Seating Arrangement Puzzle Quiz No 113 for SBI PO 2019 and IBPS PO 2019 at Smartkeeda

Directions: Read the information carefully and answer the questions given beside.

Eight boxes of different colors viz. Red, Black, White, Yellow, Violet, Brown, Grey and Pink are placed at equidistance on a circular table facing the centre, but not necessarily in the same order. Their weights (in kg) are – 19, 23, 26, 28, 31, 38, 43 and 49, again not necessarily in the same order. 
 
Black box is third to the left of the box weighing 38 kg. Grey box is third to the left of Yellow box. The box weighing 38 kg is a neighbor of both Brown box and Grey box. Brown box is second to the left of Grey box. Pink box is second to the right of Red box. Box weighing 49 kg is second to the left of Violet box. Only one box is there between Yellow and White boxes. Black box which is the fourth highest weighted box in the group is immediately heavier than Violet box but immediately lighter than Red box. White box is neither the heaviest nor the lightest. Yellow box is of 26 kg. Pink box’s weight is not an even number. The box weighing 26 kg and 19 kg are not immediate neighbors. The sum of White box and Brown box is 62 kg.

1
Which among the following boxes is placed between the box weighing 38 kg and the pink box?
» Explain it
B
Following the common explanation, we get that the box between the box weighing 38 kg i.e. Red box and Pink box is "Grey box i.e. the box weighing 49 kg."
 
Hence option B is correct.



 
Common Explanation

Reference:

Yellow box is of 26 kg.
The box weighing 26 kg and 19 kg are not immediate neighbors.
Only one box is there between Yellow and White boxes.
Grey box is third to the left of Yellow box.
Brown box is second to the left of Grey box.


Inference:

Following two cases can be drawn from the above hints.

Case 1



Case 2



Reference:

Black box which is the fourth highest weighted box in the group is immediately heavier than Violet box but immediately lighter than Red box.
White box is neither the heaviest not the lightest.
The sum of White box and Brown box is 62 kg.


Inference:

From the given weights (in kg) - 19, 23, 26, 28, 31, 38, 43 and 49, the fourth highest weight is 31 kg.
So, the weight of Black box is 31 kg, which is immediate heavier than violet box i.e. 28 kg. and immediate lighter than Red box i.e. 38 kg.
Weight of white box can’t be either 49 kg. or 19 kg.
So it’s weight should be among the remaining weights – 19, 23 and 43 kg.
With the available options, the only combination that makes the sum of 62 kg is 19 and 43.
So the weights of brown and white boxes are 19 and 43 kg respectively .

We will use some of these weights in the coming hints.

Case 1



Case 2



Reference:

Black box is third to the left of the box weighing 38 kg.
The box weighing 38 kg is a neighbor of both Brown box and Grey box.
Pink box is second to the right of Red box.


Inference:

Thus case2 gets eliminated, as position of white and pink boxes clashes here.
We have already derived the weight of red box as 38 kg, so placing the value in the Case 1 of the following arrangement.



So, we will continue with case 1 only.

Reference:

Box weighing 49 kg is second to the left of Violet box.

Inference:

The remaining vacant position is assigned to Violet box, which ascertains the weight sof Pink box as 43 kg. and Grey box as 49 kg. We had already inferred the weight of violet box, so the final arrangement will look like this.

2
If the positions of Brown and Grey boxes are interchanged then which among the following is true?
 
I. Grey box is third to the right of the box weighing 26 kg.
II. The immediate neighbours of Brown box are Red and Violet box.
III. Grey box is fourth to the left of Pink box.
» Explain it
A
Following the common explanation, it is clear that "Grey box is third to the right of the box weighing 26 kg" is the only true statement.
 
Hence option A is correct.



 
Common Explanation

Reference:

Yellow box is of 26 kg.
The box weighing 26 kg and 19 kg are not immediate neighbors.
Only one box is there between Yellow and White boxes.
Grey box is third to the left of Yellow box.
Brown box is second to the left of Grey box.


Inference:

Following two cases can be drawn from the above hints.

Case 1



Case 2



Reference:

Black box which is the fourth highest weighted box in the group is immediately heavier than Violet box but immediately lighter than Red box.
White box is neither the heaviest not the lightest.
The sum of White box and Brown box is 62 kg.


Inference:

From the given weights (in kg) - 19, 23, 26, 28, 31, 38, 43 and 49, the fourth highest weight is 31 kg.
So, the weight of Black box is 31 kg, which is immediate heavier than violet box i.e. 28 kg. and immediate lighter than Red box i.e. 38 kg.
Weight of white box can’t be either 49 kg. or 19 kg.
So it’s weight should be among the remaining weights – 19, 23 and 43 kg.
With the available options, the only combination that makes the sum of 62 kg is 19 and 43.
So the weights of brown and white boxes are 19 and 43 kg respectively .

We will use some of these weights in the coming hints.

Case 1



Case 2



Reference:

Black box is third to the left of the box weighing 38 kg.
The box weighing 38 kg is a neighbor of both Brown box and Grey box.
Pink box is second to the right of Red box.


Inference:

Thus case2 gets eliminated, as position of white and pink boxes clashes here.
We have already derived the weight of red box as 38 kg, so placing the value in the Case 1 of the following arrangement.



So, we will continue with case 1 only.

Reference:

Box weighing 49 kg is second to the left of Violet box.

Inference:

The remaining vacant position is assigned to Violet box, which ascertains the weight sof Pink box as 43 kg. and Grey box as 49 kg. We had already inferred the weight of violet box, so the final arrangement will look like this.

3
Four of the following five are alike in a certain way and hence form a group. Which of the following does not belong to the group?
» Explain it
D
Following the common explanation, it is clear that "Red box is the odd one out, as the weights of all other given boxes are odd numbers except the weight of Red box, which is an even number."
 
Hence option D is correct.



Common Explanation

Reference:

Yellow box is of 26 kg.
The box weighing 26 kg and 19 kg are not immediate neighbors.
Only one box is there between Yellow and White boxes.
Grey box is third to the left of Yellow box.
Brown box is second to the left of Grey box.


Inference:

Following two cases can be drawn from the above hints.

Case 1



Case 2



Reference:

Black box which is the fourth highest weighted box in the group is immediately heavier than Violet box but immediately lighter than Red box.
White box is neither the heaviest not the lightest.
The sum of White box and Brown box is 62 kg.


Inference:

From the given weights (in kg) - 19, 23, 26, 28, 31, 38, 43 and 49, the fourth highest weight is 31 kg.
So, the weight of Black box is 31 kg, which is immediate heavier than violet box i.e. 28 kg. and immediate lighter than Red box i.e. 38 kg.
Weight of white box can’t be either 49 kg. or 19 kg.
So it’s weight should be among the remaining weights – 19, 23 and 43 kg.
With the available options, the only combination that makes the sum of 62 kg is 19 and 43.
So the weights of brown and white boxes are 19 and 43 kg respectively .

We will use some of these weights in the coming hints.

Case 1



Case 2



Reference:

Black box is third to the left of the box weighing 38 kg.
The box weighing 38 kg is a neighbor of both Brown box and Grey box.
Pink box is second to the right of Red box.


Inference:

Thus case2 gets eliminated, as position of white and pink boxes clashes here.
We have already derived the weight of red box as 38 kg, so placing the value in the Case 1 of the following arrangement.



So, we will continue with case 1 only.

Reference:

Box weighing 49 kg is second to the left of Violet box.

Inference:

The remaining vacant position is assigned to Violet box, which ascertains the weight sof Pink box as 43 kg. and Grey box as 49 kg. We had already inferred the weight of violet box, so the final arrangement will look like this.

4
Sum of the weight of which of the following pairs comes to 74 kg?
» Explain it
C
Following the common explanation, it is clear that the weight of black box is 31 kg and the weight of white box is 43 kg.
 
Thus the required sum i.e. 31 + 43 = 74 kg. is obtained.
 
Hence option C is correct.



Common Explanation

Reference:

Yellow box is of 26 kg.
The box weighing 26 kg and 19 kg are not immediate neighbors.
Only one box is there between Yellow and White boxes.
Grey box is third to the left of Yellow box.
Brown box is second to the left of Grey box.


Inference:

Following two cases can be drawn from the above hints.

Case 1



Case 2



Reference:

Black box which is the fourth highest weighted box in the group is immediately heavier than Violet box but immediately lighter than Red box.
White box is neither the heaviest not the lightest.
The sum of White box and Brown box is 62 kg.


Inference:

From the given weights (in kg) - 19, 23, 26, 28, 31, 38, 43 and 49, the fourth highest weight is 31 kg.
So, the weight of Black box is 31 kg, which is immediate heavier than violet box i.e. 28 kg. and immediate lighter than Red box i.e. 38 kg.
Weight of white box can’t be either 49 kg. or 19 kg.
So it’s weight should be among the remaining weights – 19, 23 and 43 kg.
With the available options, the only combination that makes the sum of 62 kg is 19 and 43.
So the weights of brown and white boxes are 19 and 43 kg respectively .

We will use some of these weights in the coming hints.

Case 1



Case 2



Reference:

Black box is third to the left of the box weighing 38 kg.
The box weighing 38 kg is a neighbor of both Brown box and Grey box.
Pink box is second to the right of Red box.


Inference:

Thus case2 gets eliminated, as position of white and pink boxes clashes here.
We have already derived the weight of red box as 38 kg, so placing the value in the Case 1 of the following arrangement.



So, we will continue with case 1 only.

Reference:

Box weighing 49 kg is second to the left of Violet box.

Inference:

The remaining vacant position is assigned to Violet box, which ascertains the weight sof Pink box as 43 kg. and Grey box as 49 kg. We had already inferred the weight of violet box, so the final arrangement will look like this.

» Explain it
B
Following the common explanation, it is clear that the the third lightest box is Yellow box i.e. the box which is third to the right of the heaviest box.
 
Hence option B is correct.


 
Common Explanation

Reference:

Yellow box is of 26 kg.
The box weighing 26 kg and 19 kg are not immediate neighbors.
Only one box is there between Yellow and White boxes.
Grey box is third to the left of Yellow box.
Brown box is second to the left of Grey box.


Inference:

Following two cases can be drawn from the above hints.

Case 1



Case 2



Reference:

Black box which is the fourth highest weighted box in the group is immediately heavier than Violet box but immediately lighter than Red box.
White box is neither the heaviest not the lightest.
The sum of White box and Brown box is 62 kg.


Inference:

From the given weights (in kg) - 19, 23, 26, 28, 31, 38, 43 and 49, the fourth highest weight is 31 kg.
So, the weight of Black box is 31 kg, which is immediate heavier than violet box i.e. 28 kg. and immediate lighter than Red box i.e. 38 kg.
Weight of white box can’t be either 49 kg. or 19 kg.
So it’s weight should be among the remaining weights – 19, 23 and 43 kg.
With the available options, the only combination that makes the sum of 62 kg is 19 and 43.
So the weights of brown and white boxes are 19 and 43 kg respectively .

We will use some of these weights in the coming hints.

Case 1



Case 2



Reference:

Black box is third to the left of the box weighing 38 kg.
The box weighing 38 kg is a neighbor of both Brown box and Grey box.
Pink box is second to the right of Red box.


Inference:

Thus case2 gets eliminated, as position of white and pink boxes clashes here.
We have already derived the weight of red box as 38 kg, so placing the value in the Case 1 of the following arrangement.



So, we will continue with case 1 only.

Reference:

Box weighing 49 kg is second to the left of Violet box.

Inference:

The remaining vacant position is assigned to Violet box, which ascertains the weight sof Pink box as 43 kg. and Grey box as 49 kg. We had already inferred the weight of violet box, so the final arrangement will look like this.


Seating Arrangement Puzzles for SBI PO 2019 and IBPS PO 2019 | Circular Seating Arrangement Quiz No 113 at Smartkeeda


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Seating Arrangement Puzzle Quiz No. 113
 
Seating Arrangement is one of the topics that forms the base of any bank examination. Be it SBI PO or IBPS PO, IBPS Clerk or SBI Clerk, RRB Office Assistant or RRB Officer Scale I, RBI Grade B or IBPS SO. Not just in bank exams, but Insurance sector exams also feature questions on seating arrangement. Seating arrangement questions are commonly seen in exams like NIACL Assistant Pre, NIACL Assistant Mains, LIC HFL, UIIC etc.  At this page, you will get all the questions based on new pattern seating arrangement that has been asked in several exams like SBI Clerk Mains 2018, SBI PO Mains 2018 and RRB Office Assistant Mains 2018. Seating arrangement questions are completely based on verbal reasoning where questions are solved by applying verbal statements in a logical order. You can find new pattern seating arrangement questions with solutions that can help you to derive at the answer quickly. The unmatched explanations will help the aspirants to build their concepts. In seating arrangement questions the most important point is to build a strategy for which the given information is to be utilized in a logical manner. It is very important to use the direct hints first and then put up the other information. After placing the direct hints, use the information connected with the direct hints to get the answer. This strategy will help to reach the answer in fastest possible time, which is the key to crack a competitive exam. In SBI Clerk Mains 2018, the major portion of the reasoning section was occupied with seating arrangements. There were almost all types of seating arrangement questions like Linear seating arrangement, Circular seating arrangement, Floor based seating arrangement and Rectangular seating arrangement. So, this itself tells the importance of Seating arrangement questions in upcoming bank exams, insurance exams and even CLAT 2019. Practice one test daily at www.smartkeeda.com to achieve excellence and master the critical topic of reasoning i.e. Seating Arrangement. Here, you will get linear seating arrangement questions, circular seating arrangement questions, floor based seating arrangement and rectangular based seating arrangement questions with detailed solutions. Take one quiz daily to build a strong command over all types of seating arrangement questions because in today’s competition age it is essential to have good command over all the four sections that come in bank exams. Start your preparation with the most relevant questions at www.smartkeeda.com and don’t forget to attempt test series on SBI PO Pre+Mains, SBI Clerk Pre+Mains and IBPS PO Pre+Mains, IBPS Clerk Pre+Mains available at testzone.