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In Pitampura area of Delhi, there are 1200 people living in five different apartments, viz Drishti, Paradise, Umang, Maurya and Kala Kunj. The number of males in 24 more than the number of females. One-fourth of the total number of population are in Umang apartment. 16% of the total number of population are living in Drishti apartment.

Maurya apartment has 50 people more than Drishti apartment. The ratio of the number of males to females is 3 : 1 in Drishti apartment. The number of people in Kala Kunj is 20 more than the number of people living in Drishti apartment.

There are equal numbers of males and females living in Maurya apartment. 50 percent of the population of Paradise Apartment are males. Three-fourths of the population of Kala Kunj apartment are famales.

Important for :

1

C

Let the number of females be xSo, the number of males = x + 24

According to the question,

x + x + 24 = 1200

∴ x = 588

So, the number of females = 588

Number of males = 588 + 24 = 612

Total no. of population in Umang apartment

= | 1 | × 1200 = 300 |

4 |

Total no. of population in Drishti apartment

= | 16 | × 1200 = 192 |

100 |

Total no. of population in Maurya apartment = 192 + 50 = 242

Total no. of population in Kala kunj = 192 + 20 = 212

Total no. of population in Paradise = 1200 – 300 – 192 – 242 – 212 = 254

Now, the no. of males in Drishti apartment

= | 3 | × 192 = 144 |

4 |

No. of females in Drishti apartment

= | 1 | × 192 = 48 |

4 |

No. of males in Maurya apartment = 121

No. of females in Maurya apartment = 121

No. of males in Paradise apartment = 127

No. of females in Paradise apartment = 127

∴ No. of females in Kala Kunj = |
3 | × 212 = 159 |

4 |

No. of males in Kala Kunj = 53

Number of females in Umang = 133

_______________________________

Total no. of females in Drishti and Kala Kunj apartments = 48 + 159 = 207

Total number of males in Paradise and Umang apartments = 127 + 167 = 294

2

A

Let the number of females be xSo, the number of males = x + 24

According to the question,

x + x + 24 = 1200

∴ x = 588

So, the number of females = 588

Number of males = 588 + 24 = 612

Total no. of population in Umang apartment

= | 1 | × 1200 = 300 |

4 |

Total no. of population in Drishti apartment

= | 16 | × 1200 = 192 |

100 |

Total no. of population in Maurya apartment = 192 + 50 = 242

Total no. of population in Kala kunj = 192 + 20 = 212

Total no. of population in Paradise = 1200 – 300 – 192 – 242 – 212 = 254

Now, the no. of males in Drishti apartment

= | 3 | × 192 = 144 |

4 |

No. of females in Drishti apartment

= | 1 | × 192 = 48 |

4 |

No. of males in Maurya apartment = 121

No. of females in Maurya apartment = 121

No. of males in Paradise apartment = 127

No. of females in Paradise apartment = 127

∴ No. of females in Kala Kunj = |
3 | × 212 = 159 |

4 |

No. of males in Kala Kunj = 53

Number of females in Umang = 133

_____________________________

Reqd ratio = | 254 | = 127 : 106 |

212 |

3

C

Let the number of females be xSo, the number of males = x + 24

According to the question,

x + x + 24 = 1200

∴ x = 588

So, the number of females = 588

Number of males = 588 + 24 = 612

Total no. of population in Umang apartment

= | 1 | × 1200 = 300 |

4 |

Total no. of population in Drishti apartment

= | 16 | × 1200 = 192 |

100 |

Total no. of population in Maurya apartment = 192 + 50 = 242

Total no. of population in Kala kunj = 192 + 20 = 212

Total no. of population in Paradise = 1200 – 300 – 192 – 242 – 212 = 254

Now, the no. of males in Drishti apartment

= | 3 | × 192 = 144 |

4 |

No. of females in Drishti apartment

= | 1 | × 192 = 48 |

4 |

No. of males in Maurya apartment = 121

No. of females in Maurya apartment = 121

No. of males in Paradise apartment = 127

No. of females in Paradise apartment = 127

∴ No. of females in Kala Kunj = |
3 | × 212 = 159 |

4 |

No. of males in Kala Kunj = 53

Number of females in Umang = 133

_____________________________

Reqd% = | 167 | × 100 = 28.401% ≈ 28.40% |

588 |

4

D

Let the number of females be xSo, the number of males = x + 24

According to the question,

x + x + 24 = 1200

∴ x = 588

So, the number of females = 588

Number of males = 588 + 24 = 612

Total no. of population in Umang apartment

= | 1 | × 1200 = 300 |

4 |

Total no. of population in Drishti apartment

= | 16 | × 1200 = 192 |

100 |

Total no. of population in Maurya apartment = 192 + 50 = 242

Total no. of population in Kala kunj = 192 + 20 = 212

Total no. of population in Paradise = 1200 – 300 – 192 – 242 – 212 = 254

Now, the no. of males in Drishti apartment

= | 3 | × 192 = 144 |

4 |

No. of females in Drishti apartment

= | 1 | × 192 = 48 |

4 |

No. of males in Maurya apartment = 121

No. of females in Maurya apartment = 121

No. of males in Paradise apartment = 127

No. of females in Paradise apartment = 127

∴ No. of females in Kala Kunj = |
3 | × 212 = 159 |

4 |

No. of males in Kala Kunj = 53

Number of females in Umang = 133

_____________________________

Reqd ratio = | 127 | = 127 : 121 |

121 |

5

A

Let the number of females be xSo, the number of males = x + 24

According to the question,

x + x + 24 = 1200

∴ x = 588

So, the number of females = 588

Number of males = 588 + 24 = 612

Total no. of population in Umang apartment

= | 1 | × 1200 = 300 |

4 |

Total no. of population in Drishti apartment

= | 16 | × 1200 = 192 |

100 |

Total no. of population in Maurya apartment = 192 + 50 = 242

Total no. of population in Kala kunj = 192 + 20 = 212

Total no. of population in Paradise = 1200 – 300 – 192 – 242 – 212 = 254

Now, the no. of males in Drishti apartment

= | 3 | × 192 = 144 |

4 |

No. of females in Drishti apartment

= | 1 | × 192 = 48 |

4 |

No. of males in Maurya apartment = 121

No. of females in Maurya apartment = 121

No. of males in Paradise apartment = 127

No. of females in Paradise apartment = 127

∴ No. of females in Kala Kunj = |
3 | × 212 = 159 |

4 |

No. of males in Kala Kunj = 53

Number of females in Umang = 133

_____________________________

Avg population = | 254 + 300 + 212 | = | 766 | = 255 | 1 | ≈ 255 |

3 | 3 | 3 |