Important for :

1

Two friends Tinu and Dinu are driving car in Paris. Tinu is facing north and Dinu is facing south. They drive their cars for 80 meters in the direction they are facing and reached HDFC Bank and CUB ATM respectively. Then they turn right and drive for another 70 meters and reached PVR cinemas and Phoenix mall respectively. Then they take 90 degree anti clock wise direction for 40 meters and then they turn right. After driving for 30 meters Dinu reaches at CTS and Tinu reached at TCS. **(Set 1 Q. 1)**

A

From above figure, we get,

(120)

14400 + 1225 = 15625

15625 = 125m [TCS to mid point]

Similarly we get

125 m from CTS to mid point.

Total Distance = 125 m + 125 m = 250 m

TCS is north-west direction with respect to CTS.

Hence, option A is correct.

2

Two friends Tinu and Dinu are driving car in Paris. Tinu is facing north and Dinu is facing south. They drive their cars for 80 meters in the direction they are facing and reached HDFC Bank and CUB ATM respectively. Then they turn right and drive for another 70 meters and reached PVR cinemas and Phoenix mall respectively. Then they take 90 degree anti clock wise direction for 40 meters and then they turn right. After driving for 30 meters Dinu reaches at CTS and Tinu reached at TCS. **(Set 1 Q. 2)**

C

From fig, TCS is north direction with respect to CTS.

Total Distance = 120 m + 120 m = 240 m

Hence, option C is correct.

3

Two friends Tinu and Dinu are driving car in Paris. Tinu is facing north and Dinu is facing south. They drive their cars for 80 meters in the direction they are facing and reached HDFC Bank and CUB ATM respectively. Then they turn right and drive for another 70 meters and reached PVR cinemas and Phoenix mall respectively. Then they take 90 degree anti clock wise direction for 40 meters and then they turn right. After driving for 30 meters Dinu reaches at CTS and Tinu reached at TCS. **(Set 1 Q. 3)**

B

From above figure, we get

(120)

14400 + 1225 = 15625

15625 = 125m [TCS to mid point]

Similarly we get

From CTS to midpoint is 125 m.

Total Distance = 125 m + 125 m = 250 m

TCS is north-east direction with respect to CTS.

Hence, option B is correct.

4

A is north-east of B. The shortest distance between A and B is 10 meter. C is south of A and east of B. The distance between B and C is twice the distance between A and E. The distance between A and C is twice the distance E and H. E is north of A. H is east of E. H is 3meter south of G. The shortest distance between G and E is 5 meter. **(Set 2 Q.1)**

**What is the shortest distance between point A and H?**

C

The following common explanation, we get** “5 meter”.**

From, figure, (AH)^{2} = (EH)^{2} + (AE)^{2}

(AH)^{2} = (4)^{2} + (3)^{2}

16 + 9 = (AH)^{2}

25 = (AH)^{2}

AH = 5 meter

Hence, option C is correct.

__Common Explanation:__

From, figure, (AH)

(AH)

16 + 9 = (AH)

25 = (AH)

AH = 5 meter

Hence, option C is correct.

A is north-east of B. The shortest distance between A and B is 10 meter. C is south of A and east of B.

E is north of A. H is east of E. H is 3meter south of G. The shortest distance between G and E is 5 meter.

(EG)

(5)

25 – 9 = (EH)

distance [E to H] = 4 meter

The distance between B and C is twice the distance between A and E.

The distance between A and C is twice the distance E and H.

Distance between E and H = 4 meter

Distance [A to C] = 2 { Distance [E to H] }

Distance [A to C] = 2 × 4 = 8 meter

Thus we get fig 1 as,

(BA)

(10)

100 = (BC)

100 – 64 = (BC)

36 = (BC)

distance [B to C] = 6 meter

We know,Distance between B and C = 6 meter Given,Distance [B to C]= 2 {Distance [E to A]} 6 meter = 2 {Distance [E to A]} Distance [E to A] =6 meter/2 =3 meter |

5

A is north-east of B. The shortest distance between A and B is 10 meter. C is south of A and east of B. The distance between B and C is twice the distance between A and E. The distance between A and C is twice the distance E and H. E is north of A. H is east of E. H is 3meter south of G. The shortest distance between G and E is 5 meter.**[Set 2 Q. 2] **

C

The following common explanation, we get “12 meter”.

From figure, Distance [A to C] = 8 meter

Distance [E to H] = 4 meter.

Sum = 8 + 4 =12 meter

Hence, option C is correct.

__Common Explanation:__

**References**

A is north-east of B. The shortest distance between A and B is 10 meter. C is south of A and east of B.
**References**

E is north of A. H is east of E. H is 3meter south of G. The shortest distance between G and E is 5 meter.

**References**

The distance between B and C is twice the distance between A and E.

The distance between A and C is twice the distance E and H.

**Combining all figures, we get**

A is north-east of B. The shortest distance between A and B is 10 meter. C is south of A and east of B.

E is north of A. H is east of E. H is 3meter south of G. The shortest distance between G and E is 5 meter.

[Figure 2] |
From, figure (2),(EG) ^{2 }= (EH)^{2 }+ (HG)^{2}(5) ^{2 }= (EH)^{2 }+ (3)^{2 }2 = (EH) ^{2 }+ 925 – 9 = (EH) ^{2}16 = (EH) ^{2}Therefore,distance [E to H] = 4 meter |

The distance between B and C is twice the distance between A and E.

The distance between A and C is twice the distance E and H.

We know,Distance between E and H = 4 meter Given,Distance [A to C]= 2 {Distance [E to H]} Distance [A to C]=2*4 =8 meter Thus we get fig 1 as, [Figure 3] |
From, figure (3), (BA) ^{2} =(BC) ^{2 }+ (AC)^{2}(10) ^{2} = (BC)^{2} + (B)^{2}100 = (BC) ^{2} + 64100 – 64 = (BC) ^{2}36 = (BC) ^{2}Therefore,distance [B to C] = 6 meter |

We know,Distance between B and C = 6 meter Given,Distance [B to C]= 2 {Distance [E to A]} 6 meter = 2 {Distance [E to A]} Distance [E to A] =6 meter/2 =3 meter |

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