In the word “PARAGLIDING” there are 11 letters in which there are 4 vowels (i.e. 2 A’s and 2 I’s) and 7 consonants (i.e 2 G’s and each of P, R, L, D, N)
Considering vowel as one letter, the number of letters becomes 8 which can be arranged as
8!
=
40320
= 20160
2!
2
Vowel A and I appear twice , so vowels can be arranged as
4!
=
24
= 6
(2! × 2!)
4
Hence the required number of ways in which the letters of the word “PARAGLADING” be arranged so that all the vowels occur together = 20160 × 6 = 120960
Five people out of whom only two can drive are to be seated in a five seater car with two seats in front and three in the rear. The people who know driving don’t sit together. Only someone who knows driving can sit on the driver’s seat. Find the number of ways the five people can be seated.
A boy is playing a Snake & Ladder game; he is on 91 and has to get to 100 to complete the game. There is a snake on 93 and 96. In how many ways he can complete the game, if he doesn’t want to roll the dice more than three times.
8 members are to be selected from a group of 9 males and 7 females. In how many ways will the members with at most 3 females and at least 4 males be selected?
A chess board has rows and columns marked A to H and 1-8. Aman has a knight and a rook which he has to place on the board such that the two pieces are not in same row or column, what is total number of ways he can place the two pieces?
Permutation and Combination Questions with Explanations PDF
There are various ways in which objects from a set can be selected, generally without replacement to form subsets. The selection of subsets is known as permutation when order of selection is a factor, a combination is when the order is not a factor.
Permutation and combination is an important topic for any competitive exam. At Smartkeeda we have covered this topic in depth, so you can understand and gain mastery over this topic.
Practice daily at Smartkeeda with in-depth explanation to gain an understanding of the topic and improve your score.