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Chaman and Baman together bought 4 acres of agriculture land in the ratio of 5: 3 in the year 2015 and started cultivating wheat in the year 2016. In that year, Chaman being an elder brother gave 50 tons of wheat which was 8% of his total production of that year to Baman, now Baman’s total wheat quantity was increased by 25%. In the year 2017, Baman’s total wheat production was doubled over the previous year so he returned 10% of his total wheat produced quantity to Chaman now, after receiving from Baman, Chaman’s total wheat quantity was increased by 200/3 %. In the year 2018, both of them had produced an equal quantity of wheat and Chaman’s production of wheat was increased by 25% over the total quantity of wheat he had produced in the previous year.

Important for :

1

D

Following the common explanation, we getTotal quantity (in ton) of wheat produced by Chaman in the year 2018 = 75 tons

Hence, option D is correct.

In 2016, 8% of Chaman’s total production = 50 tons

Total production = | 50 × 100 | = 625 tons |

8 |

Let the Baman’s total production = x tons then 25% of x= 50

x = | 50 × 100 |

25 |

x = 200 tons

In 2017,

Baman’s total production = 2 × 200 = 400 tons

10% of 400 = 40 tons he returned to Chaman

Let Chaman’s total production = y then (200/3)% of y = 40

2y | = 40 |

3 |

y = 60 tons = Chaman’s total production of wheat in 2017

In 2018, Chaman’s production of wheat = 125% of 60 = 75 tons = the total production of wheat for Baman in the year 2018

2

E

Following common explanation, we get
Total quantity (in ton) of wheat produced by Baman in the year 2018 = 75 tons

Total quantity (in ton) of wheat produced by Baman in the year 2017 = 400 tons

The reqd. % increase = | (400 – 75) × 100 | = | 325 | = 81.25% |

400 | 4 |

Hence, option E is correct.

In 2016, 8% of Chaman’s total production = 50 tons

Total production = | 50 × 100 | = 625 tons |

8 |

Let the Baman’s total production = x tons then 25% of x= 50

x = | 50 × 100 |

25 |

x = 200 tons

In 2017,

Baman’s total production = 2 × 200 = 400 tons

10% of 400 = 40 tons he returned to Chaman

Let Chaman’s total production = y then (200/3)% of y = 40

2y | = 40 |

3 |

y = 60 tons = Chaman’s total production of wheat in 2017

In 2018, Chaman’s production of wheat = 125% of 60 = 75 tons = the total production of wheat for Baman in the year 2018

3

B

Following common explanation, we getQuantity of total wheat Baman produced in the year 2017 and 2018 together = 400 + 75 = 475 tons

Hence, option B is correct.

In 2016, 8% of Chaman’s total production = 50 tons

Total production = | 50 × 100 | = 625 tons |

8 |

Let the Baman’s total production = x tons then 25% of x= 50

x = | 50 × 100 |

25 |

x = 200 tons

In 2017,

Baman’s total production = 2 × 200 = 400 tons

10% of 400 = 40 tons he returned to Chaman

Let Chaman’s total production = y then (200/3)% of y = 40

2y | = 40 |

3 |

y = 60 tons = Chaman’s total production of wheat in 2017

In 2018, Chaman’s production of wheat = 125% of 60 = 75 tons = the total production of wheat for Baman in the year 2018

4

C

Following common explanation, we get
The total quantity of wheat produced by Chaman in the given three periods = 625 + 60 + 75 = 760 tons

The total quantity of wheat produced by Baman in the given three periods = 200 + 400 + 75 = 675

The required difference = 760 – 675 = 85 tons

In 2016, 8% of Chaman’s total production = 50 tons

Total production = | 50 × 100 | = 625 tons |

8 |

Let the Baman’s total production = x tons then 25% of x= 50

x = | 50 × 100 |

25 |

x = 200 tons

In 2017,

Baman’s total production = 2 × 200 = 400 tons

10% of 400 = 40 tons he returned to Chaman

Let Chaman’s total production = y then (200/3)% of y = 40

2y | = 40 |

3 |

y = 60 tons = Chaman’s total production of wheat in 2017

In 2018, Chaman’s production of wheat = 125% of 60 = 75 tons = the total production of wheat for Baman in the year 2018

5

C

Following common explanation, we getChaman’s land = | 4 × 5 | = 2.5 acres |

8 |

Baman’s land = | 4 × 3 | = 1.5 acres |

8 |

Chaman’s production of wheat = 625 tons

Baman’s production of wheat = 200 tons

The reqd. ratio = | 625 | : | 200 |

2.5 | 1.5 |

25 × 15 : 8 × 25 = 15 : 8

Hence, option C is correct.

In 2016, 8% of Chaman’s total production = 50 tons

Total production = | 50 × 100 | = 625 tons |

8 |

Let the Baman’s total production = x tons then 25% of x= 50

x = | 50 × 100 |

25 |

x = 200 tons

In 2017,

Baman’s total production = 2 × 200 = 400 tons

10% of 400 = 40 tons he returned to Chaman

Let Chaman’s total production = y then (200/3)% of y = 40

2y | = 40 |

3 |

y = 60 tons = Chaman’s total production of wheat in 2017

In 2018, Chaman’s production of wheat = 125% of 60 = 75 tons = the total production of wheat for Baman in the year 2018

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