Important Practice Questions related to Direction Sense for IBPS PO 2020

Directions: Study the following questions carefully and answer the questions given below.
1
Two friends Tinu and Dinu are driving car in Paris. Tinu is facing north and Dinu is facing south. They drive their cars for 80 meters in the direction they are facing and reached HDFC Bank and CUB ATM respectively. Then they turn right and drive for another 70 meters and reached PVR cinemas and Phoenix mall respectively. Then they take 90 degree anti clock wise direction for 40 meters and then they turn right. After driving for 30 meters Dinu reaches at CTS and Tinu reached at TCS. (Set 1 Q. 1)
 
Initially, if Dinu was 270 meters to the east of Tinu, then what is the shortest distance and direction of TCS with respect to CTS?
» Explain it
A


From above figure, we get,



(120)2 + (35)2 = 14400 + 1225

14400 + 1225  = 15625

15625 = 125m [TCS to mid point]

Similarly we get 

125 m from CTS to mid point.
 
Total Distance = 125 m + 125 m = 250 m
 
TCS is north-west direction with respect to CTS.

Hence, option A is correct.
 
2
Two friends Tinu and Dinu are driving car in Paris. Tinu is facing north and Dinu is facing south. They drive their cars for 80 meters in the direction they are facing and reached HDFC Bank and CUB ATM respectively. Then they turn right and drive for another 70 meters and reached PVR cinemas and Phoenix mall respectively. Then they take 90 degree anti clock wise direction for 40 meters and then they turn right. After driving for 30 meters Dinu reaches at CTS and Tinu reached at TCS. (Set 1 Q. 2)
 
Initially, if Dinu was 200 meters to the east of Tinu, then what is the shortest distance and direction of TCS with respect to CTS?
 
» Explain it
C
From fig, TCS is north direction with respect to CTS.
 
Total Distance = 120 m + 120 m = 240 m
 
 
Hence, option C is correct.
 
3
Two friends Tinu and Dinu are driving car in Paris. Tinu is facing north and Dinu is facing south. They drive their cars for 80 meters in the direction they are facing and reached HDFC Bank and CUB ATM respectively. Then they turn right and drive for another 70 meters and reached PVR cinemas and Phoenix mall respectively. Then they take 90 degree anti clock wise direction for 40 meters and then they turn right. After driving for 30 meters Dinu reaches at CTS and Tinu reached at TCS. (Set 1 Q. 3)
 
Initially, if Dinu was 130 meters to the east of Tinu, then what is the shortest distance and direction of TCS with respect to CTS?
» Explain it
B
 

From above figure, we get



(120)2 + (35)2 = 14400 + 1225

14400 + 1225  = 15625

15625 = 125m [TCS to mid point]

Similarly we get 

 From CTS to midpoint is 125 m.

Total Distance = 125 m + 125 m = 250 m

TCS is north-east direction with respect to CTS.
 
Hence, option B is correct.

4
A is north-east of B. The shortest distance between A and B is 10 meter. C is south of A and east of B. The distance between B and C is twice the distance between A and E. The distance between A and C is twice the distance E and H. E is north of A. H is east of E. H is 3meter south of G. The shortest distance between G and E is 5 meter. (Set 2 Q.1)

What is the shortest distance between point A and H?
» Explain it
C
The following common explanation, we get “5 meter”. 

From, figure, (AH)2    =    (EH)2 + (AE)2 
                      (AH)2   =   (4)2 + (3)2 
                    16 + 9    =   (AH)2 
                          25    =   (AH)2 
                          AH   =   5 meter
 
Hence, option C is correct.

Common Explanation:
 
References
 
A is north-east of B. The shortest distance between A and B is 10 meter. C is south of A and east of B. 
References
 
E is north of A. H is east of E. H is 3meter south of G. The shortest distance between G and E is 5 meter.
[Figure 2]

From, figure (2),

(EG)= (EH)+ (HG)
(5)= (EH)+ (3)2    ⇒    2 = (EH)+ 9
25 – 9 = (EH)2           ⇒    16 = (EH)2

Therefore,

distance [E to H] = 4 meter
References

The distance between B and C is twice the distance between A and E.

The distance between A and C is twice the distance E and H.

We know,
 
Distance between E and H = 4 meter
 
Given,

Distance [A to C] = 2 { Distance [E to H] }
Distance [A to C] = 2 × 4 = 8 meter
Thus we get fig 1 as,

[Figure 3] 

From, figure (3), 

(BA)2 = (BC)+ (AC)2
(10)2 = (BC)2 + (B)2
100 = (BC)2 + 64
100 – 64 = (BC)2
36 = (BC)2

Therefore,

distance [B to C] = 6 meter
   
 
 
We know,

Distance between B and C = 6 meter
 
Given,

Distance [B to C]= 2 {Distance [E to A]}

6 meter = 2 {Distance [E to A]}
 
Distance [E to A] =6 meter/2 =3 meter
 
 


Combining all figures, we get


 
5
A is north-east of B. The shortest distance between A and B is 10 meter. C is south of A and east of B. The distance between B and C is twice the distance between A and E. The distance between A and C is twice the distance E and H. E is north of A. H is east of E. H is 3meter south of G. The shortest distance between G and E is 5 meter.[Set 2 Q. 2] 

What is the sum of the distance between A and C & E and H?
» Explain it
C
The following common explanation, we get “12 meter”.
 
From figure, Distance [A to C] = 8 meter
 
Distance [E to H] = 4 meter.
 
Sum = 8 + 4 =12 meter
 
Hence, option C is correct.

Common Explanation:
 
References
 
A is north-east of B. The shortest distance between A and B is 10 meter. C is south of A and east of B. 
  
References
 
E is north of A. H is east of E. H is 3meter south of G. The shortest distance between G and E is 5 meter.

 
[Figure 2]

 From, figure (2),

(EG)= (EH)+ (HG)2

(5)= (EH)+ (3)

2 = (EH)+ 9

25 – 9 = (EH)2

16 = (EH)2

Therefore,

distance [E to H] = 4 meter
 

References

The distance between B and C is twice the distance between A and E.

The distance between A and C is twice the distance E and H.

 
We know,
 
Distance between E and H = 4 meter
 
Given,

Distance [A to C]= 2 {Distance [E to H]}

Distance [A to C]=2*4 =8 meter
 
Thus we get fig 1 as,
 

[Figure 3]

 
 From, figure (3), 

(BA)2 =
(BC)+ (AC)2

(10)2 = (BC)2 + (B)2

100 = (BC)2 + 64

100 – 64 = (BC)2

36 = (BC)2

Therefore,

distance [B to C] = 6 meter

   
 
 
We know,

Distance between B and C = 6 meter
 
Given,

Distance [B to C]= 2 {Distance [E to A]}

6 meter = 2 {Distance [E to A]}
 
Distance [E to A] =6 meter/2 =3 meter
 
 


Combining all figures, we get
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How to Prepare Direction Sense related questions for Bank Po exams

Verbal reasoning is a very important section of Reasoning Aptitude section with many sub sections within it. One of the verbal reasoning topics or sub sections is the topic of Direction Sense related questions. The Direction Sense related questions are important for various exams in banking as well as SSC CGL and with the upcoming IBPS Clerk exam and RBI Assistant exams, such questions on Direction Sense are even more important. Direction Sense related questions can also differ in terms of their level of difficulty with very high level questions in IBPS PO Mains and RBI Grade B. There are new pattern of Direction Sense related questions coming up in every bank exam and it is extremely urgent to stay up to date with the latest pattern.  With SEBI Grade A, RBI Assistant and IBPS PO exams lined up in 2018, these questions on Direction Sense are extremely important and need to be practiced. Questions on Direction Sense are very common in most of the competitive exams like IBPS PO Pre, IBPS Clerk Pre, SBI PO Pre, SBI Clerk Pre, IBPS PO Mains, IBPS Clerk Mains, SBI Clerk Mains, SBI PO Mains, Railways Exams, SSC CGL Tier 1, SSC CHSL, SSC MTS, CLAT, MAT, etc. Almost all the competitive exams have at least a couple of questions on Direction Sense. This is why aspirants cannot afford to ignore this important topic of Reasoning Aptitude. Also, Direction Sense questions are not difficult if the aspirant knows how to think while solving such questions on coding decoding questions along with some easy tricks and shortcuts. On this page at Smartkeeda, the digital Question Bank for Aptitude Questions, we bring to you some Direction Sense related questions along with how to solve them using the easiest methods possible. These Direction Sense questions are useful for upcoming exams like SBI Clerk 2019, SBI PO 2019, IBPS Clerk 2018, IBPS PO 2018, SSC CGL Tier 1 2018, IBPS RRB 2018-19, CDSE, CLAT 2019, MAT 2018-19, NIFT, IBPS SO Pre 2018, Syndicate Bank, Canara Bank, Railways, RBI Grade B, RRB Scale I, SEBI Grade A and many more bank and other competitive exams. So dear aspirants, what are you waiting for? Practice Direction Sense questions on Smartkeeda with our smart solutions and top your exam with flying colours.

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