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Three friends Seeta, Reeta and Geeta spends 12%, 14% and 16% of their monthly salary on travelling in the given order and each of them save half of the remaining amount. The monthly salary of Seeta and Geeta is same and the monthly saving of Seeta is Rs. 360 more than that of Geeta. The total expenditures of Seeta and Reeta together on travelling is Rs. 1240 more than that of Geeta.

Important for :

1

B

Following common explanation, we get

The monthly expenditure of Seeta and Reeta together on travelling = Rs. (12x + 14y) = Rs. (12 × 180 + 14 × 140)

= Rs. (2160 + 1960) = Rs. 4120

Hence, option B is correct.The monthly expenditure of Seeta and Reeta together on travelling = Rs. (12x + 14y) = Rs. (12 × 180 + 14 × 140)

= Rs. (2160 + 1960) = Rs. 4120

Let the monthly salary of Seeta = Rs. 100x

Then, Monthly expenditures on travelling = 12% of 100x = Rs. 12x

Remaining = Rs. (100x – 12x) = Rs. 88x

Saving = | 88x | = Rs. 44x |

2 |

Then, Monthly expenditures on travelling = 14% of 100x = Rs. 14y

Remaining = Rs. (100y – 14y) = Rs. 86y

Saving = | 86y | = Rs. 43y |

2 |

The monthly salary of Geeta = The monthly salary of Seeta = Rs. 100x

The monthly expenditures of Geeta on travelling = 16% of 100x = Rs. 16x

Remaining = Rs.(100x – 16x) = Rs. 84x

Saving = | 84x | = Rs. 42x |

2 |

The monthly salary of Seeta and Geeta are same and the monthly saving of Seeta is Rs. 360 more than that of Geeta

44x – 42x = 2x = 360

x = 180

The total expenditures of Seeta and Reeta together on travelling is Rs. 1240 more than that of Geeta.

12x + 14y = 16x + 1240

14y = 4x + 1240 = 720 + 1240 = 1960

y = 140

2

E

Following common explanation, we get
The monthly salary of Reeta = Rs. 100y = Rs. 14000

The monthly salary of Seeta = Rs. 100x = Rs. 18000

The required answer = Rs. (14000 – 18000) = 4000 less than that of Seeta

Let the monthly salary of Seeta = Rs. 100x

Then, Monthly expenditures on travelling = 12% of 100x = Rs. 12x

Remaining = Rs. (100x – 12x) = Rs. 88x

Saving = | 88x | = Rs. 44x |

2 |

Then, Monthly expenditures on travelling = 14% of 100x = Rs. 14y

Remaining = Rs. (100y – 14y) = Rs. 86y

Saving = | 86y | = Rs. 43y |

2 |

The monthly expenditures of Geeta on travelling = 16% of 100x = Rs. 16x

Remaining = Rs.(100x – 16x) = Rs. 84x

Saving = | 84x | = Rs. 42x |

2 |

44x – 42x = 2x = 360

x = 180

The total expenditures of Seeta and Reeta together on travelling is Rs. 1240 more than that of Geeta.

12x + 14y = 16x + 1240

14y = 4x + 1240 = 720 + 1240 = 1960

y = 140

3

A

Following common explanation, we get

The required sum = Rs. (44x + 43y + 42x) = Rs. (86x + 43y) = Rs. (86 × 180 + 43 × 140) = Rs. (15480 + 6020) = Rs. 21500

Hence, option A is correct.

The required sum = Rs. (44x + 43y + 42x) = Rs. (86x + 43y) = Rs. (86 × 180 + 43 × 140) = Rs. (15480 + 6020) = Rs. 21500

Hence, option A is correct.

Let the monthly salary of Seeta = Rs. 100x

Then, Monthly expenditures on travelling = 12% of 100x = Rs. 12x

Remaining = Rs. (100x – 12x) = Rs. 88x

Saving = | 88x | = Rs. 44x |

2 |

Then, Monthly expenditures on travelling = 14% of 100x = Rs. 14y

Remaining = Rs. (100y – 14y) = Rs. 86y

Saving = | 86y | = Rs. 43y |

2 |

The monthly expenditures of Geeta on travelling = 16% of 100x = Rs. 16x

Remaining = Rs.(100x – 16x) = Rs. 84x

Saving = | 84x | = Rs. 42x |

2 |

44x – 42x = 2x = 360

x = 180

The total expenditures of Seeta and Reeta together on travelling is Rs. 1240 more than that of Geeta.

12x + 14y = 16x + 1240

14y = 4x + 1240 = 720 + 1240 = 1960

y = 140

4

D

Following common explanation, we get

Their total monthly salary = Rs. (100x + 100y + 100x) = Rs. (200x + 100y) = Rs. (36000 + 14000) = Rs. 50000

Total monthly saving = Rs. (44x + 43y + 42x) = Rs. (86x + 43y) = Rs. (86 × 180 + 43 × 140) = Rs. (15480 + 6020) = Rs. 21500

The reqd. answer = | 21500 × 100 | = 43% |

50000 |

Hence, option D is correct.

Let the monthly salary of Seeta = Rs. 100x

Then, Monthly expenditures on travelling = 12% of 100x = Rs. 12x

Remaining = Rs. (100x – 12x) = Rs. 88x

Saving = | 88x | = Rs. 44x |

2 |

Then, Monthly expenditures on travelling = 14% of 100x = Rs. 14y

Remaining = Rs. (100y – 14y) = Rs. 86y

Saving = | 86y | = Rs. 43y |

2 |

The monthly expenditures of Geeta on travelling = 16% of 100x = Rs. 16x

Remaining = Rs.(100x – 16x) = Rs. 84x

Saving = | 84x | = Rs. 42x |

2 |

44x – 42x = 2x = 360

x = 180

The total expenditures of Seeta and Reeta together on travelling is Rs. 1240 more than that of Geeta.

12x + 14y = 16x + 1240

14y = 4x + 1240 = 720 + 1240 = 1960

y = 140

5

B

Following common explanation, we get

The monthly expenditures of Seeta = Rs. 12X = Rs. 12 × 180 = Rs. 2160

The monthly expenditures of Geeta = Rs. 16X = Rs. 180 × 16 = Rs. 2880

Let the monthly salary of Seeta was increased by a% then

12% of [(100 + a)% of 18000] = 2880

12% of [18000 + a × 180] = 2880

2160 + 21.6a = 2880

21.6a = 720

a = | 7200 | % = 33.33% |

216 |

The required answer = 33.33% of 18000 = Rs. 6000

Hence, option B is correct.

Let the monthly salary of Seeta = Rs. 100x

Then, Monthly expenditures on travelling = 12% of 100x = Rs. 12x

Remaining = Rs. (100x – 12x) = Rs. 88x

Saving = | 88x | = Rs. 44x |

2 |

Then, Monthly expenditures on travelling = 14% of 100x = Rs. 14y

Remaining = Rs. (100y – 14y) = Rs. 86y

Saving = | 86y | = Rs. 43y |

2 |

The monthly expenditures of Geeta on travelling = 16% of 100x = Rs. 16x

Remaining = Rs.(100x – 16x) = Rs. 84x

Saving = | 84x | = Rs. 42x |

2 |

The monthly salary of Seeta and Geeta are same and the monthly saving of Seeta is Rs. 360 more than that of Geeta

44x – 42x = 2x = 360

x = 180

The total expenditures of Seeta and Reeta together on travelling is Rs. 1240 more than that of Geeta.

12x + 14y = 16x + 1240

14y = 4x + 1240 = 720 + 1240 = 1960

y = 140

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