Important Practice Questions related to Direction Sense for IBPS PO 2018

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Directions: Study the following questions carefully and answer the questions given below.
1
Two friends Tinu and Dinu are driving car in Paris. Tinu is facing north and Dinu is facing south. They drive their cars for 80 meters in the direction they are facing and reached HDFC Bank and CUB ATM respectively. Then they turn right and drive for another 70 meters and reached PVR cinemas and Phoenix mall respectively. Then they take 90 degree anti clock wise direction for 40 meters and then they turn right. After driving for 30 meters Dinu reaches at CTS and Tinu reached at TCS. (Set 1 Q. 1)
 
Initially, if Dinu was 270 meters to the east of Tinu, then what is the shortest distance and direction of TCS with respect to CTS?
» Explain it
A


From above figure, we get,



(120)2 + (35)2 = 14400 + 1225

14400 + 1225  = 15625

15625 = 125m [TCS to mid point]

Similarly we get 

125 m from CTS to mid point.
 
Total Distance = 125 m + 125 m = 250 m
 
TCS is north-west direction with respect to CTS.

Hence, option A is correct.
 
2
Two friends Tinu and Dinu are driving car in Paris. Tinu is facing north and Dinu is facing south. They drive their cars for 80 meters in the direction they are facing and reached HDFC Bank and CUB ATM respectively. Then they turn right and drive for another 70 meters and reached PVR cinemas and Phoenix mall respectively. Then they take 90 degree anti clock wise direction for 40 meters and then they turn right. After driving for 30 meters Dinu reaches at CTS and Tinu reached at TCS. (Set 1 Q. 2)
 
Initially, if Dinu was 200 meters to the east of Tinu, then what is the shortest distance and direction of TCS with respect to CTS?
 
» Explain it
C
From fig, TCS is north direction with respect to CTS.
 
Total Distance = 120 m + 120 m = 240 m
 
 
Hence, option C is correct.
 
3
Two friends Tinu and Dinu are driving car in Paris. Tinu is facing north and Dinu is facing south. They drive their cars for 80 meters in the direction they are facing and reached HDFC Bank and CUB ATM respectively. Then they turn right and drive for another 70 meters and reached PVR cinemas and Phoenix mall respectively. Then they take 90 degree anti clock wise direction for 40 meters and then they turn right. After driving for 30 meters Dinu reaches at CTS and Tinu reached at TCS. (Set 1 Q. 3)
 
Initially, if Dinu was 130 meters to the east of Tinu, then what is the shortest distance and direction of TCS with respect to CTS?
» Explain it
B
 

From above figure, we get



(120)2 + (35)2 = 14400 + 1225

14400 + 1225  = 15625

15625 = 125m [TCS to mid point]

Similarly we get 

 From CTS to midpoint is 125 m.

Total Distance = 125 m + 125 m = 250 m

TCS is north-east direction with respect to CTS.
 
Hence, option B is correct.

4
A is north-east of B. The shortest distance between A and B is 10 meter. C is south of A and east of B. The distance between B and C is twice the distance between A and E. The distance between A and C is twice the distance E and H. E is north of A. H is east of E. H is 3meter south of G. The shortest distance between G and E is 5 meter. (Set 2 Q.1)

What is the shortest distance between point A and H?
» Explain it
C
The following common explanation, we get “5 meter”. 

From, figure, (AH)2    =    (EH)2 + (AE)2 
                      (AH)2   =   (4)2 + (3)2 
                    16 + 9    =   (AH)2 
                          25    =   (AH)2 
                          AH   =   5 meter
 
Hence, option C is correct.

Common Explanation:
 
References
 
A is north-east of B. The shortest distance between A and B is 10 meter. C is south of A and east of B. 
References
 
E is north of A. H is east of E. H is 3meter south of G. The shortest distance between G and E is 5 meter.
[Figure 2]

From, figure (2),

(EG)= (EH)+ (HG)
(5)= (EH)+ (3)2    ⇒    2 = (EH)+ 9
25 – 9 = (EH)2           ⇒    16 = (EH)2

Therefore,

distance [E to H] = 4 meter
References

The distance between B and C is twice the distance between A and E.

The distance between A and C is twice the distance E and H.

We know,
 
Distance between E and H = 4 meter
 
Given,

Distance [A to C] = 2 { Distance [E to H] }
Distance [A to C] = 2 × 4 = 8 meter
Thus we get fig 1 as,

[Figure 3] 

From, figure (3), 

(BA)2 = (BC)+ (AC)2
(10)2 = (BC)2 + (B)2
100 = (BC)2 + 64
100 – 64 = (BC)2
36 = (BC)2

Therefore,

distance [B to C] = 6 meter
   
 
 
We know,

Distance between B and C = 6 meter
 
Given,

Distance [B to C]= 2 {Distance [E to A]}

6 meter = 2 {Distance [E to A]}
 
Distance [E to A] =6 meter/2 =3 meter
 
 


Combining all figures, we get


 
5
A is north-east of B. The shortest distance between A and B is 10 meter. C is south of A and east of B. The distance between B and C is twice the distance between A and E. The distance between A and C is twice the distance E and H. E is north of A. H is east of E. H is 3meter south of G. The shortest distance between G and E is 5 meter.[Set 2 Q. 2] 

What is the sum of the distance between A and C & E and H?
» Explain it
C
The following common explanation, we get “12 meter”.
 
From figure, Distance [A to C] = 8 meter
 
Distance [E to H] = 4 meter.
 
Sum = 8 + 4 =12 meter
 
Hence, option C is correct.

Common Explanation:
 
References
 
A is north-east of B. The shortest distance between A and B is 10 meter. C is south of A and east of B. 
  
References
 
E is north of A. H is east of E. H is 3meter south of G. The shortest distance between G and E is 5 meter.

 
[Figure 2]

 From, figure (2),

(EG)= (EH)+ (HG)2

(5)= (EH)+ (3)

2 = (EH)+ 9

25 – 9 = (EH)2

16 = (EH)2

Therefore,

distance [E to H] = 4 meter
 

References

The distance between B and C is twice the distance between A and E.

The distance between A and C is twice the distance E and H.

 
We know,
 
Distance between E and H = 4 meter
 
Given,

Distance [A to C]= 2 {Distance [E to H]}

Distance [A to C]=2*4 =8 meter
 
Thus we get fig 1 as,
 

[Figure 3]

 
 From, figure (3), 

(BA)2 =
(BC)+ (AC)2

(10)2 = (BC)2 + (B)2

100 = (BC)2 + 64

100 – 64 = (BC)2

36 = (BC)2

Therefore,

distance [B to C] = 6 meter

   
 
 
We know,

Distance between B and C = 6 meter
 
Given,

Distance [B to C]= 2 {Distance [E to A]}

6 meter = 2 {Distance [E to A]}
 
Distance [E to A] =6 meter/2 =3 meter
 
 


Combining all figures, we get
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How to Prepare Direction Sense related questions for Bank Po exams

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