Important for :

1

C

Let one-fourth of the distance between P and Q be x kmthen

Time taken for the first one-fourth distance = | x | km/hour |

10 |

and

Time taken for the remaining distance = | 3x | km/hour |

12 |

Since Total time taken is 7 hours.

⇒ 7 = | x | + | 3x |

10 | 12 |

On solving, x = 20

Total distance = 4x = 80 km.

Hence, option C is correct.

2

A

t = | D |

S |

According to the question,

Let Speed = 5x, 7x Distance = y m

y – 360 | = | y |

5x | 7x |

y – 360 | = | y |

5 | 7 |

7 (y – 360) = 5y

7y – 5y = 2520

2y = 2520

y = 1260

= 1.26 km.

Hence, option A is correct.

3

C

Let speed of the car, the train, and the bus be 5a Km/hr , 9a Km/hr and 4a Km/hr respectively

Given

total speed = (72 × 3) Km/hr = 216 Km/hr

total speed = (72 × 3) Km/hr = 216 Km/hr

⇒ 5a + 9a + 4a = 216

⇒ 18a = 216

⇒ a = 12Km/hr

⇒ speed of car = 5 × 12 = 60 Km/hr

And

speed of train = 9 × 12 = 108 Km/hr

speed of train = 9 × 12 = 108 Km/hr

⇒ their average speed = | 60 + 108 | = 84 Km/hr |

2 |

Hence, option (C) is correct.

4

E

Let the distance of his house to his office = D kmT = | D |

S |

4 hour 30 minutes = | D | + | D | |

16 | 20 |

9 | = | 5D + 4D |

2 | 80 |

9 | = | 9D |

2 | 80 |

D = 40

The distance from his house to his office = 40 km

The distance from his office to his friend's house = 40 km × 120% = 48 km

The distance from his house to his friend's house = 40 + 48 = 88 km

Hence, option E is correct.

5

D

Mohit runs 300m in 50 sec.

Anuj runs 300m in 60 sec.

Now, In 1 sec Anuj runs 5m

Therefore, in 50 sec Anuj runs 50×5 = 250m

Mohit beats Anuj by 300 - 250 = 50m .

Now, In 1 sec Anuj runs 5m

Therefore, in 50 sec Anuj runs 50×5 = 250m

Mohit beats Anuj by 300 - 250 = 50m .

Hence, option D is correct.