Important for :

1

2

3

B

Given that, (x – 6) is the HCF of xLet f(x) = x

Now, f(x) = g(x) at (x = 6)

⇒ (6)

⇒ 0 = 30 – 6k ⇒ 6k = 30 ⇒ k = 5.

Hence, option B is correct.

4

A

Let f(x) = (x= (x

= (x – y)(x + y)(x

g(x) = (x

= (x

= (x + y) (x

= (x – y)(x + y)(x

Hence, option A is correct.

5

A

f(x) = x= x(x + 4) – 2(x + 4) = (x – 2)(x + 4)

g(x) = x

= x

= x (x – 2) (x – 2)

h(x) = x

So, LCM of [f(x), g(x), h(x)] = x(x – 2)(x + 4)(x – 2) = x(x + 4)(x – 2)

Hence, option A is correct.