In each of these questions, two equations numbered I and II are given. You have to solve both the equations.
Important for :
1
I. 15x2 – 23x + 6 = 0

II.  6y2 + 23y + 40 = 18
» Explain it
A
15x2 – 23x + 6 = 0 is of the form ax2 – bx + c = 0

Hence, both roots of this equation are positive i.e. x > 0

6y2 + 23y + 40 = 18

∴ 6y2 + 23y + 22 = 0

This equation is of the form ay2 + by + c = 0

Hence, both roots of this equation are negative i.e. y < 0

Hence, x > y

Hence, option A is correct.

2
I. 5x2 − 6x − 63 = 0

II. 4y2 + y − 39 = 0
» Explain it
E
I. 5x2 − 6x − 63 = 0

∴ 5x2 + 15x − 21x − 63 = 0

∴ (5x − 21)(x + 3) = 0

∴ x = –3 or x = 21/5

II. 4y2 + y − 39 = 0

∴ 4y2 – 12y + 13y − 39 = 0

∴ (4y + 13)(y – 3) = 0

∴ y = 3 or y = −13/4

When x = 21/5, x > y

When x = −3 and y = 3, x < y

Hence, the relation between x and y cannot be established.

Hence, option E is correct..

3
I. x2 – 14x + 48 = 0

II. y2 – 23y + 90 = 0
» Explain it
E
I. x2 – 14x + 48 = 0

∴ x2 – 6x – 8x + 48 = 0

∴ (x – 6)(x – 8) = 0

∴ x = 6 or x = 8

II. y2 – 23y + 90 = 0

∴ y2 – 18y – 5y + 90 = 0

∴ (y – 18)(y – 5) = 0

∴ y = 18 or y = 5

When y = 18, y > x

When y = 5, y < x

Hence, the relation between x and y cannot be established.

Hence, option E is correct.

4
I. x2 – 24x + 135 = – 8

II. y2 + 17y – 31 = 7
» Explain it
A
I. x2 – 24x + 135 = −8

∴ x2 – 24x + 143 = 0

∴ x2 – 11x – 13x + 143 = 0

∴ (x – 13)(x – 11) = 0

∴ x = 13 or x = 11

II. y2 + 17y – 31 = 7

∴ y2 + 17y – 38 = 0

∴ y2 + 19y – 2y – 38 = 0

∴ (y + 19)(y – 2) = 0

∴ y = 2 or y = –19

For either value of x, x > y

Hence, option A is correct..

5
I. 8x2 + 10x – 7 = 0

II. y2 – 6y + 8 = 0
» Explain it
B
I. 8x2 + 10x – 7 = 0

∴ 8x2 – 4x + 14x – 7 = 0

∴ (4x + 7)(2x – 1) = 0

∴ x = –7/4 or x = 1/2

II. y2 – 6y + 8 = 0

∴ y2 – 4y – 2y + 8 = 0

∴ (y − 2)(y − 4) = 0

∴ y = 4 or y = 2

Since 1/2 < 1, y > x for all values.

Hence, option B is correct..

## Quadratic Equation Questions for SBI PO Pre, LIC AAO 2020

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Folks, here is a another quiz of Quadratic Equation, so we are going to discuss different kind of Quadratic Equation questions which are frequently asked in SBI PO Pre Exam, So Quadratic Equation have a lot of chance to appear in SBI PO Pre 2020.

We have to solve both of the Quadratic equations to get to know the relation between both the variables.

Suppose we have two variables ‘x’ and ‘y’. The relationship between the variables can be any one of the following:

x > y
x < y
x = y or relation can’t be established between x & y
x ≥ y
x ≤ y

Meaning of different symbols, Before getting deep into the quadratic equations, lets try to understand the meaning of the basic operations used in finding the relationship between the variables –

(1) ‘>’ symbol: This symbol indicates that variable on the left side is definitely greater than the variable on the right side of the symbol.

For example:  x > y means x is definitely greater than y.
(2) ‘<’ symbol: This symbol indicates that variable on the left is definitely smaller than the variable on the right side of the symbol.
For example: x<y means x is definitely smaller than y.

(3) ‘=’ symbol: This symbol indicates that variable on the left side is equal to the variable on the right side of the symbol.
For example: x = y means x is definitely equal to y.

(4) ‘≥’ symbol: This symbol indicates that variable on the left side is either greater than or equal to the variable on the right side of the symbol.
For example:  x ≥ y means x is either greater than y or equal to y.
(5) ‘≤’ symbol: This symbol indicates that variable on the left side is either smaller than or equal to the variable on the right side of the symbol.

For example: x≤y means x is either smaller than y or equal to y.

General form of a Quadratic Equation
ax2 + bx + c = 0

Quadratic equation means that it will definitely have the maximum power of the variable as ‘2’ which means we will always see ax2 term in a quadratic equation.

Or we can say that b can be 0, c can be 0 but a will never be 0.

While solving quadratic equation, you will always get 2 values of the equation. These 2 values are called roots of the equation. The roots of the equation always satisfy the equation. So in case of doubt, we can check the solution by putting the values back into the equation. If the equation turns out to be zero then our roots are correct.

Here are different kind of example of Quadratic Equation , so that we will get a very clear concept of the basic formation of a quadratic equation to get prepared for LIC AAO Pre 2020.

Type 1: This is basic of quadratic equation for bank exams like IBPS clerk Pre, SBI Clerk Pre, NIACL Assistant Pre as shown below

I. x3 – 4913 = 0                       II. y2 – 361 = 0

Here is the link to practice a proper quiz for quadratic equation for bank clerk pre exams like, IBPS Clerk pre 2020 SBI Clerk pre  and NIACL Assistant Pre

Type 2: Root based Quadratic Equation, these type of quadratic equation is being asked in LIC AAO Pre, SBI PO Pre exams

I. x2 – 3√3x – 54 = 0               II. y2 – 7√2y – 36 = 0

Here is the link to Practice New Pattern Based Quadratic Equation for LIC AAO 2020

Type 3: High level Quadratic Equation for LIC AAO 2020, this kind of Quadratic has been shown in many bank po exams

I. 20x2 – 108x + 144 = 0

II. 8y2 + 18y + 4 = 0