 2023 Quiz
Download Important Questions PDF
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We hope this article regarding syllabus of Quantitative Aptitude, with important topics like Number Series, Data Interpretation, Quadratic Equation and Miscellaneous with examples. At the end we would love to finish this article with a famous quote 'Sooner or Later The Man who Wins is The Man Who Thinks He Can'. So think positive and practice hard and you will definitely achieve your goal "RBI Assistant 2023"
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