A & B, B & C, C & D do the work in the given combination and order as given respectively and the cycle repeats, then in how many days 40% work will be done?
20% of the work was done by A and B, then 50% of the left work was done by D and at last the rest of work was done by B and C. Find the number of total days taken to do the whole work.
F alone takes 15 more days than A alone to complete the whole work. If F works with 50% more efficiency, then in how many days he can do the whole work alone?
