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Krishna invested some money under 20% per annum simple interest in Axis bank. At the end of one – year, he withdrew all amount from the Axis bank and invested in Bandhan bank at the rate of R % per annum under compound interest compounded annually for two years and received Rs. 57600 as total interest from the Bandhan bank. The first year’s interest at Bandhan bank was Rs. 24000.

Important for :

1

D

Following the common explanation, we getAt 40% per annum, 120x gives compound interest of 57600 in two years or Rs. 24000 in one year

CI = P | ( | 1 + | R | ) |
^{N} |
– P |

100 |

120x | ( | 1 + | 40 | ) | – 120x = 24000 |

100 |

120x × 1.4 – 120x = 24000

168x – 120x = 48x = 24000

x = | 24000 | = 500 |

48 |

The sum of money he had invested in Axis bank = 100x = 100 × 500 = Rs. 50000

Hence, option D is correct.

Let the sum of money he invested in Axis bank = 100x then at the end of one year

Amount = | 100x × 1 × 20 | + 100x= 120x |

100 |

The CI of 2 years = 57600

The CI of 1 year = 24000

Difference = 57600 – 24000 = 33600

Now, 33600 – 24000 = 9600

At R% per annum, 24000 gives compound interest of Rs. 9600

24000 × R | = 9600 |

100 |

R = 40% per annum

2

B

Following the common explanation, we getThe interest, Krishna received from Axis bank = 20x = 20 × 500 = 10,000

The interest from Bandhan bank = 57600

The required sum = 10,000 + 57600 = 67600

Hence, option B is correct.

Let the sum of money he invested in Axis bank = 100x then at the end of one year

Amount = | 100x × 1 × 20 | +100x = 120x |

100 |

The CI of 2 years = 57600

The CI of 1 year = 24000

Difference = 57600 – 24000 = 33600

Now, 33600 – 24000 = 9600

At R% per annum, 24000 gives compound interest of Rs. 9600

24000 × R | = 9600 |

100 |

R = 40% per annum

3

A

Following the common explanation, we get
P = 50000

R = 40%

1st year = 40% per annum SI

Next 2 years = 20% per annum CI

Amount at the end of 1st year i.e. received from the Axis bank = 50000 + 40% of 50000 = 70000

SI = 70000 – 50000 = 20000

From the Bandhan bank

CI = P | ( | 1 + | R | ) |
^{N} |
– P |

100 |

CI = 70000 | ( | 1 + | 20 | ) |
^{2} |
– 70000 |

100 |

CI = 30800

Total interest = 20000 + 30800 = 50800

The interest, Krishna received from Axis bank = 20x = 20 × 500 = 10,000

The interest from Bandhan bank = 57600

The required sum = 10,000 + 57600 = 67600

The required difference = 67600 – 50800 = 16800

Hence, option A is correct.

Let the sum of money he invested in Axis bank = 100x then at the end of one year

Amount = | 100x × 1 × 20 | + 100x = 120x |

100 |

The CI of 2 years = 57600

The CI of 1 year = 24000

Difference = 57600 – 24000 = 33600

Now, 33600 – 24000 = 9600

At R% per annum, 24000 gives compound interest of Rs. 9600

24000 × R | = 9600 |

100 |

R = 40% per annum

4

B

Following the common explanation, we getP = 50000

SI at the end of 3 years = | 50000 × 20 × 3 | = Rs. 30,000 |

100 |

Hence, option B is correct.

Let the sum of money he invested in Axis bank = 100x then at the end of one year

Amount = | 100x × 1 × 20 | +100x = 120x |

100 |

The CI of 2 years = 57600

The CI of 1 year = 24000

Difference = 57600 – 24000 = 33600

Now, 33600 – 24000 = 9600

At R% per annum, 24000 gives compound interest of Rs. 9600

24000 × R | = 9600 |

100 |

R = 40% per annum

5

C

Following the common explanation, we getP = 50,000

Let the interest received from the Axis bank = Rs. x then

the first year’s interest at Bandhan bank = 40% of (50000 + x) = x

20000 + 0.4x = x

0.6x = 20000

x = | 200000 | = | 100000 |

6 | 3 |

R = | SI × 100 |

P × T |

R = | (100000/3) × 100 | = | 1000 | = | 200 | % = 66 | 2 | % |

50000 × 1 | 15 | 3 | 3 |

Hence, option C is correct.

Let the sum of money he invested in Axis bank = 100x then at the end of one year

Amount = | 100x × 1 × 20 | +100x= 120x |

100 |

The CI of 2 years = 57600

The CI of 1 year = 24000

Difference = 57600 – 24000 = 33600

Now, 33600 – 24000 = 9600

At R% per annum, 24000 gives compound interest of Rs. 9600

24000 × R | = 9600 |

100 |

R = 40% per annum

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We provide you data interpretation quiz with answers and explanation.

Aspirants preparing for SBI PO exams for the year 2019 can practice these questions. Let us now understand, what exactly is a Caselet DI. Data interpretation normally consists of questions involving pie charts, bar graphs, line graphs, radar graphs pr table with the required information for solving the questions. In a paragraph type data interpretation question, a set of information is provided in a paragraph form. It doesn’t consist of any charts or tables. You have to read the given information carefully and draw a suitable table/chart listing out all the given data to answer the questions.

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Given Below steps will help you all while solving questions of Caselet or paragraph based Data Interpretation questions in SBI PO, SBI Clerk Exams. Data Interpretation for SBI PO Pre, SBI Clerk 2019 with PDF.

Sks Here are the some points you need to remember:

Caselet DI is frequently being asked these days and so we must practice this in the form of quizzes as Smartkeeda Caselt Data Interpretation Quiz for Free of Cost. So, Caselet DI is not new or not even out of way. It is just a mathematical form of English Passage. In Caselet DI, a long paragraph is given and on the basis of that. Candidates can download data interpretation quiz with solutions for banking and other competitive examination.

In the above paragraph of Caselet DI, lots of information is given. You have to read the paragraph carefully and then you have to note down all the key information as short as possible. The given information will let you draw some diagrams such as Venn diagram, tabular chart or any other diagram.

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So, in the above information chart or Caselet Chart or Passage Chart you will see all the rules are following properly. While attempting Caselet DI you can even save your time in exam only one condition if you do practice a lot which trough you can create Image or differentiate the data and After that you can answer easily.'

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