- SA Set No 118
- SA Set No 117
- SA Set No 116
- SA Set No 115
- SA Set No 114
- SA Set No 113
- SA Set No 112
- SA Set No 111
- SA Set No 110
- SA Set No 109
- SA Set No 108
- SA Set No 107
- SA Set No 106
- SA Set No 105
- SA Set No 104
- SA Set No 103
- SA Set No 102
- SA Set No 101
- SA Set No 100
- SA Set No 99
- SA Set No 98
- SA Set No 97
- SA Set No 96
- SA Set No 95
- SA Set No 94
- SA Set No 93
- SA Set No 92
- SA Set No 91
- SA Set No 90
- SA Set No 89
- SA Set No 88
- SA Set No 87
- SA Set No 86
- SA Set No 85
- SA Set No 84
- SA Set No 83
- SA Set No 82
- SA Set No 81
- SA Set No 80
- SA Set No 79
- SA Set No 78
- SA Set No 77
- SA Set No 76
- SA Set No 75
- SA Set No 74
- SA Set No 73
- SA Set No 72
- SA Set No 71
- SA Set No 70
- SA Set No 69
- SA Set No 68
- SA Set No 67
- SA Set No 66
- SA Set No 65
- SA Set No 64
- SA Set No 63
- SA Set No 62
- SA Set No 61
- SA Set No 60
- SA Set No 59
- SA Set No 58
- SA Set No 57
- SA Set No 56
- SA Set No 55
- SA Set No 54
- SA Set No 53
- SA Set No 52
- SA Set No 51
- SA Set No 50
- SA Set No 49
- SA Set No 48
- SA Set No 47
- SA Set No 46
- SA Set No 45
- SA Set No 44
- SA Set No 43
- SA Set No 42
- SA Set No 41
- SA Set No 40
- SA Set No 39
- SA Set No 38
- SA Set No 37
- SA Set No 36
- SA Set No 35
- SA Set No 34
- SA Set No 33
- SA Set No 32
- S A Set No 31
- Set No 30
- Set No 29
- Set No 28
- Set No 27
- Set No 26
- Set No 25
- Set No 24
- Set No 23
- Set No 22
- Set No 21
- Set No 20
- Set No 19
- Set No 18
- Set No 17
- Set No 16
- Set No 15
- Set No 14
- Set No 13
- Set No 12
- Set No 11
- Set no 10
- Set No 9
- Set No 8
- Set No 7
- Set No 6
- Set No 5
- Set No 4
- Set No 3
- Set No 2
- Set No 1

In a society meeting eight persons – P, Q, R, S, T, U, V and W were seated in a straight line facing the north. They have different house numbers – 15, 28, 30, 40, 45, 65, 80 and 90 not necessarily in the same order. It is further known that:

Difference between T and P's house number is equal to the difference between Q and U's house number.

Not more than 3 persons have house number less than Q.

Not more than 2 persons have house number more than P.

T’s house number was twice of V.

Q is seated to the immediate right of the person whose house number was 65.

P is seated to the immediate right of T who is 3rd to the left of one whose house number was 45.

Three persons seated to the right of V had house numbers less than him.

House numbers of R and Q together was equal to house number of V.

One whose house number was 28 was seated to the immediate left of the one whose house number was 40.

Q and U were seated at a gap of 1 person.

S and U were not seated together.

Important for :

1

E

Following the final solution we can say that T was seated at the extreme left end of the row.Hence, the correct answer is option E.

Not more than 2 persons have house number more than P.

Not more than 3 persons have house number less than Q.

T’s house number was twice of V.

House number of R and Q together was equal to house number V.

Three persons seated to the right of V had house numbers less than him.

Here, the possible house numbers for P are 65 or 80 or 90. And the possible house numbers for Q are 15 or 28 or 30 or 40.

Similarly, the possible house numbers of V and T are 15 and 30, 40 and 80, and 45 and 90.

Here, house number 15 is not possible for V as we already know that three persons had house number less than V.

And house number 40 is also not possible for V because none of the combination of the house numbers leads to 40 and we have a hint that house number of R and Q was equal to house number V.

Thus, the only possible house number for V is 45 and the house number of T is 90.

Using the above information we can also say that the house number of R and Q can be 15 and 30 not necessarily in the same order. And the possible house number of P can be 65 or 80.

Three persons seated to the right of V had house numbers less than him.

P is seated to the immediate right of T who is 3rd to the left of one whose house number was 45.

With the first hint we can say that there were at least three persons sitting to the immediate right of V.

And with the second we can say that there are two possible scenarios in which we can fix the positions of these persons.

Difference between T and P's house number is equal to the difference between Q and U's house number.

House number of R and Q together was equal to house number V.

Here the difference between the house number of T and P can be 25 (when the house number of P is 65) or 10 (when the house number of P is 80)

And we know that the possible house numbers of Q are either 15 or 30.

Now, if the house number of Q is 15 then the only possible house number for U is 40 when the house number of P is 65.

And, if the house number of Q is 30 then the only possible house number for U is 40 when the house number of P is 80.

Q was seated to the immediate right of the person whose house number was 65.

Q and U were seated at a gap of 1 person.

Using, the above information our case 1 and case 2 can be redrawn as:

One whose house number was 28 was seated to the immediate left of the one whose house number was 40.

S and U were not seated together.

Here,

At this point we can say that the house number of R is 15 and can fix his position as shown in the figure.

S and U were not seated together.

At this point we

But, with the given information we can place S and W and in our Case-C. As shown in the figure below:

Now, the puzzle is completed.

2

C

Following the final solution we can say that the house number of Q was 30 i.e. 3 × 10Hence, the correct answer is option C.

Not more than 2 persons have house number more than P.

Not more than 3 persons have house number less than Q.

T’s house number was twice of V.

House number of R and Q together was equal to house number V.

Three persons seated to the right of V had house numbers less than him.

Here, the possible house numbers for P are 65 or 80 or 90. And the possible house numbers for Q are 15 or 28 or 30 or 40.

Similarly, the possible house numbers of V and T are 15 and 30, 40 and 80, and 45 and 90.

Here, house number 15 is not possible for V as we already know that three persons had house number less than V.

And house number 40 is also not possible for V because none of the combination of the house numbers leads to 40 and we have a hint that house number of R and Q was equal to house number V.

Thus, the only possible house number for V is 45 and the house number of T is 90.

Using the above information we can also say that the house number of R and Q can be 15 and 30 not necessarily in the same order. And the possible house number of P can be 65 or 80.

Three persons seated to the right of V had house numbers less than him.

P is seated to the immediate right of T who is 3rd to the left of one whose house number was 45.

With the first hint we can say that there were at least three persons sitting to the immediate right of V.

And with the second we can say that there are two possible scenarios in which we can fix the positions of these persons.

Difference between T and P's house number is equal to the difference between Q and U's house number.

House number of R and Q together was equal to house number V.

Here the difference between the house number of T and P can be 25 (when the house number of P is 65) or 10 (when the house number of P is 80)

And we know that the possible house numbers of Q are either 15 or 30.

Now, if the house number of Q is 15 then the only possible house number for U is 40 when the house number of P is 65.

And, if the house number of Q is 30 then the only possible house number for U is 40 when the house number of P is 80.

Q was seated to the immediate right of the person whose house number was 65.

Q and U were seated at a gap of 1 person.

Using, the above information our case 1 and case 2 can be redrawn as:

One whose house number was 28 was seated to the immediate left of the one whose house number was 40.

S and U were not seated together.

Here,

At this point we can say that the house number of R is 15 and can fix his position as shown in the figure.

S and U were not seated together.

At this point we

But, with the given information we can place S and W and in our Case-C. As shown in the figure below:

Now, the puzzle is completed.

3

B

Following the final solution we can say that the house numbers of T and U were 90 and 40 respectively.

Required Average = (90 + 40) ÷ 2 = 65

And we know that the house number of S was 65.

Hence, the correct answer is option B.

Not more than 2 persons have house number more than P.

Not more than 3 persons have house number less than Q.

T’s house number was twice of V.

House number of R and Q together was equal to house number V.

Three persons seated to the right of V had house numbers less than him.

Here, the possible house numbers for P are 65 or 80 or 90. And the possible house numbers for Q are 15 or 28 or 30 or 40.

Similarly, the possible house numbers of V and T are 15 and 30, 40 and 80, and 45 and 90.

Here, house number 15 is not possible for V as we already know that three persons had house number less than V.

And house number 40 is also not possible for V because none of the combination of the house numbers leads to 40 and we have a hint that house number of R and Q was equal to house number V.

Thus, the only possible house number for V is 45 and the house number of T is 90.

Using the above information we can also say that the house number of R and Q can be 15 and 30 not necessarily in the same order. And the possible house number of P can be 65 or 80.

Three persons seated to the right of V had house numbers less than him.

P is seated to the immediate right of T who is 3rd to the left of one whose house number was 45.

With the first hint we can say that there were at least three persons sitting to the immediate right of V.

And with the second we can say that there are two possible scenarios in which we can fix the positions of these persons.

Difference between T and P's house number is equal to the difference between Q and U's house number.

House number of R and Q together was equal to house number V.

Here the difference between the house number of T and P can be 25 (when the house number of P is 65) or 10 (when the house number of P is 80)

And we know that the possible house numbers of Q are either 15 or 30.

Now, if the house number of Q is 15 then the only possible house number for U is 40 when the house number of P is 65.

And, if the house number of Q is 30 then the only possible house number for U is 40 when the house number of P is 80.

Q was seated to the immediate right of the person whose house number was 65.

Q and U were seated at a gap of 1 person.

Using, the above information our case 1 and case 2 can be redrawn as:

One whose house number was 28 was seated to the immediate left of the one whose house number was 40.

S and U were not seated together.

Here,

At this point we can say that the house number of R is 15 and can fix his position as shown in the figure.

S and U were not seated together.

At this point we

But, with the given information we can place S and W and in our Case-C. As shown in the figure below:

Now, the puzzle is completed.

4

D

Following the final solution we can say that the house numbers of R and V were 15 and 45 respectively.

Required Average = (15 + 45) ÷ 2 = 30

And we know that the house number of Q was 30.

.

Hence, the correct answer is option D.

Not more than 2 persons have house number more than P.

Not more than 3 persons have house number less than Q.

T’s house number was twice of V.

House number of R and Q together was equal to house number V.

Three persons seated to the right of V had house numbers less than him.

Here, the possible house numbers for P are 65 or 80 or 90. And the possible house numbers for Q are 15 or 28 or 30 or 40.

Similarly, the possible house numbers of V and T are 15 and 30, 40 and 80, and 45 and 90.

Here, house number 15 is not possible for V as we already know that three persons had house number less than V.

And house number 40 is also not possible for V because none of the combination of the house numbers leads to 40 and we have a hint that house number of R and Q was equal to house number V.

Thus, the only possible house number for V is 45 and the house number of T is 90.

Using the above information we can also say that the house number of R and Q can be 15 and 30 not necessarily in the same order. And the possible house number of P can be 65 or 80.

Three persons seated to the right of V had house numbers less than him.

P is seated to the immediate right of T who is 3rd to the left of one whose house number was 45.

With the first hint we can say that there were at least three persons sitting to the immediate right of V.

And with the second we can say that there are two possible scenarios in which we can fix the positions of these persons.

Difference between T and P's house number is equal to the difference between Q and U's house number.

House number of R and Q together was equal to house number V.

Here the difference between the house number of T and P can be 25 (when the house number of P is 65) or 10 (when the house number of P is 80)

And we know that the possible house numbers of Q are either 15 or 30.

Now, if the house number of Q is 15 then the only possible house number for U is 40 when the house number of P is 65.

And, if the house number of Q is 30 then the only possible house number for U is 40 when the house number of P is 80.

Q was seated to the immediate right of the person whose house number was 65.

Q and U were seated at a gap of 1 person.

Using, the above information our case 1 and case 2 can be redrawn as:

One whose house number was 28 was seated to the immediate left of the one whose house number was 40.

S and U were not seated together.

Here,

At this point we can say that the house number of R is 15 and can fix his position as shown in the figure.

S and U were not seated together.

At this point we

But, with the given information we can place S and W and in our Case-C. As shown in the figure below:

Now, the puzzle is completed.

5

A

Following the final solution we can say that no one was sitting between Q and S.

Hence, the correct answer is option A.

Not more than 2 persons have house number more than P.

Not more than 3 persons have house number less than Q.

T’s house number was twice of V.

House number of R and Q together was equal to house number V.

Three persons seated to the right of V had house numbers less than him.

Here, the possible house numbers for P are 65 or 80 or 90. And the possible house numbers for Q are 15 or 28 or 30 or 40.

Similarly, the possible house numbers of V and T are 15 and 30, 40 and 80, and 45 and 90.

Here, house number 15 is not possible for V as we already know that three persons had house number less than V.

And house number 40 is also not possible for V because none of the combination of the house numbers leads to 40 and we have a hint that house number of R and Q was equal to house number V.

Thus, the only possible house number for V is 45 and the house number of T is 90.

Using the above information we can also say that the house number of R and Q can be 15 and 30 not necessarily in the same order. And the possible house number of P can be 65 or 80.

Three persons seated to the right of V had house numbers less than him.

P is seated to the immediate right of T who is 3rd to the left of one whose house number was 45.

With the first hint we can say that there were at least three persons sitting to the immediate right of V.

And with the second we can say that there are two possible scenarios in which we can fix the positions of these persons.

Difference between T and P's house number is equal to the difference between Q and U's house number.

House number of R and Q together was equal to house number V.

Here the difference between the house number of T and P can be 25 (when the house number of P is 65) or 10 (when the house number of P is 80)

And we know that the possible house numbers of Q are either 15 or 30.

Now, if the house number of Q is 15 then the only possible house number for U is 40 when the house number of P is 65.

And, if the house number of Q is 30 then the only possible house number for U is 40 when the house number of P is 80.

Q was seated to the immediate right of the person whose house number was 65.

Q and U were seated at a gap of 1 person.

Using, the above information our case 1 and case 2 can be redrawn as:

One whose house number was 28 was seated to the immediate left of the one whose house number was 40.

S and U were not seated together.

Here,

At this point we can say that the house number of R is 15 and can fix his position as shown in the figure.

S and U were not seated together.

At this point we

But, with the given information we can place S and W and in our Case-C. As shown in the figure below:

Now, the puzzle is completed.