Simplification Questions PDF for IBPS Clerk, SBI Clerk, IBPS RRB at Smartkeeda

Directions: What will come in place of question mark(?) in the following questions?
1
7 2  + 9 7  + 11 3  – 6 1  = ?
3 12 4 2
» Explain it
B
7 2  + 9 7  + 11 3  – 6 1  = ?
3 12 4 2

? = (7 + 9 + 11 – 6) +  ( 2  +  7  +  3  –  1 )
3 12 4 2

? = 21 +    8 + 7 + 9 – 6  = 21 +  18
12 12

? = 21 +  3  = 22 +  1  = 22 1  
2 2 2

Hence, option B is correct.
2
256.5 × 2512.25 = 2521–?
» Explain it
B
As the base on both the sides LHS and RHS are equal, we can compare the indices.
 
6.5 + 12.25 = 21 – x
 
18.75 = 21 – x 
 
Therefore, x = 21 – 18.75 
 
⇒ 2.25
 
Hence, option B is correct.
3
1332 ÷ 36 × 23 + 287 – 189 = ?
» Explain it
D
1332 ÷ 36 × 23 + 287 – 189 = ?

⇒   1332  × 23 + 287 – 189    
36

= 851 + 287 – 189 = 1138 – 189 = 949

Hence, option D is correct.
» Explain it
C
0.8% of 2580 + 16% of 685 = ?

? =  8  × 2580 +  16  × 685
10 × 100 100

= 20.64 + 109.6 = 130.24

Hence, option C is correct.
5
(153 × 1331) ÷ (11 × 17) = ?
» Explain it
B
(153 × 1331) ÷ (11 × 17) = ?

? =  153 × 1331  = 9 × 121 = 1089
11 × 17

Hence, option B is correct.

Simplification PDF with Solution for IBPS Clerk 2019

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Friends, Simplification is a most important topic for Bank Clerk Exams.

In this, Simplification quiz we will discuss how many types questions appear in IBPS Clerk Pre Exam. It is very important topic because in exam 5 to 10 questions is being asked in IBPS Clerk pre and IBPS Clerk pre.

To solve Simplification Questions for Banking and Insurance Exams like IBPS, IBPS, NABARD & RBI Grade B, NIACL, and LIC, you need to brush up your calculation skills; you need to perform calculations faster and accurately than others.
 
At Smartkeeda you can attempt difficult level simplification problems with solution and download simplification PDF for free so you can practice offline too. Smartkeeda always concern about aspirants that’s why they launched their portal Testzone for all Bank and SSC exams test series at low cost.
 
Here are the some examples of Simplification questions with solution for IBPS Clerk 2019

Ex.1

5  of 1456 of  2  of  136  = ?
13 7 17


Explanation:

5  of 1456 of  2  of  136  = ?
13 7 17

? =  5  × 1456 ×  2  ×  136  
13 7 17

? = 5 × 16 × 2 × 8

or, ? = 1280
 
Hence, option B is correct.
 
Here is fraction based simplification for IBPS Clerk Pre 2019, as you can see above:

Power Based Simplification Questions for IBPS Clerk Pre

256.5 × 2512.25 = 2521–?

Explanation : 

As the base on both the sides LHS and RHS are equal, we can compare the indices.
 
6.5 + 12.25 = 21 – x
 
18.75 = 21 – x 
 
Therefore, x = 21 – 18.75 
 
⇒ 2.25
 
Hence, option B is correct.

This type of simplification questions has also been seen in ibps clerk exams. So you need to practice power based simplification as well.

There are some root based simplification, Decimal Based Simplification as you see in above exercise. Take this Simplification quiz for IBPS Clerk Pre 2019, NIACL 2019 and other Bank and Insurance Clerk Exams for Free at Smartkeeda with Explanation.