Maths Repeated Questions of SSC CGL, CHSL, MTS at Smartkeeda

Important for :
1
If  AB || CD || IH and AC || EF, ∠BAC = 80° and MN is perpendicular to PO, then find x, y, z using following figure
» Explain it
D
As AB || IH,

∴ ∠A = ∠H = 80°           [alternate interior angles of parallel sides are equal]

Also, AC || EF,

∴ ∠H = ∠G = x = 80°       [adjacent angles of parallel sides are equal]

Now, we have, MN ⊥ PO

∴ 90 + x + y = 180                         [linear pair axion]

y = 180 – 90 – 80

y= 10°

In ∆ PQR,

x + y + z = 180°

80 + 10 + z = 180°

z = 180 – 90

z = 90°

Hence, option D is correct.

2
In the figure below, find the value of AB.
» Explain it
B
We can redraw the given figure as below-

As angle A is common to both ∆ADE and ∆ACF and also ∠C = ∠D = 90°

Therefore, ratio of sides will be same as given below-

 x + 1 = 1 x + 4 2

2x + 2 =  x + 4

Or, x = 2 cm

∴ AO = 2 + 1 + 1 + 2 + 2 + 3 = 11 cm

Consider following right-angled triangle,

AB=112 - 32

AB= 121 - 9

AB = √112  cm

Hence, option B is correct.

3
For what value of k, does the equation  7x+ 14x + k become perfect square?
» Explain it
A
Here,  a = 7,b = 14, c = k

For perfect square, we have

b– 4ac = 0

⇒ (14)– 4 × 7 × k = 0

⇒ 196 = 28k

or, k = 7

Hence, option A is correct.

4
A cube of side 11 cm is melted and converted into a solid cylinder. It is found that the height of the cylinder so formed is 7 times the length of the rectangle whose width is 1.5 cm and perimeter 4 cm. Find the radius of the cylinder?
» Explain it
B
Volume of cube = (11)3

We have, volume of cylinder = volume of cube

⇒ πr2 h=11×11×11

 22 × r2 h = 11 × 11 × 11 7

 r2 h = 121 × 7 cm3 ---- eq (1) 2

Now,

2 (L + B) = 4

L+ B = 2

L = 2 – 1.5

 L = 0.5 = 1 cm 2

 Therefore, h = 7 × 1 = 7 2 2

Now eq(1) becomes,
 r2 × 7 = 121 × 7 2 2

r2 = 121

r = 11 cm

Hence, option B is correct.

5
The minimum value of 16 tan2 θ + 25cot2 θ is
» Explain it
D
Comparing 16 tan2 θ + 25cot2 θ with  a tan2 θ + b cot2 θ, we get

a = 16

and, b = 25

We know that the minimum value of such equation = 2√ab

Thus the minimum value = 2√(16 × 25)

⇒ 2 × 4 × 5 = 40

Hence, option D is correct.

Repeated Maths Questions with Solution PDF for CGL, CHSL, MTS | Smartkeeda

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Maths Syllabus and Questions for SSC CGL and SSC CHSL 2019 or 2020 Exams
Hello Aspirants, the wait is over now SSC finally released their 2019 exams calendar in 2020. It means all SSC Exams will be conducted in 2020. Now each aspirant have to start more and more practice to gain a high score in the exam. In this exercise, you will find maths questions for SSC CGL 2020, SSC CHSL 2020 and Other SSC Exams at Free of Cost. The above exercise is made by our maths experts, they brought you Most Important Maths Questions for SSC CGL 2020 with Explanation. So you can get the desired job easily or you can say practice by practice the minimum number of question which has a high probability to appear in your next big exams SSC CGL 2020, these exercises will update on a regular basis which through you can practice variety questions of maths. You can even practice here mixed exercise of SSC CGL and Individual ones. Individuals exercise are made of single chapters quizzes.

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