- DI Info Chart 39
- DI Info Chart 38
- DI Info Chart 37
- DI Info Chart 36
- DI Info Chart 35
- DI Info Chart 34
- DI Info Chart 33
- DI Info Chart 32
- DI Info Chart 31
- DI Info Chart 30
- DI Info Chart 29
- DI Info Chart 28
- DI Info Chart 27
- DI Info Chart 26
- DI Info Chart 25
- DI Info Chart 24
- DI Info Chart 23
- DI Info Chart 22
- DI Info Chart 21
- DI Info Chart 20
- DI Info Chart 19
- DI Info Chart 18
- DI Info Chart 17
- DI Info Chart 16
- DI Info Chart 15
- DI Info Chart 14
- DI Info Chart 13
- DI Info Chart 12
- DI Info Chart 11
- DI Info Chart 10
- DI Info Chart 9
- DI Info Chart 8
- DI Info Chart 7
- DI Info Chart 6
- DI Info Chart 5
- DI Info Chart 4
- DI Info Chart 3
- DI Info Chart 2
- DI Info Chart 1

Five persons A, B, C, D and E were employed to complete a piece of work.

⇒ All the five persons A, B, C, D and E worked for different number of days, i.e. 5, 4, 4, 4 and ‘n’ days respectively.

⇒ The percentage of work done by A, B, C and E is 25%, 20%, 10% and 20% respectively and the remaining percentage of work is done by D.

Important for :

1

A

A does 25% of work in 5 days, 100% work will be done in 20 daysD does [100 – (25 + 20 + 10 + 20)] = 25% of work in 4 days, 100% work will be done in 16 days

Total work = LCM (20, 16) = 80 units

A does = | 80 | = 4 units/day |

20 |

D does = | 80 | = 5 units/day |

16 |

A + D = 4 + 5 = 9 units/day

So, total work will be done in = | 80 | days |

9 |

Hence, option A is correct.

2

3

C

A’s efficiency 20 days to do whole work

B’s efficiency 20 days to do whole work

C’s efficiency 40 days to do whole work

D’s efficiency 16 days to do whole work

Total units of work = LCM(20, 20, 40, 16) = 80 units

A = 4 units/day

B = 4 units/day

C = 2 units/day

D = 5 units/day

40% of whole work is = 80 × 0.4 = 32 units

A + B = 4 + 4 = 8 units/day

B + C = 4 + 2 = 6 units/day

C + D = 2 + 5 = 7 units/day

Now left amount of target work after 3 days = 32 – (8 + 6 + 7) = 11 units

4th day work done = A + B = 8, so left = 11 – 8 = 3

So the next 3 units will be done by B and C together in haf day only.

The required answer is = 4.5 days

Hence, option C is correct.

4

C

A, B, C and D separately can do the work in 20, 20, 40 and 16 days respectively.Total work = LCM (20, 20, 40, 16) = 320 units [ For ease of calculation 320 is taken as LCM and not 80]

A = 16 units/day

B = 16 units/day

C = 8 units/day

D = 20 units/day

A + B = 16 + 16 = 32 units/day

B + C = 16 + 8 = 24 units/day

20% work will be done in

= | (320 × 20/100) | = 2 days (by A and B) |

32 |

50% of the left work will be done in

= | 320 – 64 | = | 128 | = 6.4 days (by D) |

2 | 20 |

Rest is done = | 128 | = 5.33 days (by B and C) |

24 |

The answer is = 2 + 6.4 + 5.33 = 13.73 days

Hence, option C is correct.

5