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The table shows the distance travelled by five different boats upstream and downstream in same time and the line chart shows the speed of stream

Boat | Distance (Upstream) | Distance (Downstream) |

P | 96 | 288 |

Q | 120 | 240 |

R | 100 | 220 |

S | 150 | 350 |

T | 180 | 540 |

Important for :

1

E

Ratio = (24 + 24) : (25 + 40)= 48 : 65

Hence, option E is correct.

Speed of Boat P in still water = a km/h

96 | = | 288 |

(a – 12) | (a + 12) |

96 (a + 12) = 288 (a – 12)

96a + 1152 = 288a – 3456

3456 + 1152 = 288a – 96a

a = 24 km/h

Speed of Boat Q in still water = b km/h

120 | = | 240 |

(b – 8) | (b + 8) |

120 (b + 8) = 240 (b – 8)

120b + 960 = 240b – 1920

1920 + 960 = 240b – 120b

b = 24 km/h

Speed of Boat R in still water = c km/h

100 | = | 220 |

(c – 15) | (c + 15) |

100 (c + 15) = 220 (c – 15)

100c + 1500 = 220c – 3300

3300 + 1500 = 220c – 100c

c = 40 km/h

Speed of Boat S in still water = d km/h

150 | = | 350 |

(d – 10) | (d + 10) |

150 (d + 10) = 350 (d – 10)

150d + 1500 = 350d – 3500

3500 + 1500 = 350d – 150d

d = 25 km/h

Speed of Boat T in still water = e km/h

180 | = | 540 |

(e – 20) | (e + 20) |

180 (e + 20) = 540 (e – 20)

180e + 3600 = 540e – 10800

10800 + 3600 = 540e – 180e

e = 40 km/h

2

A

Speed of Boat R in still water = 40 × 110% = 44 km/hSpeed of stream = 15 × 120% = 18 km/h

Time taken by Boat R to cover the distance of 91 km upstream = 91/ (44 – 18)

= 91/ 26 = 3.5 hours

Hence, option A is correct.

Speed of Boat P in still water = a km/h

96 | = | 288 |

(a – 12) | (a + 12) |

96 (a + 12) = 288 (a – 12)

96a + 1152 = 288a – 3456

3456 + 1152 = 288a – 96a

a = 24 km/h

Speed of Boat Q in still water = b km/h

120 | = | 240 |

(b – 8) | (b + 8) |

120 (b + 8) = 240 (b – 8)

120b + 960 = 240b – 1920

1920 + 960 = 240b – 120b

b = 24 km/h

Speed of Boat R in still water = c km/h

100 | = | 220 |

(c – 15) | (c + 15) |

100 (c + 15) = 220 (c – 15)

100c + 1500 = 220c – 3300

3300 + 1500 = 220c – 100c

c = 40 km/h

Speed of Boat S in still water = d km/h

150 | = | 350 |

(d – 10) | (d + 10) |

150 (d + 10) = 350 (d – 10)

150d + 1500 = 350d – 3500

3500 + 1500 = 350d – 150d

d = 25 km/h

Speed of Boat T in still water = e km/h

180 | = | 540 |

(e – 20) | (e + 20) |

180 (e + 20) = 540 (e – 20)

180e + 3600 = 540e – 10800

10800 + 3600 = 540e – 180e

e = 40 km/h

3

C

Total time = | 210 | + | 210 |

(40 – 20) | (40 + 20) |

= | 210 | + | 210 |

20 | 60 |

= 10.5 + 3.5 = 14 hours

Hence, option C is correct.

Hence, option C is correct.

Speed of Boat P in still water = a km/h

96 | = | 288 |

(a – 12) | (a + 12) |

96 (a + 12) = 288 (a – 12)

96a + 1152 = 288a – 3456

3456 + 1152 = 288a – 96a

a = 24 km/h

Speed of Boat Q in still water = b km/h

120 | = | 240 |

(b – 8) | (b + 8) |

120 (b + 8) = 240 (b – 8)

120b + 960 = 240b – 1920

1920 + 960 = 240b – 120b

b = 24 km/h

Speed of Boat R in still water = c km/h

100 | = | 220 |

(c – 15) | (c + 15) |

100 (c + 15) = 220 (c – 15)

100c + 1500 = 220c – 3300

3300 + 1500 = 220c – 100c

c = 40 km/h

Speed of Boat S in still water = d km/h

150 | = | 350 |

(d – 10) | (d + 10) |

150 (d + 10) = 350 (d – 10)

150d + 1500 = 350d – 3500

3500 + 1500 = 350d – 150d

d = 25 km/h

Speed of Boat T in still water = e km/h

180 | = | 540 |

(e – 20) | (e + 20) |

180 (e + 20) = 540 (e – 20)

180e + 3600 = 540e – 10800

10800 + 3600 = 540e – 180e

e = 40 km/h

4

D

Speed of the Boat Q in still water = 24 km/hSpeed of the Boat U in still water = | 24 | × 5 = 30 km/h |

4 |

Let the speed of stream = x km/h

According to the question,

126 | + | 81 | = | 15 |

(30 + x) | (30 – x) | 2 |

126 (30 – x) + 81 (30 + x) | = | 15 |

(900 – x^{2}) |
2 |

2 (3780 – 126x + 2430 + 81x) = 15 (900 – x

2 (6210 – 45x) = 13500 – 15x

12420 – 90x = 13500 – 15x

15x

x

x

x (x – 12) + 6 (x – 12) = 0

(x + 6) (x – 12) = 0

x = –6, 12

Speed of stream = 12 km/h

Hence, option D is correct.

Speed of Boat P in still water = a km/h

96 | = | 288 |

(a – 12) | (a + 12) |

96 (a + 12) = 288 (a – 12)

96a + 1152 = 288a – 3456

3456 + 1152 = 288a – 96a

a = 24 km/h

Speed of Boat Q in still water = b km/h

120 | = | 240 |

(b – 8) | (b + 8) |

120 (b + 8) = 240 (b – 8)

120b + 960 = 240b – 1920

1920 + 960 = 240b – 120b

b = 24 km/h

Speed of Boat R in still water = c km/h

100 | = | 220 |

(c – 15) | (c + 15) |

100 (c + 15) = 220 (c – 15)

100c + 1500 = 220c – 3300

3300 + 1500 = 220c – 100c

c = 40 km/h

Speed of Boat S in still water = d km/h

150 | = | 350 |

(d – 10) | (d + 10) |

150 (d + 10) = 350 (d – 10)

150d + 1500 = 350d – 3500

3500 + 1500 = 350d – 150d

d = 25 km/h

Speed of Boat T in still water = e km/h

180 | = | 540 |

(e – 20) | (e + 20) |

180 (e + 20) = 540 (e – 20)

180e + 3600 = 540e – 10800

10800 + 3600 = 540e – 180e

e = 40 km/h

5

C

According to the question,Speed of Boat Q and S in still water together = (25 + 24) = 49 km/h

Speed of stream of Boat Q and S together = 18 km/h

% more = | 49 – 18 | × 100 |

18 |

= | 31 | × 100 = 172.22% ≈ 170% |

18 |

Hence, option C is correct.

Speed of Boat P in still water = a km/h

96 | = | 288 |

(a – 12) | (a + 12) |

96 (a + 12) = 288 (a – 12)

96a + 1152 = 288a – 3456

3456 + 1152 = 288a – 96a

a = 24 km/h

Speed of Boat Q in still water = b km/h

120 | = | 240 |

(b – 8) | (b + 8) |

120 (b + 8) = 240 (b – 8)

120b + 960 = 240b – 1920

1920 + 960 = 240b – 120b

b = 24 km/h

Speed of Boat R in still water = c km/h

100 | = | 220 |

(c – 15) | (c + 15) |

100 (c + 15) = 220 (c – 15)

100c + 1500 = 220c – 3300

3300 + 1500 = 220c – 100c

c = 40 km/h

Speed of Boat S in still water = d km/h

150 | = | 350 |

(d – 10) | (d + 10) |

150 (d + 10) = 350 (d – 10)

150d + 1500 = 350d – 3500

3500 + 1500 = 350d – 150d

d = 25 km/h

Speed of Boat T in still water = e km/h

180 | = | 540 |

(e – 20) | (e + 20) |

180 (e + 20) = 540 (e – 20)

180e + 3600 = 540e – 10800

10800 + 3600 = 540e – 180e

e = 40 km/h

Data Interpreation chapter plays a major role in IBPS Clerk Mains exam. These days new pattern based DIs are getting featured in IBPS exams like Time and Distance DI, Boats and Stream DI, Time and Work based DI, Probability based DI. In line with it, one more thing that is being seen by our experts that IBPS always brings high level of Data Interepreation questions with its changing pattern for each and every exam. IBPS Clerk Mains exam is one of the most famous exams and Smartkeeda advises you to practise more and more DI based on Boats and Stream concept, Time and Distance concept and Time and Work concept at Smartkeeda. On this banking and ssc exams portal Smartkeeda your will find memory based DI questions with tricky method and DI asked in all the major bank exams like like SBI Clerk Pre, SBI Clerk Mains, IBPS Clerk Pre, IBPS Clerk Mains, SBI PO Pre, SBI PO Main, IBPS PO Pre, IBPS PO Mains, SSC CGL Tier 1, CDSE, CLAT, MAT, SSC LDC, SSC MTS, SSC DEO, SSC Stenographer, LIC AAO, NICL, Railways, IBPS RRB Office Assistant Pre, IBPS RRB Office Assistant Mains, IBPS RRB Officer Scale 1 Pre, IBPS RRB Officer Scale 1 Mains, SBI SO, IBPS SO, etc.