# Caselet Data Interpretation for SBI PO 2020, LIC ADO 2020, LIC AAO | Take New Pattern DI Quizzes Online for Free at Smartkeeda

Directions : Study the following information carefully and answer the questions given beside.

A father divided his property between two sons A and B and one daughter C. The person has Rs. 80000 in cash, Rs. 5 lakhs as land and Rs. 6 lakhs as gold. He gave half of the gold to his daughter and remaining gold divided between sons in equal proportion. He gave only 20% of total land to his daughter and divided the remaining land  between sons A and B in the ratio of 3 : 1 respectively on the condition that the child who received highest share of land will give Rs. 2500 per month to his father. He gave 75% of the total cash amount to his daughter and remaining cash amount was divided between sons in equal proportion.
Important for :
1
How much total property (in cash, land and Gold together) did  C get?
» Explain it
B
Following common explanation, we get

Total property (In cash, land and Gold together) Daughter C got = 4 lakhs 60 thousand = Rs. 4.6 lakhs

Hence, option B is correct.

Common explanation :

The total share of daughter = half of gold + 20% of land + 75% of cash amount

 = 6 lakhs + 20% of 5 lakhs + 75% of 80 thousand 2

= 3 lakhs + 1 lakhs + 60 thousand = 4 lakhs 60 thousand

Remaining Gold = 6 lakhs – 3 lakhs = 3 lakhs

Remaining Land = 5 lakhs – 1 lakhs = 4 lakhs

Remaining Cash = 80000 – 60000 = 20000

The share of son A = (1/2) of remaining gold + (3/4) of remaining land + (1/2) of remaining cash

= 1.5 lakhs + 3 lakhs + 10 thousand = 4.6 lakhs

The share of son B = (1/2) of remaining gold + (1/4) of remaining land + (1/2) of remaining cash

= 1.5 lakhs + 1 lakhs + 10 thousand = 2.6 lakhs
2
The share of son A in total property was how much more than that of son B in total property?
» Explain it
A
Following common explanation, we get

The share of son A in total property = 4.6 lakhs

The share of son B in total property = 2.6 lakhs

The required difference = 4.6 – 2.6 = 2 lakhs

Hence, option A is correct.

Common explanation :

The total share of daughter = half of gold + 20% of land + 75% of cash amount

 = 6 lakhs + 20% of 5 lakhs + 75% of 80 thousand 2

= 3 lakhs + 1 lakhs + 60 thousand = 4 lakhs 60 thousand

Remaining Gold = 6 lakhs – 3 lakhs = 3 lakhs

Remaining Land = 5 lakhs – 1 lakhs = 4 lakhs

Remaining Cash = 80000 – 60000 = 20000

The share of son A = (1/2) of remaining gold + (3/4) of remaining land + (1/2) of remaining cash

= 1.5 lakhs + 3 lakhs + 10 thousand = 4.6 lakhs

The share of son B = (1/2) of remaining gold + (1/4) of remaining land + (1/2) of remaining cash

= 1.5 lakhs + 1 lakhs + 10 thousand = 2.6 lakhs
3
After dividing the property, the father had lived for another 10 years, then the son who had received the highest share of land was left with how much total property after 10years ?
» Explain it
D
Following common explanation, we get

In 10 years 10 × 12 = 120 months

He will pay to his father in 120 months = 120 × 2500 = 3 lakhs

The share of property he was left with = 4.6 – 3 = 1.6 lakhs

Hence, option D is correct.

Common explanation :

The total share of daughter = half of gold + 20% of land + 75% of cash amount

 = 6 lakhs + 20% of 5 lakhs + 75% of 80 thousand 2

= 3 lakhs + 1 lakhs + 60 thousand = 4 lakhs 60 thousand

Remaining Gold = 6 lakhs – 3 lakhs = 3 lakhs

Remaining Land = 5 lakhs – 1 lakhs = 4 lakhs

Remaining Cash = 80000 – 60000 = 20000

The share of son A = (1/2) of remaining gold + (3/4) of remaining land + (1/2) of remaining cash

= 1.5 lakhs + 3 lakhs + 10 thousand = 4.6 lakhs

The share of son B = (1/2) of remaining gold + (1/4) of remaining land + (1/2) of remaining cash

= 1.5 lakhs + 1 lakhs + 10 thousand = 2.6 lakhs
4
The share of land received by Son A was how much percentage more than that by daughter C?
» Explain it
B
Following common explanation, we get

The share of son A in land = 3 lakhs

The share of daughter C in land = 1 lakhs

 The reqd. % = (3 – 1) × 100 = 200% 1

Hence, option B is correct.

Common explanation :

The total share of daughter = half of gold + 20% of land + 75% of cash amount

 = 6 lakhs + 20% of 5 lakhs + 75% of 80 thousand 2

= 3 lakhs + 1 lakhs + 60 thousand = 4 lakhs 60 thousand

Remaining Gold = 6 lakhs – 3 lakhs = 3 lakhs

Remaining Land = 5 lakhs – 1 lakhs = 4 lakhs

Remaining Cash = 80000 – 60000 = 20000

The share of son A = (1/2) of remaining gold + (3/4) of remaining land + (1/2) of remaining cash

= 1.5 lakhs + 3 lakhs + 10 thousand = 4.6 lakhs

The share of son B = (1/2) of remaining gold + (1/4) of remaining land + (1/2) of remaining cash

= 1.5 lakhs + 1 lakhs + 10 thousand = 2.6 lakhs
5
What was the respective ratio of the total property received by son A and that by son B?
» Explain it
D
Following common explanation, we get

The share of son A in total property = 4.6 lakhs

The share of son B in total property = 2.6 lakhs

The required ratio = 4.6 : 2.6 = 23 : 13

Hence, option D is correct.

Common explanation :

The total share of daughter = half of gold + 20% of land + 75% of cash amount

 = 6 lakhs + 20% of 5 lakhs + 75% of 80 thousand 2

= 3 lakhs + 1 lakhs + 60 thousand = 4 lakhs 60 thousand

Remaining Gold = 6 lakhs – 3 lakhs = 3 lakhs

Remaining Land = 5 lakhs – 1 lakhs = 4 lakhs

Remaining Cash = 80000 – 60000 = 20000

The share of son A = (1/2) of remaining gold + (3/4) of remaining land + (1/2) of remaining cash

= 1.5 lakhs + 3 lakhs + 10 thousand = 4.6 lakhs

The share of son B = (1/2) of remaining gold + (1/4) of remaining land + (1/2) of remaining cash

= 1.5 lakhs + 1 lakhs + 10 thousand = 2.6 lakhs

### Caselet DI | Caselet Data Interpretation for IBPS PO Pre, IBPS Clerk Mains 2019

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Caselet Data Interpretation is an important part in all bank exams. Here we at Smartkeeda.com we will learn a New Pattern Based DI, Which is Called Caselet DI, These days Caselet DI freequenty asked in all major Bank exams IBPS PO Pre, IBPS Clerk. It has a lot chance to appear in IBPS PO 2019 and IBPS Clerk 2019.

We provide you data interpretation quiz with answers and explanation.

Aspirants preparing for IBPS PO exams for the year 2019 can practice these questions. Let us now understand, what exactly is a Caselet DI. Data interpretation normally consists of questions involving pie charts, bar graphs, line graphs, radar graphs pr table with the required information for solving the questions. In a paragraph type data interpretation question, a set of information is provided in a paragraph form. It doesn’t consist of any charts or tables. You have to read the given information carefully and draw a suitable table/chart listing out all the given data to answer the questions.

So, First of all, whenever exams authorities come up with new kind of questions, students raise one query, "How to Solve New Pattern Based Caselet Data Interpretation". So first we discuss
How to solve caselets/paragraph/Info Chart data interpretation questions?

Given Below steps will help you all while solving questions of Caselet or paragraph based Data Interpretation questions in IBPS PO, IBPS Clerk Exams. Data Interpretation for IBPS PO Pre, IBPS Clerk 2019 with PDF.

I. While Solving Caselet DI involves a thorough understanding of the subject matter of the passage given. Read the paragraph with the utmost care and analyze what the question demands. Basically, be clear on what is given and what is asked.

II. Try to underline all the important points in a Caselet Data Interpretation while reading it. You can always use symbols in place of names of persons, places etc to make your work a lot easier. Focus only on useful data and don’t do unnecessary approximations just to simplify the task.

III. With all the important information in your hand, try to represent the data in graphical or tabular form. Represent the data in a pie chart, bar graph, table etc depending upon the feasibility and the motive of the question.

IV. Read the figures closely. You can use options and approximations to avoid tedious and lengthy calculations. If the question asks for relative values, there is no need to find accurate values. Use approximation but never over-approximate.

Sks Here are some points you need to remember:

I. Improve your calculation speed: Caselets being calculation intensive, you have to be good with your calculations. Learn speed math techniques and practice them regularly. The more you practice the faster you become in calculations. After a considerable amount of practice, you can do the calculations in your mind. This is going to save a lot of your precious time in exam conditions. So build a intuitive number sense.

II. Be thorough with the arithmetic related topics like percentages, interests, ratios and proportions as Caselet DI are often based on these type of concepts. Otherwise you will face a lot off difficulty tackling these questions. Get the basics; understand the difference between growth and growth rate, average growth rate, cumulative average growth rate, market share by volume and market share revenue etc.

III. Practice makes a man perfect. The more you practice these types of questions, the easier the questions will become. Practice questions will improve your speed and accuracy. While attempting these type of questions in exam, always try to choose the questions which will give you the answer with lesser effort, or you will end up spending a significant amount of time on lengthy calculations.
Caselet DI is frequently being asked these days and so we must practice this in the form of quizzes as Smartkeeda Caselet Data Interpretation Quiz for Free of Cost. So, Caselet DI is not new or not even out of way. It is just a mathematical form of English Passage. In Caselet DI, a long paragraph is given and on the basis of that. Candidates can download data interpretation quiz with solutions for banking and other competitive examination.

In the above paragraph of "Caselet DI", lots of information is given. You have to read the paragraph carefully and then you have to note down all the key information as short as possible. The given information will let you draw some diagrams such as Venn diagram, tabular chart or any other diagram.

The difference between simple DI and Caselet DI is - In simple DI, information is already given in diagrammatical forms but in Caselet DI, you have to draw a diagram on the basis of given information

Before start solving Caselet DI, you must have knowledge of the following 7 key things:

1. How to draw a diagram on the basis of given information.

2. Which diagram is the need for the question?

3. Knowledge of Venn diagram.

4. Knowledge of the relationship between fractions and their percentage forms.

5. Knowledge of simplification and approximation.

6. If the question belongs to CI & SI or Profit & Loss or Speed, time and distance then you must have knowledge of basic formulae of these topics.

7. Must have knowledge of Ratio and Proportion.

So, in the above information chart or Caselet Chart or Passage Chart, you will see all the rules are following properly. While attempting Caselet DI you can even save your time in exam only one condition if you do practice a lot which trough you can create Image or differentiate the data and After that, you can answer easily.'

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