- DI Info Chart 23
- DI Info Chart 22
- DI Info Chart 21
- DI Info Chart 20
- DI Info Chart 19
- DI Info Chart 18
- DI Info Chart 17
- DI Info Chart 16
- DI Info Chart 15
- DI Info Chart 14
- DI Info Chart 13
- DI Info Chart 12
- DI Info Chart 11
- DI Info Chart 10
- DI Info Chart 9
- DI Info Chart 8
- DI Info Chart 7
- DI Info Chart 6
- DI Info Chart 5
- DI Info Chart 4
- DI Info Chart 3
- DI Info Chart 2
- DI Info Chart 1

Chaman and Baman together bought 4 acres of agriculture land in the ratio of 5: 3 in the year 2015 and started cultivating wheat in the year 2016. In that year, Chaman being an elder brother gave 50 tons of wheat which was 8% of his total production of that year to Baman, now Baman’s total wheat quantity was increased by 25%. In the year 2017, Baman’s total wheat production was doubled over the previous year so he returned 10% of his total wheat produced quantity to Chaman now, after receiving from Baman, Chaman’s total wheat quantity was increased by 200/3 %. In the year 2018, both of them had produced an equal quantity of wheat and Chaman’s production of wheat was increased by 25% over the total quantity of wheat he had produced in the previous year.

Important for :

1

D

Following the common explanation, we getTotal quantity (in ton) of wheat produced by Chaman in the year 2018 = 75 tons

Hence, option D is correct.

In 2016, 8% of Chaman’s total production = 50 tons

Total production = | 50 × 100 | = 625 tons |

8 |

Let the Baman’s total production = x tons then 25% of x= 50

x = | 50 × 100 |

25 |

x = 200 tons

In 2017,

Baman’s total production = 2 × 200 = 400 tons

10% of 400 = 40 tons he returned to Chaman

Let Chaman’s total production = y then (200/3)% of y = 40

2y | = 40 |

3 |

y = 60 tons = Chaman’s total production of wheat in 2017

In 2018, Chaman’s production of wheat = 125% of 60 = 75 tons = the total production of wheat for Baman in the year 2018

2

E

Following common explanation, we get
Total quantity (in ton) of wheat produced by Baman in the year 2018 = 75 tons

Total quantity (in ton) of wheat produced by Baman in the year 2017 = 400 tons

The reqd. % increase = | (400 – 75) × 100 | = | 325 | = 81.25% |

400 | 4 |

Hence, option E is correct.

In 2016, 8% of Chaman’s total production = 50 tons

Total production = | 50 × 100 | = 625 tons |

8 |

Let the Baman’s total production = x tons then 25% of x= 50

x = | 50 × 100 |

25 |

x = 200 tons

In 2017,

Baman’s total production = 2 × 200 = 400 tons

10% of 400 = 40 tons he returned to Chaman

Let Chaman’s total production = y then (200/3)% of y = 40

2y | = 40 |

3 |

y = 60 tons = Chaman’s total production of wheat in 2017

In 2018, Chaman’s production of wheat = 125% of 60 = 75 tons = the total production of wheat for Baman in the year 2018

3

B

Following common explanation, we getQuantity of total wheat Baman produced in the year 2017 and 2018 together = 400 + 75 = 475 tons

Hence, option B is correct.

In 2016, 8% of Chaman’s total production = 50 tons

Total production = | 50 × 100 | = 625 tons |

8 |

Let the Baman’s total production = x tons then 25% of x= 50

x = | 50 × 100 |

25 |

x = 200 tons

In 2017,

Baman’s total production = 2 × 200 = 400 tons

10% of 400 = 40 tons he returned to Chaman

Let Chaman’s total production = y then (200/3)% of y = 40

2y | = 40 |

3 |

y = 60 tons = Chaman’s total production of wheat in 2017

In 2018, Chaman’s production of wheat = 125% of 60 = 75 tons = the total production of wheat for Baman in the year 2018

4

C

Following common explanation, we get
The total quantity of wheat produced by Chaman in the given three periods = 625 + 60 + 75 = 760 tons

The total quantity of wheat produced by Baman in the given three periods = 200 + 400 + 75 = 675

The required difference = 760 – 675 = 85 tons

In 2016, 8% of Chaman’s total production = 50 tons

Total production = | 50 × 100 | = 625 tons |

8 |

Let the Baman’s total production = x tons then 25% of x= 50

x = | 50 × 100 |

25 |

x = 200 tons

In 2017,

Baman’s total production = 2 × 200 = 400 tons

10% of 400 = 40 tons he returned to Chaman

Let Chaman’s total production = y then (200/3)% of y = 40

2y | = 40 |

3 |

y = 60 tons = Chaman’s total production of wheat in 2017

In 2018, Chaman’s production of wheat = 125% of 60 = 75 tons = the total production of wheat for Baman in the year 2018

5

C

Following common explanation, we getChaman’s land = | 4 × 5 | = 2.5 acres |

8 |

Baman’s land = | 4 × 3 | = 1.5 acres |

8 |

Chaman’s production of wheat = 625 tons

Baman’s production of wheat = 200 tons

The reqd. ratio = | 625 | : | 200 |

2.5 | 1.5 |

25 × 15 : 8 × 25 = 15 : 8

Hence, option C is correct.

In 2016, 8% of Chaman’s total production = 50 tons

Total production = | 50 × 100 | = 625 tons |

8 |

Let the Baman’s total production = x tons then 25% of x= 50

x = | 50 × 100 |

25 |

x = 200 tons

In 2017,

Baman’s total production = 2 × 200 = 400 tons

10% of 400 = 40 tons he returned to Chaman

Let Chaman’s total production = y then (200/3)% of y = 40

2y | = 40 |

3 |

y = 60 tons = Chaman’s total production of wheat in 2017

In 2018, Chaman’s production of wheat = 125% of 60 = 75 tons = the total production of wheat for Baman in the year 2018

- caselet di pdf
- caselet di pdf book
- caselet di for ibps clerk mains
- caselet di pdf for ibps po
- caselet di ibps clerk
- caselet di venn diagram
- caselet di asked in ibps clerk
- caselet di asked in sbi clerk 2019
- caselet based di
- caselet di for bank po pdf
- caselet di for bank po mains
- caselet di for clerk
- caselet di for ibps clerk
- caselet di for ibps clerk mains
- caselet di pdf download
- caselet di using venn diagram
- caselet di example
- caselet di easy
- caselet di for ibps clerk mains 2019
- caselet di for ibps po prelims 2019
- caselet di for mains
- caselet di high level
- caselet in di
- caselet di for ibps po 2019
- caselet di pdf ibps po
- caselet di practice
- caselet di probability

We provide you data interpretation quiz with answers and explanation.

Aspirants preparing for IBPS PO exams for the year 2019 can practice these questions. Let us now understand, what exactly is a

So, First of all, whenever exams authorities come up with new kind of questions, students raise one query, "How to Solve New Pattern Based Caselet Data Interpretation". So first we discuss

How to solve caselets/paragraph/Info Chart data interpretation questions?

Given Below steps will help you all while solving questions of Caselet or paragraph based Data Interpretation questions in

Sks Here are some points you need to remember:

Caselet DI is frequently being asked these days and so we must practice this in the form of quizzes as Smartkeeda

In the above paragraph of

The difference between simple DI and Caselet DI is - In simple DI, information is already given in diagrammatical forms but in Caselet DI, you have to draw a diagram on the basis of given information

Before start solving Caselet DI, you must have knowledge of the following 7 key things:

So, in the above information chart or Caselet Chart or Passage Chart, you will see all the rules are following properly. While attempting Caselet DI you can even save your time in exam only one condition if you do practice a lot which trough you can create Image or differentiate the data and After that, you can answer easily.'

Guys, Smartkeeda Started New Platform Called Testzone which provides Best Test Series for all Bank, SSC and Insurance Exams. you must try its free mock test you will get to know by your self.

Here is the Link: Testzone

- caselet di for prelims
- caselet di questions pdf
- caselet di questions
- caselet di quiz
- caselet di for ibps rrb
- caselet di ibps clerk
- caselet di for ibps po 2019
- caselet di practice set
- caselet type di
- caselet di for ibps clerk 2019
- caselet di for ibps po 2019
- caselet di for ibps po pdf
- caselet di for ibps po 2019 pdf
- caselet di pdf download for ibps po 2019
- caselet di pdf for ibps po pre 2019
- caselet di asked in sbi po 2019
- caselet di for ibps po 2019
- caselet questions for ibps 2019
- caselet di asked in sbi po 2019

Team Smartkeeda