 # Double Pie Chart Data Interpretation Quiz and PDF for SBI PO Pre and SBI Clerk 2020, LIC ADO, LIC AAO 2020  Direction : Study the following pie chart carefully and answer the questions given beside.

Given pie chart shows the part of iron ore mined by 6 different machines in a day.

Total amount of iron ore that is mined in a day by 6 machines is 200 kg. Given pie chart shows the wasted per cent of iron ore which is mined by 6 different machines in a day while extracting Iron from them.

Total amount of wasted iron ore in a day which is mined by 6 machines together is 25 kg. Amount of mined Iron ore = Extracted amount of Iron + Wasted amount of Iron ore.
Important for :
1
What is total amount of Iron extracted from the Iron ore which is mined by the machine C and E together?
» Explain it
C
Total amount of Iron ore mined by machine C

 = 200 × 45 = 25 kg 360

Total wasted amount of Iron ore by machine C = 8% of 25 kg = 2 kg

Total amount of Iron ore mined by machine E
 = 200 × 90 = 50 kg 360

Total wasted amount of Iron ore by machine E = 28% of 25 kg = 7 kg

Total amount of Iron extracted = (25 + 50) – (2 + 7) = 75 – 9 = 66 kg

Hence, option C is correct.

2
What is the difference between the total amount of Iron extracted from Iron ore mined by machine D and total amount of Iron ore wasted by machine B and F together?
» Explain it
D
Total amount of Iron extracted from Iron ore mined by machine D

 = 200 × 36 = 20 kg 360

Wasted amount of Iron ore mined by machine D = 12% of 25 = 3 kg

Amount of Iron extracted from Iron ore mined by machine D = 20 – 3 = 17 kg

Total wasted amount of Iron ore mined by machine B and F together = 32% of 25 = 8 kg

Required difference = 17 – 8 = 9 kg

Hence, option D is correct.

3
Find that total wasted amount of Iron ore mined by machine A and C together is what per cent of total amount of Iron ore mined by machine F alone?
» Explain it
E
Total wasted amount of Iron ore mined by machine A and C together = (20 + 8)% of 25 = 7 kg

Total amount of Iron ore mined by machine F alone

 = 200 × 63 = 35 kg 360

 Reqd % = 7 × 100 = 20% 35

Hence, option E is correct.

4
Cost of Iron ore after mining is Rs.200 per kg and cost of Iron after extracting from Iron ore is Rs.250 per kg, then find the per cent profit of a person if he sold the Iron extracted from Iron ore mined by machine B instead of Iron ore mined by machine B itself.
» Explain it
B
Total amount of Iron ore mined by machine B

 = 200 × 72 = 40 kg 360

Total cost of Iron ore mined by machine B = 40 × 200 = 8000

Total wasted amount of Iron ore mined by machine B = 16% of 25 = 4 kg

Amount of Iron extracted from Iron ore = 40 – 4 = 36 kg

Total cost of Iron extracted from Iron ore by machine B = 36 × 250 = 9000
 Profit % = 9000 – 8000 × 100 = 12.5% 8000

Hence, option B is correct.

5
Due to rusting the amount of Iron extracted from Iron ore mined by machine E is decreased by 10% every year. Find the cost price of Iron extracted from Iron ore mined by machine E at the end of 2 years from now. Cost of Iron is Rs.200 per kg at present and remains same in future.
» Explain it
C
Total amount of Iron ore mined by machine E

 = 200 × 90 = 50 kg 360

Total wasted amount of Iron ore mined by machine E = 28% of 25 = 7 kg

Amount of Iron extracted from Iron ore at present = 50 – 7 = 43 kg

Amount of Iron extracted from Iron ore at the end of 2 years from present = 90% of 90% of 43 = 34.83 kg

Total cost of Iron extracted from Iron ore mined by machine E = 34.83 × 200 = Rs.6966

Hence, option C is correct.

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