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One day, in an SBI Branch the attendance of all the employees was 100% but all the employees were not punctual to the office nor did all the employees stayed till the end of the office time. On that day, of all the employees who arrived early at the office, 20% of them left early but 40% of them left late and rest of them left on time. Of the employees who arrived late at the office, 50% of them left late but 25% of them left on time and rest of them left early. Of the employees who arrived on time, 37.5% of them left early and an equal number of them left late but rest of them left on time. The number of employees who arrived early was equal to the number of employees who left on time and the number of employees who left early was 39 more than the number of employees who arrived late at the office. The number of employees who didn’t leave on time was 144.

Important for :

1

A

The following common explanation, we getEarly | On time | Late | |

Arrived | 5x (assume) | 8y (assume) | 4z (assume) |

Left | X + 3y + z | 2x + z + 2y | 2x + 2z + 3y |

the total number of employees who left early = X + 3Y + Z = 12 + 45 + 6 = 63

the total number of employees who left late = 2X + 2Z + 3Y = 24 + 12 + 45 = 81

The required difference = 81 – 63 = 18

Let the number of employees who arrived early = 5x

The number of employees who left early = 20% of 5x = x

The number of employees who left late = 40% of 5x = 2x

The number of employees who left on time = 5x – 3x = 2x

Let the number of employees who arrived late at the office = 4z

The number of employees who left late = 50% of 4z = 2z

The number of employees who left on time 25% of 4z = z

The number of employees who left early = 4z – 3z = z

Let the number of employees who arrived on time = 8y

The number of employees who left early = 37.5% of 8y = 3y = The number of employees who left late

The number of employees who left on time = 8y – 6y = 2y

Early | On time | Late | |

Arrived | 5x (assume) | 8y (assume) | 4z (assume) |

Left | X + 3y + z | 2x + z + 2y | 2x + 2z + 3y |

According to the question, 5x = 2x + z + 2y

3x = z + 2y ------- (i)

The number of employees who didn’t arrive on time = x + 3y + z + 2x + 2z + 3y = 144

3x + 3z + 6y = 144

From the equation (i), 9x = 3z + 6y ----- (ii)

Therefore, 3x + 9x = 12x = 144

X = 12

Again, according to the question, x + 3y + z = 4z + 39

3y – 3z = 27 ---------- (iii)

Adding equation (ii) and equation (iii)

9y = 9x + 27

Y = x + 3 = 12 + 3 = 15

From the equation (iii)

3z = 45 – 27 = 18

Z = 6

2

C

The following common explanation, we getthe total number of employees working in that branch = 5x + 8y + 4z = 60 + 120 + 24 = 204

Hence, option C is correct.

Let the number of employees who arrived early = 5x

The number of employees who left early = 20% of 5x = x

The number of employees who left late = 40% of 5x = 2x

The number of employees who left on time = 5x – 3x = 2x

Let the number of employees who arrived late at the office = 4z

The number of employees who left late = 50% of 4z = 2z

The number of employees who left on time 25% of 4z = z

The number of employees who left early = 4z – 3z = z

Let the number of employees who arrived on time = 8y

The number of employees who left early = 37.5% of 8y = 3y = The number of employees who left late

The number of employees who left on time = 8y – 6y = 2y

Early | On time | Late | |

Arrived | 5x (assume) | 8y (assume) | 4z (assume) |

Left | X + 3y + z | 2x + z + 2y | 2x + 2z + 3y |

According to the question, 5x = 2x + z + 2y

3x = z + 2y ------- (i)

The number of employees who didn’t arrive on time = x + 3y + z + 2x + 2z + 3y = 144

3x + 3z + 6y = 144

From the equation (i), 9x = 3z + 6y ----- (ii)

Therefore, 3x + 9x = 12x = 144

X = 12

Again, according to the question, x + 3y + z = 4z + 39

3y – 3z = 27 ---------- (iii)

Adding equation (ii) and equation (iii)

9y = 9x + 27

Y = x + 3 = 12 + 3 = 15

From the equation (iii)

3z = 45 – 27 = 18

Z = 6

3

A

The following common explanation, we getThe respective ratio = 5x : 8y : 4z = 60 : 120 : 24 = 5 : 10 : 2

Hence, option A is correct.

Let the number of employees who arrived early = 5x

The number of employees who left early = 20% of 5x = x

The number of employees who left late = 40% of 5x = 2x

The number of employees who left on time = 5x – 3x = 2x

Let the number of employees who arrived late at the office = 4z

The number of employees who left late = 50% of 4z = 2z

The number of employees who left on time 25% of 4z = z

The number of employees who left early = 4z – 3z = z

Let the number of employees who arrived on time = 8y

The number of employees who left early = 37.5% of 8y = 3y = The number of employees who left late

The number of employees who left on time = 8y – 6y = 2y

Early | On time | Late | |

Arrived | 5x (assume) | 8y (assume) | 4z (assume) |

Left | X + 3y + z | 2x + z + 2y | 2x + 2z + 3y |

According to the question, 5x = 2x + z + 2y

3x = z + 2y ------- (i)

The number of employees who didn’t arrive on time = x + 3y + z + 2x + 2z + 3y = 144

3x + 3z + 6y = 144

From the equation (i), 9x = 3z + 6y ----- (ii)

Therefore, 3x + 9x = 12x = 144

X = 12

Again, according to the question, x + 3y + z = 4z + 39

3y – 3z = 27 ---------- (iii)

Adding equation (ii) and equation (iii)

9y = 9x + 27

Y = x + 3 = 12 + 3 = 15

From the equation (iii)

3z = 45 – 27 = 18

Z = 6

4

B

The following common explanation, we get
the total number of employees working in that branch = 5x + 8y + 4z = 60 + 120 + 24 = 204

of the total number of employees was on leave on the medical ground = 25% of 204 = 51

Remaining = 204 – 51 = 153

The number of employees who was on leave for personal reason = 33.33% of 153 = 51

The number of employees present on the day before yesterday of that day = 153 – 51 = 102

Let the number of employees who arrived early = 5x

The number of employees who left early = 20% of 5x = x

The number of employees who left late = 40% of 5x = 2x

The number of employees who left on time = 5x – 3x = 2x

Let the number of employees who arrived late at the office = 4z

The number of employees who left late = 50% of 4z = 2z

The number of employees who left on time 25% of 4z = z

The number of employees who left early = 4z – 3z = z

Let the number of employees who arrived on time = 8y

The number of employees who left early = 37.5% of 8y = 3y = The number of employees who left late

The number of employees who left on time = 8y – 6y = 2y

Early | On time | Late | |

Arrived | 5x (assume) | 8y (assume) | 4z (assume) |

Left | X + 3y + z | 2x + z + 2y | 2x + 2z + 3y |

According to the question, 5x = 2x + z + 2y

3x = z + 2y ------- (i)

The number of employees who didn’t arrive on time = x + 3y + z + 2x + 2z + 3y = 144

3x + 3z + 6y = 144

From the equation (i), 9x = 3z + 6y ----- (ii)

Therefore, 3x + 9x = 12x = 144

X = 12

Again, according to the question, x + 3y + z = 4z + 39

3y – 3z = 27 ---------- (iii)

Adding equation (ii) and equation (iii)

9y = 9x + 27

Y = x + 3 = 12 + 3 = 15

From the equation (iii)

3z = 45 – 27 = 18

Z = 6

5

C

The following common explanation, we get
The number of employees who left on time = 2x + z + 2y = 24 + 6 + 30 = 60

The number of employees who didn’t leave on time = x + 3y + z + 2x + 2z + 3y = 3x + 6y + 3z = 36 + 90 + 18 = 144

The reqd. % = | (144 – 60) × 100 | = | 84 × 100 | = 58.33% approx. |

144 | 144 |

Hence, option C is correct.

Let the number of employees who arrived early = 5x

The number of employees who left early = 20% of 5x = x

The number of employees who left late = 40% of 5x = 2x

The number of employees who left on time = 5x – 3x = 2x

Let the number of employees who arrived late at the office = 4z

The number of employees who left late = 50% of 4z = 2z

The number of employees who left on time 25% of 4z = z

The number of employees who left early = 4z – 3z = z

Let the number of employees who arrived on time = 8y

The number of employees who left early = 37.5% of 8y = 3y = The number of employees who left late

The number of employees who left on time = 8y – 6y = 2y

Early | On time | Late | |

Arrived | 5x (assume) | 8y (assume) | 4z (assume) |

Left | X + 3y + z | 2x + z + 2y | 2x + 2z + 3y |

According to the question, 5x = 2x + z + 2y

3x = z + 2y ------- (i)

The number of employees who didn’t arrive on time = x + 3y + z + 2x + 2z + 3y = 144

3x + 3z + 6y = 144

From the equation (i), 9x = 3z + 6y ----- (ii)

Therefore, 3x + 9x = 12x = 144

X = 12

Again, according to the question, x + 3y + z = 4z + 39

3y – 3z = 27 ---------- (iii)

Adding equation (ii) and equation (iii)

9y = 9x + 27

Y = x + 3 = 12 + 3 = 15

From the equation (iii)

3z = 45 – 27 = 18

Z = 6

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Data Interpretation is an important part in all bank exams. Here we at Smartkeeda.com we will learn a New Pattern Based DI, Which is Called Caselet DI, These days Caselet DI freequenty asked in all major Bank exams SBI PO Pre, SBI Clerk. It has alot chance to appear in SBI PO 2019 and SBI Clerk 2019.

We provide you data interpretation quiz with answers and explanation.

Aspirants preparing for SBI PO exams for the year 2019 can practice these questions. Let us now understand, what exactly is a Caselet DI. Data interpretation normally consists of questions involving pie charts, bar graphs, line graphs, radar graphs pr table with the required information for solving the questions. In a paragraph type data interpretation question, a set of information is provided in a paragraph form. It doesn’t consist of any charts or tables. You have to read the given information carefully and draw a suitable table/chart listing out all the given data to answer the questions.

So, First of all, whenever exams authorities comes up with new kind of questions, students raises one query, "How to Solve New Pattern Based Caselet Data Interpretation". So first we discuss

How to solve caselets/paragraph/Info Chart data interpretation questions?

Given Below steps will help you all while solving questions of Caselet or paragraph based Data Interpretation questions in SBI PO, SBI Clerk Exams. Data Interpretation for SBI PO Pre, SBI Clerk 2019 with PDF.

Sks Here are the some points you need to remember:

Caselet DI is frequently being asked these days and so we must practice this in the form of quizzes as Smartkeeda Caselt Data Interpretation Quiz for Free of Cost. So, Caselet DI is not new or not even out of way. It is just a mathematical form of English Passage. In Caselet DI, a long paragraph is given and on the basis of that. Candidates can download data interpretation quiz with solutions for banking and other competitive examination.

In the above paragraph of Caselet DI, lots of information is given. You have to read the paragraph carefully and then you have to note down all the key information as short as possible. The given information will let you draw some diagrams such as Venn diagram, tabular chart or any other diagram.

The difference between simple DI and Caselet DI is - In simple DI, information is already given in diagrammatical forms but in Caselet DI, you have to draw a diagram on the basis of given information

Before start solving Caselet DI, you must have knowledge of the following 7 key things:

So, in the above information chart or Caselet Chart or Passage Chart you will see all the rules are following properly. While attempting Caselet DI you can even save your time in exam only one condition if you do practice a lot which trough you can create Image or differentiate the data and After that you can answer easily.'

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