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- Set No 21

Eight persons – Ajay, Bimal, Chander, Dhanush, Erik, Feroz, Gaurav and Harish are sitting around a circular table facing towards the centre. They have different amount of chocolates with them viz. 4, 7, 12, 17, 18, 21, 34 and 36. No two persons have same number of chocolates.

The person opposite to Bimal had 7 chocolates.

Ajay was sitting opposite to the person having 21 chocolates.

Ajay and Bimal were seated at a gap of two.

Harish was sitting third to the left of the one who had 18 chocolates.

Bimal had twice the number of chocolates that Erik had.

Harish and Gaurav were seated at a gap of 1 person.

The difference of the number of chocolates that Ajay and Bimal had was two, where the number of chocolates with Ajay was a perfect square.

Erik and Feroz had consecutive number of chocolates. The number of chocolates that Erik had was a prime number.

Gaurav had thrice the number of chocolates as that with Dhanush, who was sitting to the immediate right of Bimal.

The number of chocolates with Gaurav was opposite of the number of chocolates with Harish. i.e. if Harish has 'mn' number of chocolates, then Gaurav will have 'nm' number of chocolates.

Gaurav had less chocolates than Harish and the number of chocolates with both of them were in double digits.

The person opposite to Bimal had 7 chocolates.

Ajay was sitting opposite to the person having 21 chocolates.

Ajay and Bimal were seated at a gap of two.

Harish was sitting third to the left of the one who had 18 chocolates.

Bimal had twice the number of chocolates that Erik had.

Harish and Gaurav were seated at a gap of 1 person.

The difference of the number of chocolates that Ajay and Bimal had was two, where the number of chocolates with Ajay was a perfect square.

Erik and Feroz had consecutive number of chocolates. The number of chocolates that Erik had was a prime number.

Gaurav had thrice the number of chocolates as that with Dhanush, who was sitting to the immediate right of Bimal.

The number of chocolates with Gaurav was opposite of the number of chocolates with Harish. i.e. if Harish has 'mn' number of chocolates, then Gaurav will have 'nm' number of chocolates.

Gaurav had less chocolates than Harish and the number of chocolates with both of them were in double digits.

Important for :

1

B

From the following explanation it is clear that Chander has the seocnd least number of chocolates.

Hence option B is correct.

**Final Arrangement:**

Hence option B is correct.

Reference:

Gaurav had thrice the number of chocolates as that with Dhanush, who was sitting to the immediate right of Bimal.

The person opposite to Bimal had 7 chocolates.

The number of chocolates that Erik had was a prime number.

Bimal had twice the number of chocolates that Erik had.

They have different amount of chocolates with them viz. 4, 7,12, 17, 18, 21, 34 and 36.

From the given number of chocolates, prime numbers are 7 and 17 only. But twice of 7 is 14, which is not among the given numbers. Thus the number of chocolates with

Then as per the fourth hint, number of choclates with

Then for number of chocolates with Gaurav and Dhanush, as per our first hint there are only two combinations which are 4 – 12 and 7 – 21 among the given set of numbers.

But since we know that the person having 7 chocolates sits opposite to Bimal and Dhanush sits to the immediate right of Bimal, thus Dhanush will be having 4 chocolates.

So, the number of chocolates with

Persons |
No. of Chocolates |

Ajay | |

Bimal | 34 |

Chander | |

Dhanush | 4 |

Erik | 17 |

Feroz | |

Gaurav | 12 |

Harish |

Ajay was sitting opposite to the person having 21 chocolates.

The difference of the number of chocolates that Ajay and Bimal had was two, where the number of chocolates with Ajay was a perfect square.

Ajay and Bimal were seated at a gap of two.

The number of chocolates with Bimal is 34, and the difference between Ajay and Bimal's chocolates is 2, thus number of chocolates with

Persons |
No. of Chocolates |

Ajay | 36 |

Bimal | 34 |

Chander | |

Dhanush | 4 |

Erik | 17 |

Feroz | |

Gaurav | 12 |

Harish |

Harish was sitting third to the left of the one who had 18 chocolates.

Harish and Gaurav were seated at a gap of 1 person.

Erik and Feroz had consecutive number of chocolates.

The number of chocolates with Gaurav was opposite of the digits of the number of chocolates with Harish. i.e. if Harish has 'mn' number of chocolates, then Gaurav will have 'nm' number of chocolates.

Harish had more chocolates than Gaurav and the number of chocolates with both of them were in double digits.

We already know that Erik has 17 chocolates, so the number of chocolates with

Now the numbers left are - 7 and 21 and the persons left are Harish and Chander.

With the fourth hint it is clear that number of chocolates with

So

Persons |
No. of Chocolates |

Ajay | 36 |

Bimal | 34 |

Chander | 7 |

Dhanush | 4 |

Erik | 17 |

Feroz | 18 |

Gaurav | 12 |

Harish | 21 |

2

C

From the following explanation it is clear that "Dhanush – 4" is the correct combination.

Hence option C is correct.

**Final Arrangement:**

Hence option C is correct.

Reference:

Gaurav had thrice the number of chocolates as that with Dhanush, who was sitting to the immediate right of Bimal.

The person opposite to Bimal had 7 chocolates.

The number of chocolates that Erik had was a prime number.

Bimal had twice the number of chocolates that Erik had.

They have different amount of chocolates with them viz. 4, 7,12, 17, 18, 21, 34 and 36.

From the given number of chocolates, prime numbers are 7 and 17 only. But twice of 7 is 14, which is not among the given numbers. Thus the number of chocolates with

Then as per the fourth hint, number of choclates with

Then for number of chocolates with Gaurav and Dhanush, as per our first hint there are only two combinations which are 4 – 12 and 7 – 21 among the given set of numbers.

But since we know that the person having 7 chocolates sits opposite to Bimal and Dhanush sits to the immediate right of Bimal, thus Dhanush will be having 4 chocolates.

So, the number of chocolates with

Persons |
No. of Chocolates |

Ajay | |

Bimal | 34 |

Chander | |

Dhanush | 4 |

Erik | 17 |

Feroz | |

Gaurav | 12 |

Harish |

Ajay was sitting opposite to the person having 21 chocolates.

The difference of the number of chocolates that Ajay and Bimal had was two, where the number of chocolates with Ajay was a perfect square.

Ajay and Bimal were seated at a gap of two.

The number of chocolates with Bimal is 34, and the difference between Ajay and Bimal's chocolates is 2, thus number of chocolates with

Persons |
No. of Chocolates |

Ajay | 36 |

Bimal | 34 |

Chander | |

Dhanush | 4 |

Erik | 17 |

Feroz | |

Gaurav | 12 |

Harish |

Harish was sitting third to the left of the one who had 18 chocolates.

Harish and Gaurav were seated at a gap of 1 person.

Erik and Feroz had consecutive number of chocolates.

The number of chocolates with Gaurav was opposite of the digits of the number of chocolates with Harish. i.e. if Harish has 'mn' number of chocolates, then Gaurav will have 'nm' number of chocolates.

Harish had more chocolates than Gaurav and the number of chocolates with both of them were in double digits.

We already know that Erik has 17 chocolates, so the number of chocolates with

Now the numbers left are - 7 and 21 and the persons left are Harish and Chander.

With the fourth hint it is clear that number of chocolates with

So

Persons |
No. of Chocolates |

Ajay | 36 |

Bimal | 34 |

Chander | 7 |

Dhanush | 4 |

Erik | 17 |

Feroz | 18 |

Gaurav | 12 |

Harish | 21 |

3

A

The person having least number of chocolates is Dhanush and the person second to his left is Harish having 21 chocolates.

Ajay has 36 chocolates.

Required difference = 36 – 21 -> 15.

Thus, Ajay has 15 chocolates more than the one who sits second to the left of one who has the least number of chocolates.

Hence option A is correct.

**Final Arrangement:**

Ajay has 36 chocolates.

Required difference = 36 – 21 -> 15.

Thus, Ajay has 15 chocolates more than the one who sits second to the left of one who has the least number of chocolates.

Hence option A is correct.

Reference:

Gaurav had thrice the number of chocolates as that with Dhanush, who was sitting to the immediate right of Bimal.

The person opposite to Bimal had 7 chocolates.

The number of chocolates that Erik had was a prime number.

Bimal had twice the number of chocolates that Erik had.

They have different amount of chocolates with them viz. 4, 7,12, 17, 18, 21, 34 and 36.

From the given number of chocolates, prime numbers are 7 and 17 only. But twice of 7 is 14, which is not among the given numbers. Thus the number of chocolates with

Then as per the fourth hint, number of choclates with

Then for number of chocolates with Gaurav and Dhanush, as per our first hint there are only two combinations which are 4 – 12 and 7 – 21 among the given set of numbers.

But since we know that the person having 7 chocolates sits opposite to Bimal and Dhanush sits to the immediate right of Bimal, thus Dhanush will be having 4 chocolates.

So, the number of chocolates with

Persons |
No. of Chocolates |

Ajay | |

Bimal | 34 |

Chander | |

Dhanush | 4 |

Erik | 17 |

Feroz | |

Gaurav | 12 |

Harish |

Ajay was sitting opposite to the person having 21 chocolates.

The difference of the number of chocolates that Ajay and Bimal had was two, where the number of chocolates with Ajay was a perfect square.

Ajay and Bimal were seated at a gap of two.

The number of chocolates with Bimal is 34, and the difference between Ajay and Bimal's chocolates is 2, thus number of chocolates with

Persons |
No. of Chocolates |

Ajay | 36 |

Bimal | 34 |

Chander | |

Dhanush | 4 |

Erik | 17 |

Feroz | |

Gaurav | 12 |

Harish |

Harish was sitting third to the left of the one who had 18 chocolates.

Harish and Gaurav were seated at a gap of 1 person.

Erik and Feroz had consecutive number of chocolates.

The number of chocolates with Gaurav was opposite of the digits of the number of chocolates with Harish. i.e. if Harish has 'mn' number of chocolates, then Gaurav will have 'nm' number of chocolates.

Harish had more chocolates than Gaurav and the number of chocolates with both of them were in double digits.

We already know that Erik has 17 chocolates, so the number of chocolates with

Now the numbers left are - 7 and 21 and the persons left are Harish and Chander.

With the fourth hint it is clear that number of chocolates with

So

Persons |
No. of Chocolates |

Ajay | 36 |

Bimal | 34 |

Chander | 7 |

Dhanush | 4 |

Erik | 17 |

Feroz | 18 |

Gaurav | 12 |

Harish | 21 |

4

E

From the following explanation it is clear that the odd one out here is 'Harish' who has an odd number of chocolates.

Rest of the persons have even number of chocolates.

Hence option E is correct.

**Final Arrangement:**

Rest of the persons have even number of chocolates.

Hence option E is correct.

Reference:

Gaurav had thrice the number of chocolates as that with Dhanush, who was sitting to the immediate right of Bimal.

The person opposite to Bimal had 7 chocolates.

The number of chocolates that Erik had was a prime number.

Bimal had twice the number of chocolates that Erik had.

They have different amount of chocolates with them viz. 4, 7,12, 17, 18, 21, 34 and 36.

From the given number of chocolates, prime numbers are 7 and 17 only. But twice of 7 is 14, which is not among the given numbers. Thus the number of chocolates with

Then as per the fourth hint, number of choclates with

Then for number of chocolates with Gaurav and Dhanush, as per our first hint there are only two combinations which are 4 – 12 and 7 – 21 among the given set of numbers.

But since we know that the person having 7 chocolates sits opposite to Bimal and Dhanush sits to the immediate right of Bimal, thus Dhanush will be having 4 chocolates.

So, the number of chocolates with

Persons |
No. of Chocolates |

Ajay | |

Bimal | 34 |

Chander | |

Dhanush | 4 |

Erik | 17 |

Feroz | |

Gaurav | 12 |

Harish |

Ajay was sitting opposite to the person having 21 chocolates.

The difference of the number of chocolates that Ajay and Bimal had was two, where the number of chocolates with Ajay was a perfect square.

Ajay and Bimal were seated at a gap of two.

The number of chocolates with Bimal is 34, and the difference between Ajay and Bimal's chocolates is 2, thus number of chocolates with

Persons |
No. of Chocolates |

Ajay | 36 |

Bimal | 34 |

Chander | |

Dhanush | 4 |

Erik | 17 |

Feroz | |

Gaurav | 12 |

Harish |

Harish was sitting third to the left of the one who had 18 chocolates.

Harish and Gaurav were seated at a gap of 1 person.

Erik and Feroz had consecutive number of chocolates.

The number of chocolates with Gaurav was opposite of the digits of the number of chocolates with Harish. i.e. if Harish has 'mn' number of chocolates, then Gaurav will have 'nm' number of chocolates.

Harish had more chocolates than Gaurav and the number of chocolates with both of them were in double digits.

We already know that Erik has 17 chocolates, so the number of chocolates with

Now the numbers left are - 7 and 21 and the persons left are Harish and Chander.

With the fourth hint it is clear that number of chocolates with

So

Persons |
No. of Chocolates |

Ajay | 36 |

Bimal | 34 |

Chander | 7 |

Dhanush | 4 |

Erik | 17 |

Feroz | 18 |

Gaurav | 12 |

Harish | 21 |

5

D

From the following explanation it is clear that the one who has 18 chocolates is fifth to the right of the one who has 12 chocolates.

Hence option D is correct.

**Final Arrangement:**

Hence option D is correct.

Reference:

Gaurav had thrice the number of chocolates as that with Dhanush, who was sitting to the immediate right of Bimal.

The person opposite to Bimal had 7 chocolates.

The number of chocolates that Erik had was a prime number.

Bimal had twice the number of chocolates that Erik had.

They have different amount of chocolates with them viz. 4, 7,12, 17, 18, 21, 34 and 36.

From the given number of chocolates, prime numbers are 7 and 17 only. But twice of 7 is 14, which is not among the given numbers. Thus the number of chocolates with

Then as per the fourth hint, number of choclates with

Then for number of chocolates with Gaurav and Dhanush, as per our first hint there are only two combinations which are 4 – 12 and 7 – 21 among the given set of numbers.

But since we know that the person having 7 chocolates sits opposite to Bimal and Dhanush sits to the immediate right of Bimal, thus Dhanush will be having 4 chocolates.

So, the number of chocolates with

Persons |
No. of Chocolates |

Ajay | |

Bimal | 34 |

Chander | |

Dhanush | 4 |

Erik | 17 |

Feroz | |

Gaurav | 12 |

Harish |

Ajay was sitting opposite to the person having 21 chocolates.

The difference of the number of chocolates that Ajay and Bimal had was two, where the number of chocolates with Ajay was a perfect square.

Ajay and Bimal were seated at a gap of two.

The number of chocolates with Bimal is 34, and the difference between Ajay and Bimal's chocolates is 2, thus number of chocolates with

Persons |
No. of Chocolates |

Ajay | 36 |

Bimal | 34 |

Chander | |

Dhanush | 4 |

Erik | 17 |

Feroz | |

Gaurav | 12 |

Harish |

Harish was sitting third to the left of the one who had 18 chocolates.

Harish and Gaurav were seated at a gap of 1 person.

Erik and Feroz had consecutive number of chocolates.

The number of chocolates with Gaurav was opposite of the digits of the number of chocolates with Harish. i.e. if Harish has 'mn' number of chocolates, then Gaurav will have 'nm' number of chocolates.

Harish had more chocolates than Gaurav and the number of chocolates with both of them were in double digits.

We already know that Erik has 17 chocolates, so the number of chocolates with

Now the numbers left are - 7 and 21 and the persons left are Harish and Chander.

With the fourth hint it is clear that number of chocolates with

So

Persons |
No. of Chocolates |

Ajay | 36 |

Bimal | 34 |

Chander | 7 |

Dhanush | 4 |

Erik | 17 |

Feroz | 18 |

Gaurav | 12 |

Harish | 21 |

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Seating Arrangement is one of the topics that forms the base of any bank examination. Be it IBPS PO or SBI PO, IBPS Clerk or SBI Clerk, RRB Office Assistant or RRB Officer Scale I, RBI Grade B or IBPS SO. Not just in bank exams, but Insurance sector exams also feature questions on seating arrangement. Seating arrangement questions are commonly seen in exams like LIC AAO Pre, LIC AAO Mains, NIACL Assistant Pre, NIACL Assistant Mains, LIC HFL, UIIC etc. At this page, you will get all the questions based on new pattern seating arrangement that has been asked in several exams like IBPS Clerk Mains 2019, IBPS PO Mains 2019 and RRB Office Assistant Mains 2019. Seating arrangement questions are completely based on verbal reasoning where questions are solved by applying verbal statements in a logical order. You can find new pattern seating arrangement questions with solutions that can help you to derive at the answer quickly. The unmatched explanations will help the aspirants to build their concepts. In seating arrangement questions the most important point is to build a strategy for which the given information is to be utilized in a logical manner. It is very important to use the direct hints first and then put up the other information. After placing the direct hints, use the information connected with the direct hints to get the answer. This strategy will help to reach the answer in fastest possible time, which is the key to crack a competitive exam. In IBPS Clerk Mains 2019, the major portion of the reasoning section was occupied with seating arrangements. There were almost all types of seating arrangement questions like Linear seating arrangement, Circular seating arrangement, Floor based seating arrangement and Rectangular seating arrangement. So, this itself tells the importance of Seating arrangement questions in upcoming bank exams, insurance exams. Practice one test daily at www.smartkeeda.com to achieve excellence and master the critical topic of reasoning i.e. Seating Arrangement. Here, you will get linear seating arrangement questions, circular seating arrangement questions, floor based seating arrangement and rectangular based seating arrangement questions with detailed solutions. Take one quiz daily to build a strong command over all types of seating arrangement questions because in today’s competition age it is essential to have good command over all the four sections that come in bank exams. Start your preparation with the most relevant questions at www.smartkeeda.com and don’t forget to attempt test series on IBPS PO Pre+Mains, IBPS Clerk Pre plus Mains available at testzone.