Important for :

1

C

Let Arjun kapoor attempt x questions, he gets 10% of the answers wrong.

Arjun kapoor’s score = 0.9x – (0.1x) × | 1 | = 0.85x |

2 |

0.85x = 0.85z, where z is the total number of marks as well as total number of marks possible.

So, x = z ⇒ x = 100% of z

Similarly let Anil Kapoor attempt y questions

Anil kapoor’s score = 0.8y – (0.2y) × | 1 | = 0.7y |

2 |

0.7y = 0.7z ⇒ y = 100% of z

Now, 0.85z = P + 6, where P is pass mark …….. (i)

Also, 0.7z = P – 3 …….. (ii)

From (i) and (ii), we get

0.15z = 9 ⇒ z = 60

Putting the value of z in (ii), we get

0.7 × 60 = P – 3 ⇒ p = 42 + 3 = 45

Hence, option (C) is correct.

2

D

Cost of the Tomato last year = Rs.10

So, Cost of the Tomato this year = 10 + 20% of 10 = Rs.(10 + 2) = Rs.12

Cost of the Potato last year = Rs.5

Let the cost of Potato this year be x

Therefore, cost of 5 Potato and 3 Tomato this year = 5x + (3 × 12) = 5x + 36 ….. (i)

cost of 5 Potato and 3 Tomato last year = ((5 × 5) + (3 × 10)) = 55 …….. (ii)

This year the cost is Rs.11 more

From (i) and (ii), we get

5x + 36 = 55 + 11 ⇒ 5x = (66 – 36) ⇒ x = 6

Increase in the cost of Potato = (6 – 5) = Rs. 1

Percentage increase = | 1 | × 100% = 20% |

5 |

Hence, option (D) is correct.

3

A

The quantity of pulp (the part that is not water) in 90 kg of fresh sugarcane= | 16 | × 90 kg. |

100 |

This is also the quantity of pulp in the dried sugarcane formed.

Dried sugarcane have 72% pulp

16 | × 90 = | 72 |

100 | 100 |

(Quantity of dried sugarcane formed) = | 72 | × X (Say) |

100 |

⇒ X = 20

Hence, option (A) is correct.

4

A

Let the population of Salt Lake = 9x,

The population of South Kolkata = 8x, and

The population of Rajarhat = 3x

The total population of these three localities = 9x + 8x + 3x = 20x

The number of literate in Salt Lake = 80% of 9x = 7.2x

The number of literate in South Kolkata = 70% of 8x = 5.6 x

The number of literate in Rajarhat = 90% of 3x = 2.7x

The total number of literate in these three localities = 7.2x + 5.6x + 2.7x = 15.5x

Hence. Required percentage = | 15.5 x | × 100 = 77.5% |

20x |

Therefore, option (A) is correct.

5

A

Let Narendra Modi is denoted by M, Rahul Gandhi is denoted by R and Arvind Kejriwal is denoted by A. Now let R gets vote = x

M = 1.4x

M – A = 54000

R = 1.1A

From equation (II) and (IV) we get,

M = 1. 4 × 1.1A = 1.54 A

From equation (III) and (V) we get.,

0.54A = 54000

A = 100000

M = 1.54 × 10000 = 154000

R = 1.1 × 100000 = 110000

Hence total votes pole in election = (154000 + 110000 + 100000) = 364000

From question 90% of total votes pole on voting list.

Hence vote in voting list = | 364000 × 100 | = 404444 |

90 |

Therefore, option (A) is correct.