Directions  : Study the following information carefully and answer the questions given beside.

In an examination, six subjects - A, B, C, D, E, and F have equal maximum marks. The number of marks scored by one particular candidate in subject A is 20% less than his marks in subject F. The ratio of marks scored by the same candidate in subject B to that in C is 4 : 5 and that in D to E is 3 : 4. The number of marks scored by this candidate in subject E is 25% more than that of F. He scored 65 marks in the subject C. He scored 436/9 % in the examination and the average of marks scored by him in all the subjects is 218/3. 
1
What was the total marks in the examination?
» Explain it
D
From the following common explanation, we get

The total marks = 900 

Hence, option D is correct.

Common explanation : 

Let the marks scored by the candidate in the subject F = 10x then

The marks scored by the candidate in the subject A = 80% of 10x = 8x

The ratio of marks scored in B to that in C is 4 : 5 and that D to E is 3 : 4. The number of marks scored by the candidate in E is 25% more than that of F

In E, the marks obtained = 125% of 10x =  25x  = 4a
2

Then, the marks obtained in D =  3 × 25x  =  75x
2 × 4 8

The marks obtained in C = 5y = 65
 
The marks obtained in B = 4y =  65 × 4  = 52
5

According to the question,
 
A + B + C + D + E + F =  218 × 6
3

8x + 52 + 65 +  75x  +  25x  + 10x = 436
8 2

8x +  75x  +  25x  + 10x= 436 – 52 – 65 = 319
8 2

(64x + 75x + 100x + 80x) = 319 × 8

x = 8
 
The total marks = z then 48  4  % of z = 436
9

By solving, z =  436 × 900  = 900
436
2
What percentage of marks the candidate had scored in the subject E over the maximum marks of that subject?
» Explain it
D
From the following common explanation, we get

The marks of each subject =  900  = 150
6

The marks obtained by the candidate in the subject E

25x  = 100
2

The reqd. % =  100 × 100  = 66.66%
150

Hence, option D is correct.

Common explanation : 

Let the marks scored by the candidate in the subject F = 10x then
 
The marks scored by the candidate in the subject A = 80% of 10x = 8x

The ratio of marks scored in B to that in C is 4 : 5 and that D to E is 3 : 4. The number of marks scored by the candidate in E is 25% more than that of F

In E, the marks obtained = 125% of 10x =  25x  = 4a
2

Then, the marks obtained in D =  3 × 25  =  75x
2 × 4 8

The marks obtained in C = 5y = 65
 
The marks obtained in B = 4y =  65 × 4  = 52
5

According to the question,

A + B + C + D + E + F =  218 × 6
3

8x + 52 + 65 +  75x  +  25x  + 10x = 436
8 2

8x +  75x  +  25x  + 10x= 436 – 52 – 65 = 319
8 2

(64x + 75x + 100x + 80x) = 319 × 8

x = 8

The total marks = z then 48  4  % of z = 436
9

By solving, z =  436 × 900  = 900
436
3
The number of marks obtained by the candidate in the subject B was how much less than in the subject D?
» Explain it
B
From the following common explanation, we get

The number of marks obtained by the candidate in the subject B = 52

The number of marks obtained by the candidate in the subject D

75x  = 75
8

The required difference = 75 – 52 = 23

Hence, option B is correct.

Common explanation : 

Let the marks scored by the candidate in the subject F = 10x then
 
The marks scored by the candidate in the subject A = 80% of 10x = 8x

The ratio of marks scored in B to that in C is 4 : 5 and that D to E is 3 : 4. The number of marks scored by the candidate in E is 25% more than that of F

In E, the marks obtained = 125% of 10x =  25x  = 4a
2

Then, the marks obtained in D =  3 × 25  =  75x
2 × 4 8

The marks obtained in C = 5y = 65

The marks obtained in B = 4y =  65 × 4  = 52
5

According to the question,

A + B + C + D + E + F  =  218 × 6
3

8x + 52 + 65 +  75x  +  25x  + 10x = 436
8 2

8x +  75x  +  25x  + 10x= 436 – 52 – 65 = 319
8 2

(64x + 75x + 100x + 80x) = 319 × 8

x = 8

The total marks = z then 48  4  % of z = 436
9

By solving, z =  436 × 900  = 900
436
4
What was the average of marks obtained by the candidate in the subject E and F together?
» Explain it
A
From the following common explanation, we get

The sum of the marks obtained by the candidate in the subject E and F together = 100 + 80 

The reqd. average =  180  = 90
2

Hence, option A is correct.

Common explanation : 

Let the marks scored by the candidate in the subject F = 10x then
 
The marks scored by the candidate in the subject A = 80% of 10x = 8x

The ratio of marks scored in B to that in C is 4 : 5 and that D to E is 3 : 4. The number of marks scored by the candidate in E is 25% more than that of F

In E, the marks obtained = 125% of 10x =  25x  = 4a
2

Then, the marks obtained in D =  3 × 25  =  75x
2 × 4 8

The marks obtained in C = 5y = 65

The marks obtained in B = 4y =  65 × 4  = 52
5

According to the question,

A + B + C + D + E + F =  218 × 6
3

8x + 52 + 65 +  75x  +  25x  + 10x = 436
8 2

8x +  75x  +  25x  + 10x= 436 – 52 – 65 = 319
8 2

(64x + 75x + 100x + 80x) = 319 × 8

x = 8

The total marks = z then 48  4  % of z = 436
9

By solving, z =  436 × 900  = 900
436
5
The number of marks obtained by the candidate in the subject C was how much percentage less than that of subject E?
» Explain it
D
 From the following common explanation, we get

The number of marks obtained by the candidate in the subject C = 65 
 
The number of marks obtained by the candidate in the subject E = 100 

The reqd. % =  (100 – 65) × 100  = 35%
100

Hence, option D is correct.

Common explanation : 

Let the marks scored by the candidate in the subject F = 10x then
 
The marks scored by the candidate in the subject A = 80% of 10x = 8x

The ratio of marks scored in B to that in C is 4 : 5 and that D to E is 3 : 4. The number of marks scored by the candidate in E is 25% more than that of F

In E, the marks obtained = 125% of 10x =  25x  = 4a
2

Then, the marks obtained in D =  3 × 25  =  75x
2 × 4 8

The marks obtained in C = 5y = 65

The marks obtained in B = 4y =  65 × 4  = 52
5

According to the question,

A + B + C + D + E + F =  218 × 6
3

8x + 52 + 65 +  75x  +  25x  + 10x = 436
8 2

8x +  75x  +  25x  + 10x= 436 – 52 – 65 = 319
8 2

(64x + 75x + 100x + 80x) = 319 × 8

x = 8

The total marks = z then 48  4  % of z = 436
9

By solving, z =  436 × 900  = 900
436

Caselet DI | Caselet Data Interpretation for IBPS PO Pre, IBPS Clerk Mains 2019


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Caselet Data Interpretation is an important part in all bank exams. Here we at Smartkeeda.com we will learn a New Pattern Based DI, Which is Called Caselet DI, These days Caselet DI freequenty asked in all major Bank exams IBPS PO Pre, IBPS Clerk. It has a lot chance to appear in IBPS PO 2019 and IBPS Clerk 2019.

We provide you data interpretation quiz with answers and explanation.

Aspirants preparing for IBPS PO exams for the year 2019 can practice these questions. Let us now understand, what exactly is a Caselet DI. Data interpretation normally consists of questions involving pie charts, bar graphs, line graphs, radar graphs pr table with the required information for solving the questions. In a paragraph type data interpretation question, a set of information is provided in a paragraph form. It doesn’t consist of any charts or tables. You have to read the given information carefully and draw a suitable table/chart listing out all the given data to answer the questions.

So, First of all, whenever exams authorities come up with new kind of questions, students raise one query, "How to Solve New Pattern Based Caselet Data Interpretation". So first we discuss
How to solve caselets/paragraph/Info Chart data interpretation questions?

Given Below steps will help you all while solving questions of Caselet or paragraph based Data Interpretation questions in IBPS PO, IBPS Clerk Exams. Data Interpretation for IBPS PO Pre, IBPS Clerk 2019 with PDF.

I. While Solving Caselet DI involves a thorough understanding of the subject matter of the passage given. Read the paragraph with the utmost care and analyze what the question demands. Basically, be clear on what is given and what is asked.

II. Try to underline all the important points in a Caselet Data Interpretation while reading it. You can always use symbols in place of names of persons, places etc to make your work a lot easier. Focus only on useful data and don’t do unnecessary approximations just to simplify the task.

III. With all the important information in your hand, try to represent the data in graphical or tabular form. Represent the data in a pie chart, bar graph, table etc depending upon the feasibility and the motive of the question.

IV. Read the figures closely. You can use options and approximations to avoid tedious and lengthy calculations. If the question asks for relative values, there is no need to find accurate values. Use approximation but never over-approximate.

Sks Here are some points you need to remember:

I. Improve your calculation speed: Caselets being calculation intensive, you have to be good with your calculations. Learn speed math techniques and practice them regularly. The more you practice the faster you become in calculations. After a considerable amount of practice, you can do the calculations in your mind. This is going to save a lot of your precious time in exam conditions. So build a intuitive number sense.
 
II. Be thorough with the arithmetic related topics like percentages, interests, ratios and proportions as Caselet DI are often based on these type of concepts. Otherwise you will face a lot off difficulty tackling these questions. Get the basics; understand the difference between growth and growth rate, average growth rate, cumulative average growth rate, market share by volume and market share revenue etc.

III. Practice makes a man perfect. The more you practice these types of questions, the easier the questions will become. Practice questions will improve your speed and accuracy. While attempting these type of questions in exam, always try to choose the questions which will give you the answer with lesser effort, or you will end up spending a significant amount of time on lengthy calculations.
Caselet DI is frequently being asked these days and so we must practice this in the form of quizzes as Smartkeeda Caselet Data Interpretation Quiz for Free of Cost. So, Caselet DI is not new or not even out of way. It is just a mathematical form of English Passage. In Caselet DI, a long paragraph is given and on the basis of that. Candidates can download data interpretation quiz with solutions for banking and other competitive examination.

In the above paragraph of "Caselet DI", lots of information is given. You have to read the paragraph carefully and then you have to note down all the key information as short as possible. The given information will let you draw some diagrams such as Venn diagram, tabular chart or any other diagram.

The difference between simple DI and Caselet DI is - In simple DI, information is already given in diagrammatical forms but in Caselet DI, you have to draw a diagram on the basis of given information

Before start solving Caselet DI, you must have knowledge of the following 7 key things:

1. How to draw a diagram on the basis of given information.

2. Which diagram is the need for the question?

3. Knowledge of Venn diagram.

4. Knowledge of the relationship between fractions and their percentage forms.

5. Knowledge of simplification and approximation.

6. If the question belongs to CI & SI or Profit & Loss or Speed, time and distance then you must have knowledge of basic formulae of these topics.

7. Must have knowledge of Ratio and Proportion.

So, in the above information chart or Caselet Chart or Passage Chart, you will see all the rules are following properly. While attempting Caselet DI you can even save your time in exam only one condition if you do practice a lot which trough you can create Image or differentiate the data and After that, you can answer easily.'

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